{ "metadata": { "name": "", "signature": "sha256:ff90ca36306843dda7b5d7f4afff0c2bcd17928b8d2090ef8ae2b28da2c7c555" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 3: Importance of State Functions: Internal Energy and Enthalpy" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example Problem 3.2, Page Number 45" ] }, { "cell_type": "code", "collapsed": false, "input": [ "from math import log`\n", "#Variable Declaration\n", "betaOH = 11.2e-4 #Thermal exapnasion coefficient of ethanol, \u00b0C\n", "betagl = 2.00e-5 #Thermal exapnasion coefficient of glass, \u00b0C\n", "kOH = 11.0e-5 #Isothermal compressibility of ethanol, /bar\n", "dT = 10.0 #Increase in Temperature, \u00b0C\n", "\n", "#Calcualtions\n", "vfbyvi = (1+ betagl*dT)\n", "dP = betaOH*dT/kOH-(1./kOH)*log(vfbyvi)\n", "\n", "#Results\n", "print 'Pressure increase in capillary %4.1f bar'%dP" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Pressure increase in capillary 100.0\n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example Problem 3.4, Page Number 49" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Variable Declaration\n", "cpsubysy = 1000 #Specific heat ration of surrounding and system\n", "Tpreci = 0.006 #Precision in Temperature measurement, \u00b0C\n", "\n", "#Calcualtions\n", "dtgas = -cpsubysy*(-Tpreci)\n", "\n", "#Results\n", "print 'Minimum detectable temperature change of gas +-%4.1f \u00b0C'%dtgas" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Minimum detectable temperature change of gas +- 6.0 \u00b0C\n" ] } ], "prompt_number": 5 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example Problem 3.6, Page Number 50" ] }, { "cell_type": "code", "collapsed": false, "input": [ "from sympy import *\n", "\n", "#Variable Declaration\n", "n = 1.0 #number of mole of N2, mol \n", "Ti = 200.0 #Intial Temperature, K\n", "Pi = 5.00 #Initial pressure, bar\n", "Tf = 400.0 #Intial Temperature, K\n", "Pf = 20.0 #Initial pressure, bar\n", "a = 0.137 #van der Waals constant a, Pa.m3/(mol2)\n", "b = 3.87e-5 #van der Waals constant b, m3/(mol)\n", "A, B, C, D = 22.5, -1.187e-2,2.3968e-5, -1.0176e-8\n", " #Constants in Cvm equation J, K and mol\n", "vi = 3.28e-3 #initial volume, m3/mol\n", "vf = 7.88e-3 #Final volume, m3/mol\n", "\n", "#Calculations\n", "T = symbols('T')\n", "dUT = n**2*a*(1./vi-1./vf)\n", "dUV = integrate( A + B*T + C*T**2 + D*T**3, (T,Ti,Tf))\n", "\n", "#Results\n", "print 'dUT = %4.1f J: This is wrongly reported in book'%dUT\n", "print 'dUV = %4.1f J'%dUV" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "dUT = 24.4 J: This is wrongly reported in book\n", "dUV = 4174.1 J\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example Problem 3.7, Page Number 53" ] }, { "cell_type": "code", "collapsed": false, "input": [ "from sympy import *\n", "\n", "#Variable Declaration\n", "m = 143.0 #Mass of graphite, g \n", "Ti = 300.0 #Intial Temperature, K\n", "Tf = 600.0 #Intial Temperature, K\n", "A, B, C, D, E = -12.19,0.1126,-1.947e-4,1.919e-7,-7.8e-11\n", " #Constants in Cvm equation J, K and mol\n", "M = 12.01\n", "\n", "#Calculations\n", "\n", "T = symbols('T')\n", "dH = (m/M)*integrate( A + B*T + C*T**2 + D*T**3 + E*T**4, (T,Ti,Tf))\n", "expr = A + B*T + C*T**2 + D*T**3 + E*T**4\n", "cpm = expr.subs(T,300.)\n", "qp = (m/M)*cpm*(Tf-Ti)\n", "err = abs(dH-qp)/dH\n", "#Results\n", "print 'dH = %6.1f kJ'%(dH/1000)\n", "print 'qp = %6.1f kJ'%(qp/1000)\n", "print 'Error in calculations %4.1f'%(err*100)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "dH = 46.8 kJ\n", "qp = 30.8 kJ\n", "Error in calculations 34.3\n" ] } ], "prompt_number": 19 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example Problem 3.9, Page Number 56" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Variable Declaration\n", "m = 124.0 #Mass of liquid methanol, g\n", "Pi = 1.0 #Initial Pressure, bar\n", "Ti = 298.0 #Intial Temperature, K\n", "Pf = 2.5 #Final Pressure, bar\n", "Tf = 425.0 #Intial Temperature, K\n", "rho = 0.791 #Density, g/cc\n", "Cpm = 81.1 #Specifi heat, J/(K.mol)\n", "M = 32.04\n", "\n", "#Calculations\n", "n = m/M\n", "DH = n*Cpm*(Tf-Ti)+ m*(Pf-Pi)*1e-6/rho\n", "\n", "#Results\n", "print 'Enthalpy change for change in state of methanol is %4.1f kJ'%(DH/1000)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Enthalpy change for change in state of methanol is 39.9 kJ\n" ] } ], "prompt_number": 24 } ], "metadata": {} } ] }