{ "metadata": { "name": "chapter 8.ipynb" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter No.8:Thin And Thick Cyclinders And Spheres" ] }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.1,Page No.322" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "\n", "#Initilization of Variables\n", "\n", "L=3000 #mm #Length\n", "d1=1000 #mm #Internal diameter\n", "t=15 #mm #Thickness\n", "P=1.5 #N/mm**2 #Fluid Pressure\n", "E=2*10**5 #n/mm**2 #Modulus of elasticity\n", "mu=0.3 #Poissoin's ratio\n", "\n", "#Calculations\n", "\n", "#Hoop stress\n", "f1=P*d1*(2*t)**-1 #N/mm**2\n", "\n", "#Longitudinal Stress\n", "f2=P*d1*(4*t)**-1 #N/mm**2\n", "\n", "#Max shear stress\n", "q_max=(f1-f2)*2**-1 #N/mm**2\n", "\n", "#Diametrical Strain\n", "#Let e1=dell_d*d**-1 .....................(1)\n", "e1=(f1-mu*f2)*E**-1 \n", "\n", "#Sub values in equation 1 and further simplifying we get\n", "dell_d=e1*d1 #mm\n", "\n", "#Longitudinal strain\n", "#e2=dell_L*L**-1 ......................(2)\n", "e2=(f2-mu*f1)*E**-1 \n", "\n", "#Sub values in equation 2 and further simplifying we get\n", "dell_L=e2*L #mm\n", "\n", "#Change in Volume \n", "#Let Z=dell_V*V**-1 ................(3)\n", "Z=2*e1+e2\n", "\n", "#Sub values in equation 3 and further simplifying we get\n", "dell_V=Z*pi*4**-1*d1**2*L\n", "\n", "#Result\n", "print\"Max Intensity of shear stress\",round(q_max,2),\"N/mm**2\"\n", "print\"Change in the Dimensions of the shell is:dell_d\",round(dell_d,2),\"mm\"\n", "print\" :dell_L\",round(dell_L,2),\"mm\"\n", "print\" :dell_V\",round(dell_V,2),\"mm**3\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Max Intensity of shear stress 12.5 N/mm**2\n", "Change in the Dimensions of the shell is:dell_d 0.21 mm\n", " :dell_L 0.15 mm\n", " :dell_V 1119192.38 mm**3\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.2,Page No.323" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "\n", "#Initilization of Variables\n", "\n", "L=2000 #mm #Length\n", "d=200 #mm # diameter\n", "t=10 #mm #Thickness\n", "dell_V=25000 #mm**3 #Additional volume\n", "E=2*10**5 #n/mm**2 #Modulus of elasticity\n", "mu=0.3 #Poissoin's ratio\n", "\n", "#Calculations\n", "\n", "#Let p be the pressure developed\n", "\n", "#Circumferential Stress\n", "\n", "#f1=p*d*(2*t)**-1 #N/mm**2\n", "#After sub values and further simplifying\n", "#f1=10*p\n", "\n", "#f1=p*d*(4*t)**-1 #N/mm**2\n", "#After sub values and further simplifying\n", "#f1=5*p\n", "\n", "#Diameterical strain = Circumferential stress\n", "#Let X=dell_d*d**-1 ................................(1)\n", "#X=e1=(f1-mu*f2)*E**-1 \n", "#After sub values and further simplifying\n", "#e1=8.5*p*E**-1\n", "\n", "#Longitudinal strain\n", "#Let Y=dell_L*L**-1 ......................................(2)\n", "#Y=e2=(f2-mu*f1)*E**-1 \n", "#After sub values and further simplifying\n", "#e2=2*p*E**-1\n", "\n", "#Volumetric strain\n", "#Let X=dell_V*V**-1 \n", "#X=2*e1+e2\n", "#After sub values and further simplifying\n", "#X=19*p*E**-1\n", "#After further simplifying we get\n", "p=dell_V*(pi*4**-1*d**2*L)**-1*E*19**-1 #N/mm**2\n", "\n", "#Hoop Stress\n", "f1=p*d*(2*t)**-1\n", "\n", "X=e1=8.5*p*E**-1\n", "#Sub value of X in equation 1 we get\n", "dell_d=8.5*p*E**-1*d\n", "\n", "Y=e2=2*p*E**-1\n", "#Sub value of Y in equation 2 we get\n", "dell_L=2*p*E**-1*L\n", "\n", "#Result\n", "print\"Pressure Developed is\",round(p,2),\"N/mm**2\"\n", "print\"Hoop stress Developed is\",round(f1,2),\"N/mm**2\"\n", "print\"Change in diameter is\",round(dell_d,2),\"mm\"\n", "print\"Change in Length is\",round(dell_L,2),\"mm\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Pressure Developed is 4.19 N/mm**2\n", "Hoop stress Developed is 41.88 N/mm**2\n", "Change in diameter is 0.04 mm\n", "Change in Length is 0.08 mm\n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.3,Page No.324" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "\n", "#Initilization of Variables\n", "\n", "d=750 #mm #Diameter of water supply pipes\n", "h=50*10**3 #mm #Water head\n", "sigma=20 #N/mm**2 #Permissible stress\n", "rho=9810*10**-9 #N/mm**3\n", "\n", "#Calculations\n", "\n", "#Pressure of water\n", "P=rho*h #N/mm**2\n", "\n", "#Stress\n", "#sigma=p*d*(2*t)**-1\n", "#After further simplifying\n", "t=P*d*(2*sigma)**-1 #mm \n", "\n", "#Result\n", "print\"Thickness of seamless pipe is\",round(t,3),\"mm\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Thickness of seamless pipe is 9.197 mm\n" ] } ], "prompt_number": 3 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.4,Page No.326" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "\n", "#Initilization of Variables\n", "\n", "d=2500 #mm #Diameter of riveted boiler\n", "P=1 #N/mm**2 #Pressure\n", "rho1=0.7 #Percent efficiency\n", "rho2=0.4 #Circumferential joints\n", "sigma=150 #N/mm**2 #Permissible stress\n", "\n", "#Calculations\n", "\n", "#Equating Bursting force to longitudinal joint strength ,we get\n", "#p*d*L=rho1*2*t*L*sigma\n", "#After rearranging and further simplifying we get\n", "t=P*d*(2*sigma*rho1)**-1 #mm\n", "\n", "#Considering Longitudinal force\n", "#pi*d**2*4**-1*P=rho2*pi*d*t*sigma\n", "#After