{
 "metadata": {
  "name": ""
 },
 "nbformat": 3,
 "nbformat_minor": 0,
 "worksheets": [
  {
   "cells": [
    {
     "cell_type": "heading",
     "level": 1,
     "metadata": {},
     "source": [
      "Chapter 4:Defining Thermodynamic State:The State Postulate"
     ]
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 4.1,Page no:51"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "\n",
      "M=2.5 \t\t\t\t#mass of the substance[Kg]\n",
      "x=0.6 \t\t\t\t#mass fraction for vapour phase \n",
      "P=7 \t\t\t\t#pressure [atm]\n",
      "T=438 \t\t\t\t#temperature[K]\n",
      "\n",
      "Ml=(1-x)*M \t\t\t#mass fraction of liquid phase[Kg]\n",
      "Mg=x*M \t\t\t\t#mass fraction of vapour phase[Kg]\n",
      "print\"M(liquid phase)=\",Ml,\"Kg\\nM(vapour phase)=\",Mg,\"Kg\""
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "M(liquid phase)= 1.0 Kg\n",
        "M(vapour phase)= 1.5 Kg\n"
       ]
      }
     ],
     "prompt_number": 1
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 4.2,Page no:51"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "\n",
      "Vl=0.0177 \t\t\t#specific volume of saturated liquid[m3/Kg]\n",
      "Vg=4.43 \t\t\t#specific volume of saturated vapour[m3/Kg]\n",
      "P=7 \t\t\t\t#pressure[atm]\n",
      "T=438 \t\t\t\t#temperature[K]\n",
      "x=0.6 \t\t\t\t#fraction of vapour phase\n",
      "M=2.5 \t\t\t\t#mass of the substance[Kg]\n",
      "\n",
      "V=((1-x)*Vl+x*Vg)*M \t\t#total volume occupied [m3]\n",
      "print\"Total volume occupied =\",round(V,2),\"m^3\"\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Total volume occupied = 6.66 m^3\n"
       ]
      }
     ],
     "prompt_number": 2
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 4.3,Page no:51"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "\n",
      "M=2.5 \t\t\t\t#mass of a substance[Kg]\n",
      "x=0.6 \t\t\t\t#fraction of vapour phase \n",
      "Ug=1105.0 \t\t\t#specific internal energy of saturated vapour[J/Kg]\n",
      "Ul=298.0 \t\t\t\t#specific internal energy of saturated liquid[J/Kg] \n",
      "U=M*((1-x)*Ul+x*Ug) \n",
      "print\"The total internal energy of the mixture =\",U,\"J\"\n",
      "print\"\\nNOTE:In textbook,it is wrongly calculated as 1950 J\"\n",
      " "
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "The total internal energy of the mixture = 1955.5 J\n",
        "\n",
        "NOTE:In textbook,it is wrongly calculated as 1950 J\n"
       ]
      }
     ],
     "prompt_number": 3
    }
   ],
   "metadata": {}
  }
 ]
}