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 "worksheets": [
  {
   "cells": [
    {
     "cell_type": "heading",
     "level": 1,
     "metadata": {},
     "source": [
      "Chapter13-thermodynamic relations"
     ]
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example2-pg284"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "#calculate entropy wrt pressures and volume wrt temerature\n",
      "##initialisation of variables\n",
      "S1= 6.539 ##kJ/kg K\n",
      "S2= 6.7664 ##kJ/kg K\n",
      "v1= 0.10976 ##m^3\n",
      "v2= 0.08700 ##m^3\n",
      "P= 3. ##Mpa\n",
      "P1= 2. ##Mpa\n",
      "T= 350. ##K\n",
      "T1= 250. ##K\n",
      "S3= 3.1741 ##kJ/kg K\n",
      "S4= 3.2071 ##kJ/kg K\n",
      "P2= 30. ##Mpa\n",
      "P3= 20. ##Mpa\n",
      "v3= 0.0014217 ##m^3\n",
      "v4= 0.0012860 ##m^3\n",
      "T2= 320. ##K\n",
      "T3= 280. ##K\n",
      "##CALCULATIONS\n",
      "r= (S1-S2)/(P*10*10*10-P1*10*10*10)\n",
      "r1= (v1-v2)/(T-T1)\n",
      "R= (S3-S4)/(P2*10*10*10-P3*10*10*10)\n",
      "R1= (v3-v4)/(T2-T3)\n",
      "##RESULTS\n",
      "print'%s %.7f %s'% ('entropy wrt pressre=',r,'kJ/kg K kpa')\n",
      "print'%s %.e %s'% ('entropy wrt pressre=',R,'kJ/kg K kpa')\n",
      "print'%s %.7f %s'%  ('volume wrt temperature=',r1,'m^3/kg K ')\n",
      "print'%s %.2e %s'% ('volume wrt temperature=',R1,'m^3/kg K ')\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "entropy wrt pressre= -0.0002274 kJ/kg K kpa\n",
        "entropy wrt pressre= -3e-06 kJ/kg K kpa\n",
        "volume wrt temperature= 0.0002276 m^3/kg K \n",
        "volume wrt temperature= 3.39e-06 m^3/kg K \n"
       ]
      }
     ],
     "prompt_number": 6
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example3-pg286"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "#saturation pressure\n",
      "##initialisation of variables\n",
      "hfg= 2406.7 ##kJ/kg\n",
      "Psat40= 7.384 ##kPa\n",
      "R= 8.314 ##J/mol K\n",
      "T= 40. ##C\n",
      "T1= 50. ##C\n",
      "M= 18.##kg\n",
      "##CALCULATIONS\n",
      "Psat50= Psat40*math.e**((hfg*M/R)*((1/(273.15+T))-(1/(273.15+T1))))\n",
      "##RESULTS\n",
      "print'%s %.3f %s' %('Saturation pressure=',Psat50,'kPa')\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Saturation pressure= 12.357 kPa\n"
       ]
      }
     ],
     "prompt_number": 2
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example4-pg287"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "#calcualte lowest temprature\n",
      "##initialisation of variables\n",
      "W= 800. ##N\n",
      "A= 0.4 ##cm^2\n",
      "p= 0.611 ##Mpa\n",
      "P1= 0.1 ##Mpa\n",
      "T= 0.01 ##C\n",
      "vs= 0.0010908 ##m^3/kg\n",
      "hs= -333.40 ##kJ/kg\n",
      "vf= 0.0010002 ##m^3/kg\n",
      "hf= 0 ##kJ/kg\n",
      "vg= 206.14 ##m^3/kg\n",
      "hg= 2501.4 ##kJ/kg\n",
      "##CALCULATIONS\n",
      "P2= P1+(W/A)*math.pow(10,(4-6))\n",
      "dT= (273.15++T)*(vf-vs)*(P2*10*10*10-p)/(0-hs)\n",
      "Tmin= dT+T\n",
      "##RESULTS\n",
      "print'%s %.2f %s'% ('lowest temperature=',Tmin,'C')\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "lowest temperature= -1.48 C\n"
       ]
      }
     ],
     "prompt_number": 3
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example7-pg292"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "import math\n",
      "#calculate volume exapansion coefficent and isothermal compressibilitiy and isotherma modulus of elasticity\n",
      "##initialisation of variables\n",
      "vi= 0.0009992 ##m^3\n",
      "T= 60. ##C\n",
      "T1= 20. ##C\n",
      "T2= 40. ##C\n",
      "vi1= 0.0010042 ##m^3\n",
      "vi2= 0.0009886 ##m^3\n",
      "v= 0.000951 ##m^3\n",
      "v1= 0.0009992 ##m^3\n",
      "v2= 0.0009956 ##m^3\n",
      "##CALCULATIONS\n",
      "B= (vi1-vi2)/(vi*(T-T1))\n",
      "Kt= (v1-v2)/(v*(T2-T1))\n",
      "Et= 1/Kt\n",
      "##RESULTS\n",
      "print'%s %.2e %s'% ('volume exapansion coefficient=',B,'L/s')\n",
      "print'%s %.3e %s'% ('isothermal compressibility=',Kt,'Mpa')\n",
      "print'%s %.f %s'% ('isothermal modulus of elasticity=',Et,'Mpa')\n",
      "\n",
      "\n",
      "##ANSWER FOR Et GIVEN IN THE TEXTBOOK IS WRONG\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "volume exapansion coefficient= 3.90e-04 L/s\n",
        "isothermal compressibility= 1.893e-04 Mpa\n",
        "isothermal modulus of elasticity= 5283 Mpa\n"
       ]
      }
     ],
     "prompt_number": 4
    }
   ],
   "metadata": {}
  }
 ]
}