rearranging and further simplifying we get\n", "t2=P*d*(4*sigma*rho2)**-1\n", "\n", "#Result\n", "print\"Thickness of plate required is\",round(t,2),\"mm\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Thickness of plate required is 11.9 mm\n" ] } ], "prompt_number": 4 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.5,Page No.326" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "\n", "#Initilization of Variables\n", "\n", "#Boiler Dimensions\n", "t=16 #mm #Thickness\n", "p=2 #N/mm**2 #internal pressure\n", "f=150 #N/mm**2 #Permissible stress\n", "rho1=0.75 #Longitudinal joints\n", "rho2=0.45 #circumferential joints\n", "\n", "#Calculations\n", "\n", "#Equating Bursting force to longitudinal joint strength ,we get\n", "d1=rho1*2*t*f*p**-1 #mm\n", "\n", "#Considering circumferential strength \n", "d2=4*rho2*t*f*p**-1 #mm\n", "\n", "#Result\n", "print\"Largest diameter of Boiler is\",round(d1,2),\"mm\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Largest diameter of Boiler is 1800.0 mm\n" ] } ], "prompt_number": 5 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.6,Page No.329" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "\n", "#Initilization of Variables\n", "\n", "d=250 #mm #Diameter iron pipe\n", "t=10 #mm #Thickness\n", "d2=6 #mm #Diameter of steel\n", "p=80 #N/mm**2 #stress\n", "P=3 #N/mm**2 #Pressure\n", "E_c=1*10**5 #N/mm**2\n", "mu=0.3 #poissoin's ratio\n", "E_s=2*10**5 #N/mm**2\n", "n=1 #No.of wires\n", "\n", "#Calculations\n", "\n", "L=6 #mm #Length of cyclinder\n", "\n", "#Force Exerted by steel wire at diameterical section\n", "F=p*2*pi*d2**2*1*4**-1 #N\n", "\n", "#Initial stress in cyclinder\n", "f_c=F*(2*t*d2)**-1 #N/mm**2\n", "\n", "#LEt due to fluid pressure alone stresses developed in steel wire be F_w and in cyclinder f1 and f2\n", "f2=P*d*(4*t)**-1 #N/mm**2\n", "\n", "#Considering the equilibrium of half the cyclinder, 6mm long we get\n", "#F_w*2*pi*4**-1*d2**2*n+f1*2*t*d2=P*d*d2\n", "#After further simplifying we get\n", "#F_w+2.122*f1=79.58 . ......................................(1)\n", "\n", "#Equating strain in wire to circumferential strain in cyclinder \n", "#F_w=(f1-mu*f2)*E_s*E_c**-1 #N/mm**2\n", "#After further simplifying we get\n", "#F_w=2*f1-11.25 ....................................(2)\n", "\n", "#Sub in equation in1 we get\n", "f1=(79.58+11.25)*(4.122)**-1 #N/mm**2\n", "F_w=2*f1-11.25 #N/mm**2\n", "\n", "#Final stresses\n", "#1) In steel Wire\n", "sigma=F_w+p #N/mm**2\n", "\n", "#2) In Cyclinder\n", "sigma2=f1-f_c\n", "\n", "#Result\n", "print\"Final Stresses developed in:cyclinder is\",round(sigma,2),\"N/mm**2\"\n", "print\" :Steel is\",round(sigma2,2),\"N/mm**2\" " ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Final Stresses developed in:cyclinder is 112.82 N/mm**2\n", " :Steel is -15.66 N/mm**2\n" ] } ], "prompt_number": 6 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.7,Page No.332" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "\n", "#Initilization of Variables\n", "\n", "d=750 #mm #Diameter of shell\n", "t=8 #mm #THickness\n", "p=2.5 #N/mm**2\n", "E=2*10**5 #N/mm**2\n", "mu=0.25 #Poissoin's ratio\n", "\n", "#Calculations\n", "\n", "#Hoop stress\n", "f1=f2=p*d*(4*t)**-1 #N/mm**2\n", "\n", "#Change in Diameter\n", "dell_d=d*p*d*(1-mu)*(4*t*E)**-1 #mm\n", "\n", "#Change in Volume\n", "dell_V=3*p*d*(1-mu)*(4*t*E)**-1*pi*6**-1*d**3\n", "\n", "#Answer for Change in diameter is incorrect in book\n", "\n", "#Result\n", "print\"Stress introduced is\",round(f1,2),\"N/mm**2\"\n", "print\"Change in Diameter is\",round(dell_d,2),\"N/mm**2\"\n", "print\"Change in Volume is\",round(dell_V,2),\"mm**3\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Stress introduced is 58.59 N/mm**2\n", "Change in Diameter is 0.16 N/mm**2\n", "Change in Volume is 145608.33 mm**3\n" ] } ], "prompt_number": 7 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.8,Page No.333" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "\n", "#Initilization of Variables\n", "\n", "d=600 #mm #Diameter of sherical shell\n", "t=10 #mm #Thickness\n", "f=80 #N/mm**2 #Permissible stress\n", "rho=0.75 #Efficiency joint\n", "\n", "#Calculations\n", "\n", "#Max Pressure\n", "p=f*4*t*rho*d**-1 #N/mm**2\n", "\n", "#Result\n", "print\"Max Pressure is\",round(p,2),\"N/mm**2\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Max Pressure is 4.0 N/mm**2\n" ] } ], "prompt_number": 8 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.9,Page No.333" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "\n", "#Initilization of Variables\n", "\n", "L=1000 #mm #Length of shell\n", "d=200 #mm #Diameter\n", "t=6 #mm #Thickness\n", "p=1.5 #N/mm**2 #Internal Pressure\n", "E=2*10**5 #N/mm**2\n", "mu=0.25 #Poissoin's Ratio\n", "\n", "#Calculations\n", "\n", "#Change in Volume of sphere\n", "dell_V_s=3*p*d*(1-mu)*(4*t*E)**-1*pi*6**-1*d**3\n", "\n", "#Hoop stress\n", "f1=p*d*(2*t)**-1 #N/mm**2\n", "\n", "#Longitudinal stress\n", "f2=p*d*(4*t)**-1 #N/mm**2\n", "\n", "#Principal strain\n", "e1=(f1-mu*f2)*E**-1\n", "e2=(f2-mu*f1)*E**-1\n", "\n", "V_c=1000 #mm**3\n", "\n", "#Change in Volume of cyclinder\n", "dell_V_c=(2*e1+e2)*pi*4**-1*d**2*L\n", "\n", "#Total Change in Diameter\n", "dell_V=dell_V_s+dell_V_c #mm**3\n", "\n", "#Result\n", "print\"Change in Volume is\",round(dell_V,2),\"mm**3\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Change in Volume is 8443.03 mm**3\n" ] } ], "prompt_number": 9 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.10,Page No.337" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "%matplotlib inline\n", "\n", "#Initilization of Variables\n", "\n", "d1=400 #mm #Internal Diameter\n", "t=100 #mm #Thickness\n", "p=80 #N/mm**2 #Fluid pressure\n", "\n", "\n", "#Calculations\n", "\n", "#Internal Radius\n", "r1=d1*2**-1 #mm\n", "\n", "#Outer Radius\n", "r_o=r1+t #mm\n", "\n", "p1=80 #N/mm**2\n", "p2=0\n", "\n", "#Now From Lame's Euation\n", "#p_x=b*(x**2)**-1-a\n", "#at x=200 #mm \n", "p_x=80 #N/mm**2\n", "#80=b*(200**2)**-1-a ..........................(1)\n", "\n", "#at x=300 #mm\n", "#p_x2=0\n", "#0=b*(300**2)**-1-a ...........................(2)\n", "\n", "#Sub equation 2 from 1\n", "#80=b*(200**2)**-1-b*(300**2)**-1\n", "#After Further simplifying we get\n", "b=(50000)**-1*(200**2*300**2*80)\n", "\n", "#From equation 2 we get\n", "a=b*(300**2)**-1\n", "\n", "#Variation of radial pressure p_x;\n", "#p_x=b*(x**2)**-1-a\n", "#After sub values and further simplifying we get\n", "\n", "#Radial pressure Variation\n", "#At \n", "x=200 #mm\n", "p_x=b*(x**2)**-1-a #N/mm**2\n", "\n", "#At\n", "x2=250 #mm\n", "p_x2=b*(x2**2)**-1-a #N/mm**2\n", "\n", "#At \n", "x3=300 #mm\n", "p_x3=b*(x3**2)**-1-a #N/mm**2\n", "\n", "\n", "#Hoop stress Distribution\n", "#Variation of F_x\n", "\n", "#At \n", "x=200 #mm\n", "F_x=b*(x**2)**-1+a #N/mm**2\n", "\n", "#At\n", "x2=250 #mm\n", "F_x2=b*(x2**2)**-1+a #N/mm**2\n", "\n", "#At\n", "x3=300 #mm\n", "F_x3=b*(x3**2)**-1+a #N/mm**2\n", "\n", "#Result\n", "print\"Max Hoop stress is\",round(F_x,2),\"N/mm**2\"\n", "print\"Min Hoop stress is\",round(F_x3,2),\"N/mm**2\"\n", "print\"Plot of Hoop stress\"\n", "\n", "#Plotting Variation of hoop stress\n", "\n", "X1=[x,x2,x3]\n", "Y1=[p_x,p_x2,p_x3]\n", "Y2=[-F_x,-F_x2,-F_x3]\n", "Z1=[0,0,0]\n", "plt.plot(X1,Y1,X1,Y2,X1,Z1)\n", "plt.xlabel(\"Length x in mm\")\n", "plt.ylabel(\"Radial Stress Distribution & Hoop Stress Distribution in N/mm**2\")\n", "plt.show()\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Max Hoop stress is 208.0 N/mm**2\n", "Min Hoop stress is 128.0 N/mm**2\n", "Plot of Hoop stress\n" ] }, { "metadata": {}, "output_type": "display_data", "png": 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skdWFW7ZsQffu3XH8+HGMGzcOY8aMAaA9wnfKlCkIDg7GmDFjEBcXJ7WK4uLi\nMGvWLPTq1QsBAQEcaCcishCN2iIlIiICycnJ5ojHZNwihYio6WTZImXVqlXSBxcWFuLDDz+UKlEo\nFJg3b55x0RIRUZuiN5GUlJRI3UqzZs1CSUmJ2YIiIqLWo1FdW60Ju7aIiJpO9oOtiIiI9GEiISIi\nkzCREBGRSRqdSBYsWIDExEQIIfDKK6/IGRMREbUijU4kkZGRWLlyJUJDQ3Hjxg05YyIiolZEbyL5\n+OOPcfHiRenxgw8+iNLSUri4uKB3795mCY6IiCyf3kTyr3/9Cz169AAAXLt2DSNHjkRQUBAOHz6M\nzZs3my1AIiKybHoTiUajQWlpKbKysjB06FBERUXhgw8+gJWVFSoqKswZIxERWTC9K9vnz58Pf39/\naDQa+Pv7w9nZGVlZWdiwYQO7toiISNLgynaNRiP9fe2117B3715ERETgo48+QpcuXcwWZFNwZTsR\nUdOZ8tvJLVKIiNqpalGNwpuFyC3Jhdpb3fy7/xIRUetVWVWJ/JJ85BTnILckV/u3OBc5JX/+Lc5B\nfmk+XDq4QOms/8TZxmCLhIiolSm5VaKbHGoniz//Xiu/Bk8nTyhdlPBx8YHS+a6/Lkp4O3vD3sYe\nALu2dDCREFFrVS2qcaXsSr3JoXaZplqjNznUPO7WsRusrawbXbesiaSiogKbNm1CVlaWNPiuUCjw\n1ltvGVWh3JhIiMgS3a66jbySvDpJofbf/JJ8ONk53UkKztq/dyeKTh06SedFNRdZTkis8fDDD8PV\n1RVqtRr29vZGVUJE1JaVVpbWTQ53jUcUlRfBw8mjTitC5aWSHns7e8PB1qGlv06TGWyR9OvXD7/9\n9pu54jEZWyRE1FyEENqupgbGI3KLc1FZVVmna+nuLiePjh5N6moyN1lbJIMHD0ZKSgpCQ0ONqoCI\nyBLdrrqN/NJ8neRwdysiryQPHe061kkOg7sP1ilztXdt9q6m1sRgiyQoKAhpaWnw8/NDhw4dtG9S\nKJCSkmKWAJuKLRIiull5s95B6tp/r5ZdRbeO3RpsRSidla2yq8kYsg62Z2VlSZUAkCry9fU1qkK5\nMZEQtV1CCFwtv2pwPOJW1S2Ds5o8nDxgY8WldDVkn/576tQpHD58GAqFAkOHDkVYWJhRldXYuHEj\nlixZgt9//x0nT56ESqUCoE1aQUFBCAwMBAAMGjQIcXFxAIDExEQ89dRTqKiowNixYxEbG1v/F2Ii\nIWqVNNUdY9fjAAAd4UlEQVQa5Jfk1zseUVOWV5IHBxuHOrOa7k4WbvZu7bqryRiyjpHExsbis88+\nw6RJkyCEwPTp0/Hss89izpw5RlUIACEhIdiyZQuee+65Os8FBAQgOTm5Tvns2bPxxRdfIDIyEmPH\njsXu3bsxevRoo2MgIvO5WXmzTjfT3a2IK2VX0LVjVykp1CSGMM+wO2UuSjjaOrb016G7GEwkn3/+\nOU6cOIGOHTsCAF599VUMHDjQpERS0+JorPz8fJSUlCAyMhIAEBMTg61btzKRELUwIQSKyosMrrKu\n0FRIiaAmKfRy74Vo32ipFeHp5MmuplaqUf+rWVlZ1XtfDpmZmYiIiECnTp3w3nvv4d5770Vubi58\nfHyk1yiVSuTm5soaB1F7p6nWoKC0QG9yyC3WdjnZ29jXGY+IUkZhUtAk6XFnh87samrDDCaSmTNn\nIioqSura2rp1K55++mmDHzxq1CgUFBTUKV+6dCnGjx9f73u8vb2RnZ0NNzc3JCUlYcKECThz5kwj\nvgYRNUXZ7TIpEegbjyi8WYgujl10ZjD5uPggpFuITllHu44t/XWohRlMJPPmzcOwYcNw5MgRKBQK\nrFu3DhEREQY/+Mcff2xyMHZ2drCzswMAqFQq+Pv748KFC1AqlcjJyZFel5OTA6VS/26VS5Yske5H\nR0cjOjq6ybEQtUZCCFyruKbTYqhvVlPZ7TLdrTeclQjoHIBhvsOkx55OnrC1tm3pr0QyiY+PR3x8\nfLN8lt5ZW8XFxXBxcUFRURGAO9N+a5qnnTt3Nrny4cOH44MPPoBarQYAXLlyBW5ubrC2tkZGRgb+\n8pe/4LfffoOrqyuioqKwevVqREZGYty4cZgzZ069YySctUVtVVV1lbarycAqaztrO4Ozmtwd3NnV\nRDpkmf47btw4/PDDD/D19a33P7jMzEyjKgSALVu2YM6cObhy5Qo6deqEiIgI7Nq1C5s2bcLixYth\na2sLKysrvPPOOxg3bhyAO9N/y8vLMXbsWKxevbr+L8REQq1Q+e3yBhfP5Rbn4vLNy3B3dK8zHlE7\nUShdlHCyc2rpr0OtELeRr4WJhCyNEAI5xTlILUxFTnFOvYniZuVNeDt7N7jK2svJi11NJBtZE8mI\nESOwf/9+g2WWgomEWpIQAlnXs5CUn4TE/EQk5SchKT8JVgorhHiEoLtL93pXWXdx7MKuJmpRsixI\nLC8vR1lZGQoLC6VxEkA7dsKpt0TapJF+LV2bNPISkVSgTRr2NvZQe6mh8lLh/wb8H9Teang5eTFR\nUJulN5F8+umniI2NRV5enjQYDgDOzs548cUXzRIckaWoFtW4cPWC1NJIzE9Ecn4yXDq4QO2thtpL\njbkD50LlpYKnk2dLh0tkVga7ttasWYOXXnrJXPGYjF1bZKqq6iqcu3pO28r4M3GcKjiFLo5doPJS\nSa0NlZcKXTt2belwiZqFrGMkX375Zb1N8piYGKMqlBsTCTWFplqDs4Vnta2MP7unfi34FV7OXlLS\nUHupEeEVgc4Opk95J7JUsm7aePLkSSmRlJeX48CBA1CpVBabSIj0qayqxJnLZ3QGwk9fPo3uLt2h\n9lZD5anC5ODJCPcMh6u9a0uHS9RqNHn67/Xr1/HYY49hz549csVkErZICABuaW7h9OXTOgPhZy6f\ngZ+bn9Q1pfZSI9wzHM4dnFs6XKIWJ2uL5G6Ojo4mLUYkam7lt8uRcilFamUk5ifi3JVz6OXeS0oY\nM8JnIMwjjPtCEcnAYCKpvcFidXU1UlNTMWXKFFmDItLnZuVN/HrpV6mVkZiXiLSiNAR2CZSSxrOq\nZxHqEdpujkglamkGu7ZqNvVSKBSwsbFBjx490L17d3PEZhR2bbUdJbdKkFyQrDOmkXktE3279dXp\nnurXrR862HRo6XCJWjXZt0jJz89HQkICrKysMGDAAHh6Wu48eSaS1ulGxQ1pFXhN0sguzkZIt5A7\nScNbjeCuwbCztmvpcInaHFkTyeeff4533nkHw4cPB6Btobz11lt45plnjKpQbkwklq+ovEhnEDwx\nLxEFpQUI8wyTptuqvFQI6hrEE/OIzETWRNK7d28cO3YM7u7uAICrV69i0KBBOH/+vFEVyo2JxLIU\n3izUaWUk5ifiatlVRHhFQOWpbWWovFTo494H1lbWLR0uUbsl66ytLl26wMnpzrbUTk5O6NKli1GV\nUdtWUFogtTRqEkfxrWJpFfjkoMl4/7730cu9F6wU8h7ZTETmozeRrFq1CgAQEBCAqKgoTJgwAQCw\nbds2hIaGmic6skhCCOSV5Om0MpLyk1ChqZAGwKeFTMOq+1fBz82PSYOojdObSEpKSqBQKODv74+e\nPXtKq9sffvhh7mLajgghkF2crbPvVFJ+EqpElTSe8VTYU1gzZg3u6XQP/9sgaod4sBVJhBDIvJ5Z\nZ1t0a4W1tMNtzUC4j4sPkwZRGyLLYPvLL7+M2NhYnQWJtSvcvn27URXKjYmkcapFNdKL0uscwORo\n6yjtO1UzEO7t7N3S4RKRzGRJJImJiVCr1Th06FCdD1coFBg2bJhRFcqNiaSuquoqXCi6oNM9lVyQ\nDFd7V52FfSovFTycPFo6XCJqAbJN/9VoNIiJicH69euNDs7c2nsi0VRrcO7KOZ2B8FMFp9CtY7c6\nZ2l0ceTsOyLSkm36r42NDS5evIhbt26hQwduQWFpblfdxtkrZ3Wm26ZcSoG3s7eUNMb3Hg+Vlwpu\nDm4tHS4RtVEG15H4+fnh3nvvxUMPPQRHR0cA2sw1b9482YOjOyqrKvHb5d90BsJ/u/wbenTqIbUy\nHg1+FOGe4ehk36mlwyWidsRgIvH394e/vz+qq6tRWlpqjpjavQpNBU5fOq1zPvjZwrPo6dZTGgh/\nIvQJhHuGw8nOyfAHEhHJyGAiCQ4OrrNt/IYNG0yqdMGCBdixYwfs7Ozg7++P//znP+jUSfuv6GXL\nlmHt2rWwtrbG6tWrcf/99wPQDv4/9dRTqKiowNixYxEbG2tSDJai7HaZ9iyNWgPh56+eRy/3XtJ0\n25nhMxHmGQZHW8eWDpeIqA6D60giIiKQnJxssKwpfvzxR4wYMQJWVlZ49dVXAQDLly9Hamoqpk2b\nhpMnTyI3NxcjR47EhQsXoFAoEBkZiX/+85+IjIzE2LFjMWfOHIwePbruF7LgwfbSylL8WvCrzkB4\nelE6groG6Uy3DfUIhb2NfUuHS0TtiCyD7bt27cLOnTuRm5uLOXPmSBWUlJTA1tbWuEj/NGrUKOl+\nVFQUNm3aBEC7/crUqVNha2sLX19fBAQE4MSJE7jnnntQUlKCyMhIAEBMTAy2bt1abyKxFMW3ipGc\nr3uWxh83/kDfrn2h8lJhSPchmBM1B3279uVZGkTUqulNJN7e3lCr1di2bRvUarWUSFxcXPCPf/yj\n2QJYu3Ytpk6dCgDIy8vDwIEDped8fHyQm5sLW1tb+Pj4SOVKpRK5ubnNFoOprldcr3OWRk5xDkI9\nQqH2UuM+v/uwYPACBHcNhq21aUmYiMjS6E0kYWFhCAsLwxNPPCG1QIqKipCTkwM3N8NTSUeNGoWC\ngoI65UuXLpVWy7///vuws7P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"text": [ "" ] } ], "prompt_number": 10 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.11,Page No.338" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "%matplotlib inline\n", "\n", "#Initilization of Variables\n", "\n", "d_o=300 #mm #Outside diameter \n", "d2=200 #mm #Internal Diameter\n", "p=14 #N/mm**2 #internal Fluid pressure\n", "t=50 #mm #Thickness\n", "r_o=150 #mm #Outside Diameter\n", "r2=100 #mm #Internal Diameter\n", "\n", "#Calculations\n", "\n", "#From Lame's Equation\n", "#p_x=b*(x**2)**-1-a #N/mm**2 ...................(1)\n", "#F_x=b*(x**2)**-1+a #N/mm**2 ...................(2)\n", "\n", "#At \n", "x=r2=100 #mm\n", "p_x=14 #N/mm**2\n", "\n", "#Sub value of p_x in equation 1 we get\n", "#14=(100)**-1*b-a ............................(3)\n", "\n", "#At\n", "x2=r_o=150 #mm\n", "p_x2=0 #N/mm**2\n", "\n", "#Sub value in equation 1 we get\n", "#0=b*(150**2)**-1-a ......................(4)\n", "\n", "#From Equations 3 and 4 we get\n", "#14=b*(100**2)**-1-b*(100**2)**-1\n", "#After sub values and further simplifying we get\n", "b=14*100**2*150**2*(150**2-100**2)**-1\n", "\n", "#From equation 4 we get\n", "a=b*(150**2)**-1\n", "\n", "#Hoop Stress\n", "#F_x=b*(x**2)**-1+a #N/mm**2\n", "\n", "#At \n", "x=100 #mm\n", "F_x=b*(x**2)**-1+a #N/mm**2\n", "\n", "#At\n", "x2=125 #mm\n", "F_x2=b*(x2**2)**-1+a #N/mm**2\n", "\n", "#At\n", "x3=150 #mm\n", "F_x3=b*(x3**2)**-1+a #N/mm**2\n", "\n", "#If thin Cyclindrical shell theory is used,hoop stress is uniform and is given by\n", "F=p*d2*(2*t)**-1 #N/mm**2\n", "\n", "#Percentage error in estimating max hoop tension\n", "E=(F_x-F)*F_x**-1*100 #%\n", "\n", "#Result\n", "print\"Max Hoop Stress Developed in the cross-section is\",round(F,2),\"N/mm**2\"\n", "print\"Plot of Variation of hoop stress\"\n", "\n", "#Plotting Variation of hoop stress\n", "\n", "X1=[x,x2,x3]\n", "Y1=[F_x,F_x2,F_x3]\n", "Z1=[0,0,0]\n", "plt.plot(X1,Y1,X1,Z1)\n", "plt.xlabel(\"Length x in mm\")\n", "plt.ylabel(\"Radial Stress Distribution & Hoop Stress Distribution in N/mm**2\")\n", "plt.show()\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Max Hoop Stress Developed in the cross-section is 28.0 N/mm**2\n", "Plot of Variation of hoop stress\n" ] }, { "metadata": {}, "output_type": "display_data", "png": 