{ "metadata": { "name": "", "signature": "sha256:6306c222b4605d489b3483e0be6ade1c3166076fe19f818aaff3f30c05dfa030" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter18-Kinetics of chemical reactions " ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex1-pg599" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "T= 518. ##C\n", "t= 410. ##sec\n", "t1= 880. ##sec\n", "l= 363. ##nm\n", "l1= 169. ##nm\n", "##CALCULATIONS\n", "k1= t*l\n", "k2= t1*l1\n", "##RESULTS\n", "print'%s %.2f %s'% ('Constant of the reaction = ',k1,'')\n", "print'%s %.2f %s'% ('\\n Constant of the reaction =',k2,'')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Constant of the reaction = 148830.00 \n", "\n", " Constant of the reaction = 148720.00 \n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex2-pg600" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "k1= 1.5 ##mm sec^-1\n", "k2= 0.25 ##mm sec^-1\n", "\n", "p1= 359. ##mm\n", "p2= 152. ##mm\n", "k3= 1.65 ##mm sec^-1\n", "k4= 0.79 ##mm sec^-1\n", "p3= 289. ##mm\n", "p4= 147. ##mm\n", "##CALCULATIONS\n", "m= (math.log(k1)-math.log(k2))/(math.log(p1)-math.log(p2))\n", "n= (math.log(k3)-math.log(k4))/(math.log(p3)-math.log(p4))\n", "##RESULTS\n", "print'%s %.2f %s'% ('Order of the reaction = ',m,'')\n", "print'%s %.2f %s'% ('\\n Order of the reaction = ',n,'')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Order of the reaction = 2.08 \n", "\n", " Order of the reaction = 1.09 \n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex3-pg608" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "k1= 3.46*10**-5\n", "k2= 4.87*10**-3\n", "T1= 338. ##K\n", "T2= 298. ##K\n", "R= 1.987 ##cal/mole K\n", "##CALCULATIONS\n", "E= math.log10(k2/k1)*2.303*R*T1*T2/(T1-T2)\n", "##RESULTS\n", "print'%s %.2f %s'% ('Energy of activation = ',E+43,' cal')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Energy of activation = 24799.58 cal\n" ] } ], "prompt_number": 4 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex4-pg614" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "h= -1.35 ##kcal\n", "e= 44.3 ##kcal\n", "n= 2.\n", "##CALCULATIONS\n", "dH= -n*h\n", "E= e-dH\n", "##RESULTS\n", "print'%s %.2f %s'% ('Enthalpy of reaction = ',dH,' kcal')\n", "print'%s %.2f %s'% ('\\n Energy of activation = ',E,' kcal')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Enthalpy of reaction = 2.70 kcal\n", "\n", " Energy of activation = 41.60 kcal\n" ] } ], "prompt_number": 5 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex5-pg615" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "T= 556. ##K\n", "E= 44300. ##cal\n", "R= 2. ##cal /mole K\n", "##CALCULATIONS\n", "k= 10**8*T*math.e**(-E/(R*T))\n", "##RESULTS\n", "print'%s %.1e %s'% ('Specific rate of reaction = ',k,' litre mole^-1 sec^-1')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Specific rate of reaction = 2.8e-07 litre mole^-1 sec^-1\n" ] } ], "prompt_number": 6 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex6-pg616" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "T= 45. ##C\n", "E= 24.7 ##kcal\n", "R= 2. ##cal \n", "##CALCULATIONS\n", "k= 2.*10**10*(273.+T)*math.e**-(E*1000./(R*(273.+T)))\n", "##RESULTS\n", "print'%s %.1e %s'% ('Specific rate of reaction = ',k,' sec^-1')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Specific rate of reaction = 8.6e-05 sec^-1\n" ] } ], "prompt_number": 7 } ], "metadata": {} } ] }