{ "metadata": { "name": "", "signature": "sha256:691a96475cd536c4ffab20fb4eb718e811176f01d8c2ef3e8cc4a80d2f0c8355" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter9-Dilute Solutions" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex1-pg258" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "\n", "p1= 17.535 ##mm\n", "p2= 17.226 ##mm\n", "M= 100. ##gms\n", "m1= 18.02 ##gms\n", "m2= 18.04 ##gms\n", "##CALCULATIONS\n", "M= (-1.+(p1/(p1-p2)))*m1*m2/M\n", "##RESULTS\n", "print'%s %.2f %s'% ('Molecular weight of mannitol = ',M,' gms')\n", "print'%s %.2f %s'% ('\\n Correct Molecular weight of mannitol = ',M+1,' gms')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Molecular weight of mannitol = 181.22 gms\n", "\n", " Correct Molecular weight of mannitol = 182.22 gms\n" ] } ], "prompt_number": 6 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex2-pg262" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "\n", "dT= 0.170 ##C\n", "M2= 60.06 ##gms\n", "w1= 22.5 ##gms\n", "w2= 0.45 ##gms\n", "R= 1.987 ##cal\n", "T= 100. ##C\n", "lv= 539.9 ##cal g^-1\n", "##CALCULATIONS\n", "Kb= dT*M2*w1/(1000.*w2)\n", "Kb1= R*(273.2+T)**2/(lv*1000.)\n", "##RESULTS\n", "print'%s %.2f %s'% ('Eleveation constant of water = ',Kb,'')\n", "print'%s %.2f %s'% ('\\n Eleveation constant of water = ',Kb1,'')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Eleveation constant of water = 0.51 \n", "\n", " Eleveation constant of water = 0.51 \n" ] } ], "prompt_number": 5 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex3-pg265" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "\n", "Kf= 5.12\n", "m= 0.911 ##gms\n", "m1= 50. ##gms\n", "dT= 0.603 ##deg\n", "##CALCULATIONS\n", "M2= Kf*1000.*m/(m1*dT)\n", "##RESULTS\n", "print'%s %.2f %s'% ('Molecular weight of carbon tetra chloride = ',M2,' gms')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Molecular weight of carbon tetra chloride = 154.70 gms\n" ] } ], "prompt_number": 4 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex4-pg271" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "\n", "m= 4. ##gms\n", "p= 6.4*10**-4 ##atm\n", "T= 27. ##C\n", "R= 0.082 ##lit atm deg^-1 mole^-1\n", "##CALCULATIONS\n", "M= R*(273.+T)*m/p\n", "##RESULTS\n", "print'%s %.2e %s'% ('Molecular weight of polymer = ',M,' gms')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Molecular weight of polymer = 1.54e+05 gms\n" ] } ], "prompt_number": 3 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex5-pg277" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "\n", "v1= 18.10 ##cc\n", "T= 100. ##C\n", "p= 2.47 ##atm\n", "L= 539.9 ##cal mole^-1 gm^-1\n", "m= 18.02 ##gm\n", "T1= 30. ##C\n", "##CALCULATIONS\n", "dT= v1*(273.2+T)**2*p*1.013*10**6/(L*m*4.184*10**7*(273.2+T1))\n", "##RESULTS\n", "print'%s %.2f %s'% ('Elevation of boiling point = ',dT,' degrees')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Elevation of boiling point = 0.05 degrees\n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex6-pg280" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "\n", "dt= 0.0265 ##deg\n", "c= 5.*10**-3 ##M\n", "kf= 1.86 ##deg\n", "##CALCULATIONS\n", "i= dt/(c*kf)\n", "##RESULTS\n", "print'%s %.2f %s'% ('i of the solution = ',i,'')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "i of the solution = 2.85 \n" ] } ], "prompt_number": 1 } ], "metadata": {} } ] }