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29vaQJAknTpx4bAP379/HiBEjMGzYMMycOdNwT41GA1dXV2RkZGDgwIEcMiIi\nqgaK9hB27dplaARApRoSQmDq1Knw9vY2JAMAeOmll7Bu3TpERERg3bp1GPXwCRFERFQjLNqpnJKS\ngl9++cWwyiggIMCimx88eBDPPfcc/P39DQll4cKF6NGjB8aNG4dLly5BpVIhNjYWLR85H449BCKi\nylN0UjkmJgarV6/GmDFjIITAli1b8F//9V945513rGrQ4sCYEIiIKk3RhODn54ejR4+iWbNmAIDb\nt2+jV69eOHnypFUNWhwYEwIRUaUpXsvo4SMzbXF8JhER2Z7ZSeXJkyejZ8+eRkNGU6ZMsUVsRERk\nQxZNKicmJuLQoUMAgP79+yMoKEj5wDhkRERUaYouOwUAOzs7wyohDhkREdVNZj/dY2JiMHHiRGRn\nZ+P69euYOHGioWopERHVHVxlRERUh3CVERERVRlXGREREYBKrDJ6+IAcrjIiIqqdFNmpnJOTY/S6\n9G2lq41at25tVYMWB8aEQERUaYokBJVKZfjwv3btGjp06GDU4IULF6xq0OLAmBCIiCpN0VpGABAU\nFITk5GSrGrAWEwIRUeUpvsqIiIjqPiYEIiIC8Jhlp0uXLjV0PbKzs7Fs2TKjieXZs2fbLEgiIlKe\nyYRQUFBgmFSeNm0aCgoKbBYUERHZnkWTyjWBk8pERJVXayeVp0yZAhcXF/j5+RmuRUVFwc3NDUFB\nQQgKCsKuXbuUDIGIiCykaEKYPHlyuQ/80vmH5ORkJCcnY+jQoUqGQEREFlI0IfTv3x+tWrUqd51D\nQUREtY/FCWHu3LlITEyEEAIzZ86sUqMrVqxAQEAApk6ditzc3Crdi4iIqofFCaFHjx5YvHgx/P39\nkZeXZ3WD06dPR3p6OlJSUtC+fXvMmTPH6nsREVH1MbnsdOXKlRg+fDg6d+4MABgxYgTWrl0LJycn\ndO3a1eoG27VrZ/h+2rRpCAsLM/neqKgow/dqtRpqtdrqdomI6iKNRgONRlMt9zK57NTX1xe///47\nAODWrVsYMWIEevfujcWLF6Nnz544duyYRQ1otVqEhYUZTljLyMhA+/btAQCfffYZjh07hg0bNpQP\njMtOiYgqrSqfnSZ7CDqdDoWFhbhx4wZGjBiBwYMHY8mSJQCAu3fvWnTzCRMmYP/+/bhx4wY6deqE\nBQsWQKPRICUlBZIkwd3dHatWrbIqcCIiql4mE8KcOXPg4eEBnU4HDw8PODo6QqvVIjY21uIho+++\n+67cNZ5LqnDaAAAWK0lEQVS2RkRUOz12p7JOpzP8929/+xv27NmDoKAgfP7552jbtq2ygXHIiIio\n0hQ/D6EmMCEQEVVerS1dQURETw4mBCIiAsCEQERED5hcZVTq7t272Lx5M7RarWGSWZIk/OMf/1A8\nOCIish2zCWHkyJFo2bIlQkJC0KRJE1vERERENcDsKqOHdyzbElcZERFVnqKrjPr06YMTJ05YdXMi\nInpymO0hdOvWDefPn4e7uzsaN24s/5IkKZ4k2EMgIqo8RTemabVaQyNA2eE2KpXKqgYtDowJgYio\n0hTfqZySkoJffvkFkiShf//+CAgIsKqxSgXGhEBEVGmKziHExMRg4sSJyM7ORlZWFiZOnIjly5db\n1RgREdVeZnsIfn5+OHr0KJo1awYAuH37Nnr16mU430CxwNhDICKqNMVrGTVo0KDC74mIqO4wuzFt\n8uTJ6NmzJ8aMGQMhBLZs2cIzDYiI6iCLJpUTExNx8OBBw6RyUFCQ8oFxyIiIqNIUWWWUn58PJycn\n5OTkAChbblq6/LR169ZWNWhxYEwIRESVpkhCGD58OLZv3w6VSmVIAg9LT0+3qkGLA2NCICKqtFp7\nYtqUKVOwfft2tGvXzrAqKScnB+PHj8fFixehUqkQGxuLli1blg+MCYGIqNIUXWUUGhpq0bWKTJ48\nGbt27TK6Fh0djUGDBuHcuXMIDQ1FdHS0haESEZGSTCaEoqIi3Lx5E9nZ2cjJyTF8abVaXL161aKb\n9+/fH61atTK6FhcXh/DwcABAeHg4tmzZUoXwiYiouphcdrpq1SrExMTg2rVrCAkJMVx3dHTEjBkz\nrG4wKysLLi4uAAAXFxdkZWVZfS8iIqo+JhPCzJkzMXPmTKxYsQJvv/22Io1LklThhDUREdme2Y1p\nTk5O+Pbbb8tdnzRpklUNuri4IDMzE66ursjIyEC7du1MvjcqKsrwvVqthlqttqpNIqK6SqPRQKPR\nVMu9zK4ymjFjhuFf8UVFRfj5558RHByMTZs2WdSAVqtFWFiYYZXRvHnz0KZNG0RERCA6Ohq5ubkV\nTixzlRERUeXZdNlpbm4uxo8fj927d5t974QJE7B//37cuHEDLi4u+J//+R+MHDkS48aNw6VLl7js\nlIiomtk0IRQXF8PX1xfnzp2zqkFLMSEQEVVeVT47zc4hhIWFGb7X6/VITU3FuHHjrGqMiIhqL7M9\nhNLJCkmSYG9vj86dO6NTp07KB8YeAhFRpSm6U1mtVsPT0xO5ubnIyclBw4YNrWqIiIhqN7MJ4auv\nvkLPnj3xww8/YNOmTejZsyfWrFlji9iIiMiGzA4Zde3aFUeOHEGbNm0AADdv3kTv3r05qUxEVAsp\nOmTUtm1bNG/e3PC6efPmaNu2rVWNERFR7WVyldHSpUsBAF26dEHPnj0xatQoAMDWrVvh7+9vm+iI\niMhmTCaEgoICSJIEDw8PPP3004bdyiNHjmT9ISKiOkjRA3KqgnMIRESVp8jGtL/+9a+IiYkx2pj2\ncINxcXFWNUhERLWTyYRQWs303XffLZdtOGRERFT3PHbISKfTYdKkSdiwYYMtYwLAISMiImsotuzU\n3t4ely5dwr1796y6ORERPTnMFrdzd3dHv3798NJLL8HBwQGAnIFmz56teHBERGQ7ZhOCh4cHPDw8\noNfrUVhYaIuYiIioBphNCN7e3uXKXcfGxioWEBER1Qyz+xCCgoKQnJxs9lq1B8ZJZSKiSlNkH8LO\nnTuxY8cOXL16Fe+8846hgYKCApbAJiKqg0wmhA4dOiAkJARbt25FSEiIISE4OTnhs88+s1mARERk\nG2aHjO7fv2/oEeTk5ODKlSvVUtxOpVLByckJdnZ2aNiwIRISEowD45AREVGlKXqm8qBBgxAXFwed\nToeQkBA4Ozujb9++Ve4lSJIEjUaD1q1bV+k+RERUPcyeh5CbmwsnJyf88MMPmDRpEhISEvDTTz9V\nS+PsARAR1R5mE0JJSQkyMjIQGxuL4cOHA6ieWkaSJOGFF15A9+7dsXr16irfj4iIqsbskNE//vEP\nDBkyBH379kWPHj2QlpaGZ555psoNHzp0CO3bt0d2djYGDRoELy8v9O/fv8r3JSIi69SK8xAWLFiA\n5s2bY86cOYZrkiQhMjLS8FqtVkOtVtdAdEREtZdGo4FGozG8XrBggdXD8SYTwqJFixAREYG33367\n3Ky1JElYvny5VQ0CwJ07d1BSUgJHR0fcvn0bgwcPRmRkJAYPHmzURi3IVURETxRFVhl5e3sDAEJC\nQipssCqysrIwevRoAHKJ7T/96U9GyYCIiGyvVgwZVYQ9BCKiylPsPIS1a9ciODgYDg4OcHBwQPfu\n3bFu3TqrGiIiotrN5JDRunXrEBMTg2XLliEoKAhCCCQnJ2Pu3LmQJMlwxCYREdUNJoeMevbsiX//\n+99wd3c3uq7VajF+/Hj8+uuvygbGISMiokpTZMiooKCgXDIA5BpEBQUFVjVGRES1l8mE0KRJE5O/\n9LifERHRk8nkkFHTpk3RpUuXCn8pLS0Nd+7cUTYwDhkREVWaIvsQTp8+bXVARET05OE+BCKiOkSx\nfQhERFR/MCEQERGASiaEnJwcnDhxQqlYiIioBplNCAMGDEB+fj5ycnIQEhKCadOmYdasWbaIjYiI\nbMhsQsjLy1PsCE0iIqo9auwITSIiql3MJoTSIzQ9PDyq9QhNIiKqXbgPgYioDlF0H8K8efOQn5+P\n+/fvIzQ0FG3btsW//vUvqxojIqLay2xC2L17N5ycnLBt2zaoVCqkpaXh008/tUVsRERkQ2YTgk6n\nAwBs27YNr7zyClq0aMFJZSKiOshsQggLC4OXlxcSExMRGhqK69evV0v56127dsHLywvPPPMMFi1a\nVOX7ERFR1Vg0qZyTk4MWLVrAzs4Ot2/fRkFBAVxdXa1utKSkBJ6envjpp5/QsWNHPPvss/juu+/Q\nrVu3ssA4qWyg0WigVqtrOoxagc+iDJ9FGT6LMopOKt++fRv/+7//i7feegsAcO3aNRw/ftyqxkol\nJCSgS5cuUKlUaNiwIV599VVs3bq1SvesyzQaTU2HUGvwWZThsyjDZ1E9zCaEyZMno1GjRjh8+DAA\noEOHDnj//fer1OjVq1fRqVMnw2s3NzdcvXq1SvckIqKqMZsQ0tLSEBERgUaNGgEAmjVrVuVGOSlN\nRFT7mDwxrVTjxo1RVFRkeJ2WlobGjRtXqdGOHTvi8uXLhteXL1+Gm5ub0Xs8PDyYOB6yYMGCmg6h\n1uCzKMNnUYbPQubh4WH175pNCFFRURg6dCiuXLmC1157DYcOHcLatWutbhAAunfvjj/++ANarRYd\nOnTA999/j++++87oPefPn69SG0REVDmPTQh6vR63bt3C5s2bcfToUQBATEwMnJ2dq9aovT3++c9/\nYsiQISgpKcHUqVONVhgREZHtmV12GhISgsTERFvFQ0RENcTspPKgQYOwZMkSXL58GTk5OYavqpgy\nZQpcXFzg5+dnuJaTk4NBgwaha9euGDx4MHJzcw0/W7hwIZ555hl4eXlhz549VWq7tqnoWWzcuBE+\nPj6ws7NDUlKS0fvr27OYO3c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"text": [ "" ] } ], "prompt_number": 11 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.12,Page No.339" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "\n", "#Initilization of Variables\n", "\n", "d_o=300 #mm #Outside diameter \n", "d2=200 #mm #Internal Diameter\n", "p=12 #N/mm**2 #internal Fluid pressure\n", "F_max=16 #N/mm**2 #Tensile stress\n", "r_o=150 #mm #Outside Diameter\n", "r2=100 #mm #Internal Diameter\n", "\n", "#Calculations\n", "\n", "#Let p_o be the External Pressure applied.