{ "metadata": { "name": "", "signature": "sha256:bc483af2aab74a69c5c0f5f640bdbb7d93b0bf6485c56961f1dfe2ffba52540b" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter15-Equilibria in electrolytes" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex1-pg486" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "c1= 0.1 ##M\n", "c2= 0.2 ##M\n", "c3= 0.4 ##M\n", "n1= 1.\n", "n2= 2.\n", "##CALCULATIONS\n", "u1= 0.5*(c1*n1**2+c1*n1**2)\n", "u2= 0.5*(c3*n1**2+c2*n2**2)\n", "u3= 0.5*((c3+c1)*n1**2+c1*n1**2+c2*n2**2)\n", "##RESULTS\n", "print'%s %.2f %s'% ('Ionic strength = ',u1,'')\n", "print'%s %.2f %s'% ('\\n Ionic strength = ',u2,'')\n", "print'%s %.2f %s'% ('\\n Ionic strength = ',u3,'')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Ionic strength = 0.10 \n", "\n", " Ionic strength = 0.60 \n", "\n", " Ionic strength = 0.70 \n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex2-pg488" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "c1= 0.01 ##M\n", "c2= 0.001 ##M\n", "n= 2. ##moles\n", "k= -0.509\n", "n1= 1. ##moles\n", "##CALCULATIONS\n", "f1= 10**(k*math.sqrt(c1))\n", "f2= 10**(k*n*math.sqrt((c2*(n+n1))))\n", "##RESULTS\n", "print'%s %.2f %s'% ('activity coefficient = ',f1,'')\n", "print'%s %.2f %s'% ('\\n activity coefficient = ',f2,'')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "activity coefficient = 0.89 \n", "\n", " activity coefficient = 0.88 \n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex3-pg491" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "a= 6.4*10**-6 ##g ion per lit\n", "a1= 0.05\n", "n= 2.\n", "##CALCULATIONS\n", "Ksp= a**2*a1\n", "s= (Ksp/n**2)**(1./3.)\n", "##RESULTS\n", "print'%s %.2e %s'% ('Ks = ',Ksp,'')\n", "print'%s %.2e %s'% ('\\n solubility of Ag2CrO4 = ',s,' mole per litre')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Ks = 2.05e-12 \n", "\n", " solubility of Ag2CrO4 = 8.00e-05 mole per litre\n" ] } ], "prompt_number": 3 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex4-pg494" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "s1= -0.0059 ##mole per litre\n", "x1= 0.0118 ##mole per lit\n", "x2= 0.0269 ##mole per litre\n", "##CALCULATIONS\n", "S= s1+math.sqrt(0.25*x1**2+x2**2)\n", "##RESULTS\n", "print'%s %.4f %s'% ('Solubility = ',S,' mole per litre')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Solubility = 0.0216 mole per litre\n" ] } ], "prompt_number": 4 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex5-pg506" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "Ka= 1.752*10**-5\n", "c= 0.1 ##M\n", "##CALCULATIONS\n", "ch= math.sqrt(Ka*c)\n", "ch1= -0.5*Ka+math.sqrt(Ka*c)\n", "r= ch1/c\n", "##RESULTS\n", "print'%s %.2e %s'% ('CH+ = ',ch,' g ion per litre')\n", "print'%s %.3e %s'% ('\\n CH+ = ',ch1,' g ion per litre')\n", "print'%s %.2e %s'% ('\\n degree of dissociation = ',r,'')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "CH+ = 1.32e-03 g ion per litre\n", "\n", " CH+ = 1.315e-03 g ion per litre\n", "\n", " degree of dissociation = 1.31e-02 \n" ] } ], "prompt_number": 5 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex6-pg508" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "c1= 0.1 ##M\n", "cs= 0.05 ##M\n", "Ka= 1.75*10**-5\n", "##CALCULATIONS\n", "ch= Ka*c1/cs\n", "##RESULTS\n", "print'%s %.1e %s'% ('CH+ = ',ch,' g ion per litre')\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "CH+ = 3.5e-05 g ion per litre\n" ] } ], "prompt_number": 6 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex7-pg511" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "ch= 5.46*10**-5 ##g ion per litre\n", "ph= 8.752\n", "##CALCULATIONS\n", "pH= -math.log10(ch)\n", "ch1= 10**(-ph)\n", "##RESULTS\n", "print'%s %.2f %s'% ('pH = ',pH,'') \n", "print'%s %.2e %s'% ('\\n Hydrogen ion concentration = ',ch1,' g ion per litre') \n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "pH = 4.26 \n", "\n", " Hydrogen ion concentration = 1.77e-09 g ion per litre\n" ] } ], "prompt_number": 7 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex8-pg512" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "##Intitalisation of variables\n", "pt= 14.\n", "ph= 4.75\n", "##CALCULATIONS\n", "coh= 10**(-(pt-ph))\n", "##RESULTS\n", "print'%s %.2e %s'% ('COH- = ',coh,' g ion per litre') \n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "COH- = 5.62e-10 g ion per litre\n" ] } ], "prompt_number": 8 } ], "metadata": {} } ] }