\n", "#From LLame's theorem\n", "#p_x=b*(x**2)**-1-a ..............(1)\n", "#F_x=b*(x**2)**-1+a ...........................(2)\n", "\n", "#Now At\n", "x=100 #mm\n", "p_x=12 #N/mm**2\n", "#sub in equation 1 we get\n", "#12=b*(100**2)**-1-a . ..................(3)\n", "\n", "#The Max Hoop stress occurs at least value of x where\n", "x=r1=100 #mm\n", "#16=b*(100**2)**-1+a .......................(4)\n", "\n", "#From Equations 1 and 2 we get\n", "#28=b*(100**2)**-1+b*(100**2)**-1\n", "#After furhter Simplifying we get\n", "b=28*100**2*2**-1\n", "\n", "#sub in equation 1 we get\n", "a=-(12-(b*(100**2)**-1))\n", "\n", "#Thus At\n", "x2=150 #mm\n", "p_o=b*(x2**2)**-1-a\n", "\n", "#Result\n", "print\"Minimum External applied is\",round(p_o,2),\"N/mm**2\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Minimum External applied is 4.22 N/mm**2\n" ] } ], "prompt_number": 12 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.13,Page No.340" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "\n", "#Initilization of Variables\n", "\n", "d1=160 #mm #Internal Diameter \n", "r1=80 #mm #External Diameter\n", "p1=40 #N/mm**2 #Internal Diameter\n", "P_max=120 #N/mm**2 #Allowable stress\n", "\n", "#Calculations\n", "\n", "#From Lame's Equation we have\n", "#p_x=b*(x**2)**-1-a ..........................(1)\n", "#F_x=b*(x**2)**-1+a ...........................(2)\n", "\n", "#At \n", "x=r1=80 #N/mm**2 \n", "#Sub in equation 1 we get\n", "#120=b*(80**2)**-1+a ........................(3)\n", "\n", "#The hoop tension at inner edge is max stress\n", "#Hence\n", "#120=b*(80**2)**-1+a .............................(4)\n", "\n", "#From Equation 3 and 4 we get\n", "b=160*80**2*2**-1 \n", "\n", "#Sub in equation 3 we get\n", "a=-(40-(b*(80**2)**-1))\n", "\n", "#Let External radius be r_o.Since at External Surface is Zero,we get\n", "#0=b*(r_o)**-1-a\n", "#After Further simplifying we get\n", "r_o=(b*a**-1)**0.5\n", "\n", "#Thickness of Cyclinder \n", "t=r_o-r1 #mm\n", "\n", "#Result\n", "print\"Thickness Required is\",round(t,2),\"mm\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Thickness Required is 33.14 mm\n" ] } ], "prompt_number": 13 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.14,Page No.341" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "\n", "#Initilization of Variables\n", "\n", "d_o=300 #mm #Outside diameter \n", "d1=180 #mm #Internal Diameter\n", "p=12 #N/mm**2 #internal Fluid pressure\n", "p_o=6 #N/mm**2 #External Pressure\n", "r_o=150 #mm #Outside Diameter\n", "r=90 #mm #Internal Diameter\n", "\n", "\n", "#Calculations\n", "\n", "#From Lame's Equation we have\n", "#p_x=b*(x**2)**-1-a ..........................(1)\n", "#F_x=b*(x**2)**-1+a ...........................(2)\n", "\n", "#At \n", "x=r1=90 #N/mm**2 \n", "p=42 #N/mm**2\n", "#Sub in equation 1 we get\n", "#42=b*(90**2)**-1-a ..............................(3)\n", "\n", "#At \n", "x=r_o=150 #mm\n", "p2=6 #N/mm**2\n", "#sub in equation 1 we get\n", "#6=b*(150**2)**-1-a ..............................(4)\n", "\n", "#From equations 3 and 4 weget\n", "#36=b*(90**2)**-1-b2(150**2)**-1\n", "#After further simplifying we get\n", "b=36*90**2*150**2*(150**2-90**2)**-1\n", "\n", "#Sub value of b in equation 4 we get\n", "a=b*(150**2)**-1-p_o\n", "\n", "#At \n", "x=r1=90 #mm\n", "F_x=b*(x**2)**-1+a #N/mm**2\n", "\n", "#At \n", "x2=r_o=150 #mm \n", "F_x2=b*(x2**2)**-1+a #N/mm**2\n", "\n", "#Now if External pressure is doubled i.e p_o2=12 #N/mm**2 We have\n", "p_o2=12 #N/mm**2\n", "#sub in equation 4 we get\n", "#12=b2*(150**2)**-1-a2 ..........................(5)\n", "\n", "#Max Hoop stress is to be 70.5 #N/mm**2,which occurs at x=r1=90 #mm\n", "#Sub in equation 4 we get\n", "#70.5=b*(90**2)**-1+a2 ................................(6)\n", "\n", "#Adding equation 5 and 6\n", "#82.5=b2*(150**2)**-1+b*(90**2)**-1\n", "#After furhter simplifying we get\n", "b2=82.5*150**2*90**2*(150**2+90**2)**-1\n", "\n", "#Sub in equation 5 we get\n", "a2=b2*(150**2)**-1-12 \n", "\n", "#If p_i is the internal pressure required then from Lame's theorem\n", "p_i=b2*(r1**2)**-1-a2\n", "\n", "#Result\n", "print\"Stresses int the material are:F_x\",round(F_x,2),\"N/mm**2\"\n", "print\" :F_x2\",round(F_x2,2),\"N/mm**2\"\n", "print\"Internal Pressure that can be maintained is\",round(p_i,2),\"N/mm**2\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Stresses int the material are:F_x 70.5 N/mm**2\n", " :F_x2 34.5 N/mm**2\n", "Internal Pressure that can be maintained is 50.82 N/mm**2\n" ] } ], "prompt_number": 14 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.15,Page No.344" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "%matplotlib inline\n", "\n", "#Initilization of Variables\n", "\n", "r1=200 #mm #Inner Radius\n", "r2=250 #mm #Radius at common surface\n", "r3=300 #mm #Outer radius\n", "p=6 #N/mm**2 #Inital pressure\n", "p2=80 #N/mm**2 #Pressure\n", "\n", "#Calculations\n", "\n", "#Inner Cyclinder:\n", "\n", "#From Lame's Equation we have\n", "#p_x=b*(x**2)**-1-a ..........................(1)\n", "#F_x=b*(x**2)**-1+a ...........................(2)\n", "\n", "#At \n", "x=r1=200 #mm\n", "p_x=0\n", "#0=b1*(250**2)**-1-a1 .................(3)\n", "\n", "#At x=r2=250 #mm\n", "p_x2=6 #N/mm**2\n", "#6=b1*(250**2)-a1 ...................(4)\n", "\n", "#From Equation 3 and 4 we get\n", "b1=6*200**2*250**2*(200**2-250**2)**-1\n", "\n", "#From equation 3 we get\n", "a1=b1*(200**2)**-1\n", "\n", "F_200=b1*(200**2)**-1+a1\n", "F_250=b1*(250**2)**-1+a1\n", "\n", "#For outer cyclinder \n", "#From Lame's Equation we have\n", "#p_x2=b2*(x**2)**-1-a2 ..........................(5)\n", "#F_x2=b2*(x**2)**-1+a2 ...........................(6)\n", "\n", "\n", "#At \n", "x2=r2=250 #mm\n", "p_x2=6 #N/mm**2\n", "#6=b2*(250**2)**-1-a2 ...........................(7) \n", "\n", "#At\n", "x3=300 #mm\n", "#p_x2=0\n", "#0=b2**2*(300**2)**-1-a2 .................................(8)\n", "\n", "#from equation 7 and 8 we get\n", "b2=6*250**2*300**2*(300**2-250**2)**-1\n", "\n", "#sub in equation 8 we get\n", "a2=b2*(300**2)**-1\n", "\n", "F_250_2=b2*(250**2)**-1+a2\n", "F_300_2=b2*(300**2)**-1+a2\n", "\n", "#When Fluid is admitted\n", "#Let Lame's equation be\n", "#p_x3=b3*(x**2)**-1-a3 ..........................(5)\n", "#F_x3=b3*(x**2)**-1+a3 ...........................(6)\n", "\n", "\n", "#At x=200\n", "p_x3=80 #N/mm**2\n", "#80=b3*(200**2)**-1-a3 ................................(7)\n", "\n", "#At x=300 #mm\n", "#p_x=0\n", "#0=b3*(300**2)**-1-a3 ..............................(8)\n", "\n", "#from Equation 7 and 8 we get\n", "b3=80*200**2*300**2*(300**2-200**2)**-1\n", "\n", "#From Equation 8 we get\n", "a3=b3*(300**2)**-1\n", "\n", "#Hoop stresses \n", "F_200_3=b3*(200**2)**-1+a3 #N/mm**2\n", "F_250_3=b3*(250**2)**-1+a3 #N/mm**2\n", "F_300_3=b3*(300**2)**-1+a3 #N/mm**2\n", "\n", "#Pressure at common surface\n", "p_250=b3*(250**2)**-1-a3 #N/mm**2\n", "\n", "#final stress\n", "f_200=F_200+F_200_3 #N/mm**2\n", "f_250=F_250+F_250_3 #N/mm**2\n", "f_300=F_250_2+F_250_3 #N/mm**2\n", "f_300_2=F_300_2+F_300_3 #N/mm**2\n", "\n", "#Result\n", "print\"final Hoop stress are:f_200\",round(f_200,2),\"N/mm**2\"\n", "print\" :f_250\",round(f_250,2),\"N/mm**2\"\n", "print\" :f_300\",round(f_300,2),\"N/mm**2\"\n", "print\" :f_300_2\",round(f_300_2,2),\"N/mm**2\"\n", "print\"Variation of Hoop stress and Radial stress\"\n", "\n", "#Final stresses\n", "#Variation of hoop stress \n", " \n", "X1=[x,x2,x3,x3]\n", "Y1=[f_200,f_250,f_300,f_300_2]\n", "Z1=[0,0,0,0]\n", "plt.plot(X1,Y1,X1,Z1)\n", "plt.xlabel(\"Length x in mm\")\n", "plt.ylabel(\"Hoop Stress Distribution in N/mm**2\")\n", "plt.show()\n", "\n", "#Due to Fluid\n", "#Variation of hoop stress \n", " \n", "X1=[x,x2,x3]\n", "Y1=[F_200_3,F_250_3,F_300_3]\n", "Z1=[0,0,0]\n", "plt.plot(X1,Y1,X1,Z1)\n", "plt.xlabel(\"Length x in mm\")\n", "plt.ylabel(\"Hoop Stress Distribution in N/mm**2\")\n", "plt.show()\n", "\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "final Hoop stress are:f_200 174.67 N/mm**2\n", " :f_250 128.83 N/mm**2\n", " :f_300 189.43 N/mm**2\n", " :f_300_2 155.27 N/mm**2\n", "Variation of Hoop stress and Radial stress\n" ] }, { "metadata": {}, "output_type": "display_data", "png": 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"text": [ "" ] } ], "prompt_number": 15 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.16,Page No.348" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "\n", "#Initilization of Variables\n", "\n", "do=200 #mm #Inner Diameter\n", "r_o=100 #mm #Inner radius\n", "d1=300 #mm #outer diameter\n", "r1=150 #mm #Outer radius\n", "d2=250 #mm #Junction Diameter\n", "r2=125 #mm #Junction radius\n", "E=2*10**5 #N/mm**2 #Modulus of Elasticity\n", "p=30 #N/mm**2 #radial pressure\n", "\n", "#Calculations\n", "\n", "#from Lame's Equation we get\n", "#p_x=b*(x**2)**-1-a ..........................(1)\n", "#F_x=b*(x**2)**-1+a ...........................(2)\n", "\n", "#Then from Boundary condition \n", "#p_x=0 at x=100 #mm\n", "#0=b1*(100**2)**-1-a1 .....................(3)\n", "\n", "#p_x2=30 #N/mm**2 at x2=125 #mm\n", "#30=b1*(125**2)**-1-a1 ................................(4)\n", "\n", "#From equation 3 and 4 we get\n", "b1=30*125**2*100**2*(100**2-125**2)**-1\n", "\n", "#From Equation 3 we get\n", "a1=b1*(100**2)**-1\n", "\n", "#therefore Hoop stress in inner cyclinder at junction\n", "F_2_1=b1*(125**2)**-1+a1 #N/mm**2\n", "\n", "#Outer Cyclinder\n", "#p_x=b*(x**2)**-1-a ..........................(5)\n", "#F_x=b*(x**2)**-1+a ...........................(6)\n", "\n", "#Now at x=125 #mm\n", "#p_x3=30 #N/mm**2\n", "#30=b2*(125**2)**-1-a2 ..................................(7)\n", "\n", "#At x=150 #mm\n", "#p_x4=0\n", "#0=b2*(150**2)**-1-a2 ...................................(8)\n", "\n", "#From equations 7 and 8\n", "b2=30*150**2*125**2*(150**2-125**2)**-1\n", "\n", "#From eqauation 8 we get\n", "a2=b2*(150**2)**-1\n", "\n", "#Hoop stress at junction \n", "F_2_0=b2*(125**2)**-1+a2 #N/mm**2\n", "\n", "rho_r=(F_2_0-F_2_1)*E**-1*r2\n", "\n", "#Result\n", "print\"Shrinkage Allowance is\",round(rho_r,3),\"mm\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Shrinkage Allowance is 0.189 mm\n" ] } ], "prompt_number": 16 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.17,Page No.350" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "\n", "#Initilization of Variables\n", "\n", "d_o=500 #mm #Outer Diameter\n", "r_o=250 #mm #Outer Radius\n", "d1=300 #mm #Inner Diameter\n", "r1=150 #mm #Inner Radius\n", "d2=400 #mm #Junction Diameter\n", "E=2*10**5 #N/mm**2 #Modulus ofElasticity\n", "alpha=12*10**-6 #Per degree celsius\n", "dell_d=0.2 #mm\n", "dell_r=0.1 #mm\n", "\n", "#Calculations\n", "\n", "#Let p be the radial pressure developed at junction\n", "#Let Lame's Equation for internal cyclinder be\n", "#p_x=b*(x**2)**-1-a ................................(1)\n", "#F_x=b*(x**2)**-1+a ...............................(2)\n", "\n", "#At \n", "x=150 #mm \n", "p_x=0\n", "#Sub in equation 1 we get\n", "#0=b*(150**2)**-1-a .........................(3)\n", "\n", "#At \n", "x2=200 #mm\n", "#p_x2=p\n", "#p=b*(200**2)**-1-a ......................(4)\n", " \n", "#From Equation 3 and 4\n", "#p=b*(200**2)**-1-b(150**2)**-1\n", "#after further simplifying we get\n", "#b=-51428.571*p\n", "\n", "#sub in equation 3 we get\n", "#a1=-2.2857*p\n", "\n", "#therefore hoop stress at junction is\n", "#F_2_1=-21428.571*p*(200**2)**-1-2.2857*p\n", "#after Further simplifying we geet\n", "#F_2_1=3.5714*p\n", "\n", "#Let Lame's Equation for cyclinder be \n", "#p_x=b*(x**2)**-1-a .........................5\n", "#F_x=b*(x**2)**-1+a .............................6\n", "\n", "#At \n", "x=200 #mm\n", "#p_x=p2\n", "#p2=b2*(20**2)**-1-a2 ...................7\n", "\n", "#At\n", "x2=200 #mm\n", "p_x2=0\n", "#0=b2*(250**2)**-1-a2 ....................8\n", "\n", "#from equation 7 and 8 we get\n", "#p2=b2*(200**2)**-1-b2*(250**2)**-1\n", "#After further simplifying we get\n", "#p2=b2*(250**2-200**2)*(200**2*250**2)**-1\n", "#b2=111111.11*p\n", "\n", "#from equation 7\n", "#a2=b2*(250**2)**-1\n", "#further simplifying we get\n", "#a2=1.778*p\n", "\n", "#At the junctionhoop stress in outer cyclinder \n", "#F_2_0=b2*(200**2)**-1+a2\n", "#After further simplifying we get\n", "#F_2_0=4.5556*p\n", "\n", "#Considering circumferential strain,the compatibility condition\n", "#rho_r*r2**-1=1*E**-1*(F_2_1+F_2_0)\n", "#where F_2_1 is compressive and F_2_0 is tensile\n", "#furter simplifying we get\n", "p=0.1*200**-1*2*10**5*(3.5714+4.5556)**-1\n", "\n", "#Let T be the rise in temperature required\n", "#dell_d=d*alpha*T\n", "#After sub values and further simplifying we get\n", "d=250 #mm\n", "T=dell_d*(d*alpha)**-1 #Per degree celsius\n", "\n", "#Result\n", "print\"Radial Pressure Developed at junction\",round(p,2),\"N/mm**2\"\n", "print\"Min Temperatureto outer cyclinder\",round(T,2),\"Per degree Celsius\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Radial Pressure Developed at junction 12.3 N/mm**2\n", "Min Temperatureto outer cyclinder 66.67 Per degree Celsius\n" ] } ], "prompt_number": 17 }, { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Example 8.8.18,Page No.355" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "import numpy as np\n", "%matplotlib inline\n", "\n", "#Initilization of Variables\n", "\n", "d_o=400 #mm #Outer Diameter\n", "r_o=200 #mm #Outer radius\n", "t=50 #mm #Thickness\n", "r1=150 #mm #Internal Radius\n", "p=50 #N/mm**2 #Internal Pressure\n", "\n", "#Calculations\n", "\n", "#The Radial Pressure and hoop stress at any radial distance x are given by\n", "#p_x=b*(x**2)**-1-a ..........................(1)\n", "#F_x=b*(x**2)**-1+a ...........................(2)\n", "\n", "#Now at\n", "x=150 #N/mm**2\n", "p_x1=50 #N/mm**2\n", "#Sub in equation 1 we get\n", "#50=2*b*(150**3)**-1-a ...........................(3)\n", "\n", "#At x=200 #mm\n", "p_x2=0\n", "#0=2*b*(200**2)**-1-a ....................(4)\n", "\n", "#From equation 3 and 4 we get\n", "#50=2*b*(150**3)**-1-2*b*(200**3)**-1\n", "#After further simplifying we get\n", "b=50*150**3*200**3*(200**3-150**3)**-1*2**-1\n", "\n", "#Sub in equation 3 we get\n", "a=b*(200**3)**-1\n", "\n", "#Now At\n", "x=150 #mm\n", "F_x=b*(x**3)**-1+a\n", "\n", "#Now At\n", "x2=160 #mm\n", "F_x2=b*(x2**3)**-1+a\n", "\n", "#Now At\n", "x3=170 #mm\n", "F_x3=b*(x3**3)**-1+a\n", "\n", "#Now At\n", "x4=180 #mm\n", "F_x4=b*(x4**3)**-1+a\n", "\n", "#Now At\n", "x5=190 #mm\n", "F_x5=b*(x5**3)**-1+a\n", "\n", "#Now At\n", "x6=200 #mm\n", "F_x6=b*(x6**3)**-1+a\n", "\n", "#Result\n", "print\"Plot of Variation of hoop stress\"\n", "\n", "#Plotting Variation of hoop stress\n", "\n", "X1=[x,x2,x3,x4,x5,x6]\n", "Y1=[F_x,F_x2,F_x3,F_x4,F_x5,F_x6]\n", "Z1=[0,0,0,0,0,0]\n", "plt.plot(X1,Y1,X1,Z1)\n", "plt.xlabel(\"Length x in mm\")\n", "plt.ylabel(\"Hoop Stress Distribution in N/mm**2\")\n", "plt.show()\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Plot of Variation of hoop stress\n" ] }, { "metadata": {}, "output_type": "display_data", "png": 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