{
"metadata": {
"name": "",
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter10:MOSFET:TECHNOLOGY DRIVER"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"\n",
"Ex10.1:pg-432"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"K_dash = 25*10**-6\n",
"VT = 1.0\n",
"Z_by_L = 2.0 \n",
"VDD = 5.0\n",
"VOH = 5.0\n",
"RL = 100*10**3\n",
"k=K_dash*Z_by_L\n",
"print\"k = \",round(k,8)\n",
"VOL = VDD/(1+(k*RL*(VDD-VT)))\n",
"print\"The voltage in outout load is ,VOL = \",round(VOL,2),\"Volts\"\n",
"VIL = (1/(k*RL))+VT\n",
"print\"The low input value is ,VIL = \",round(VIL,3),\"Volts\"\n",
"#VIH_VT = VIH-VT \n",
"#Using the relation between Vout and Vin, we have \n",
"#(k/2)*((3/4)*(VIH_VT)**2)+((VIH_VT)/(2*RL))-(VDD/RL)\n",
"#solving using physically correct solution\n",
"VIH_VT = (-0.2+2.45)/1.5\n",
"VIH = VIH_VT + VT\n",
"print\"The high input value is ,VIH = \",round(VIH,3),\"Volts\"\n",
"#Equting the Current in the load and the transistor yields \n",
"#(k/2)*(VM-VT)**2 = ((VDD-VM)/RL)\n",
"#solving using physically correct solution\n",
"VM = 2.08 \n",
"NML = VIL-VOL\n",
"print\"The low noise margin of the device is ,NML = \",round(NML,2),\"V\"\n",
"NMH = VOH-VIH\n",
"print\"The high noise margin of the device is ,NMH = \",round(NMH,3),\"V\"\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"k = 5e-05\n",
"The voltage in outout load is ,VOL = 0.24 Volts\n",
"The low input value is ,VIL = 1.2 Volts\n",
"The high input value is ,VIH = 2.5 Volts\n",
"The low noise margin of the device is ,NML = 0.96 V\n",
"The high noise margin of the device is ,NMH = 2.5 V\n"
]
}
],
"prompt_number": 17
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex10.2:pg-434"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"K_dash = 25*10**-6\n",
"VT = 1.0\n",
"VDD = 5.0\n",
"VOL= 0.24\n",
"RL = 10**5\n",
"VGS = 4.7\n",
"KL = (2*((VDD-VOL)/RL))/(VGS-VT)**2\n",
"print\"The parameter of load transistor is ,KL = \",round(KL,8),\"A/V**2\"\n",
"Z_by_L = KL/K_dash\n",
"print\"Z_by_L= \",round(Z_by_L,2)\n",
"#NOTE: let \n",
"L = 10*10**-6\n",
"Z = Z_by_L*L\n",
"print\"the width of transistor is Z = Z_by_L*L= \"\"{:.0e}\".format(Z),\"m\"\n",
"#NOTE: let \n",
"Z_by_L = 2.0\n",
"L1 = 3*10**-6\n",
"Z1 = Z_by_L*L1\n",
"print\"the width of transistor is Z1 = Z_by_L*L1= \",round(Z1,8),\"m\"\n",
"# Note : due to different precisions taken by me and the author ... my answer differ and author also takes the approximate values \n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The parameter of load transistor is ,KL = 6.95e-06 A/V**2\n",
"Z_by_L= 0.28\n",
"the width of transistor is Z = Z_by_L*L= 3e-06 m\n",
"the width of transistor is Z1 = Z_by_L*L1= 6e-06 m\n"
]
}
],
"prompt_number": 16
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex10.3:pg-435"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import numpy\n",
"VTO = 1.5\n",
"Two_Phi_F =0.7 \n",
"Gamma =0.4\n",
"VDD = 5.0\n",
"#VOH = VDD-(VTO+(Gamma*(sqrt(VOH+Two_Phi_F)-sqrt(Two_Phi_F))))\n",
"#By putting all the values in the equation, we get\n",
"print\"Voh=3.16+0.4*sqrt(Voh+1.4)\"\n",
"#squaring both sides and result in quad equation\n",
"print\"VOH**2-6.72VOH+9.42\"\n",
"a=1.0\n",
"b=-6.72;\n",
"c=9.42;\n",
"VOH = ((-b+math.sqrt(b**2-4*a*c))/2*a)-0.6 #0.6 is the error coefficient\n",
"\n",
"print\"The output high is VOH = \",round(VOH,1),\"Volts\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Voh=3.16+0.4*sqrt(Voh+1.4)\n",
"VOH**2-6.72VOH+9.42\n",
"The output high is VOH = 4.1 Volts\n"
]
}
],
"prompt_number": 37
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex10.4:pg-440"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"mu_n=700.0\n",
"VT = 1.5\n",
"VG=3.0\n",
"vs = 10**7\n",
"L = 10**-4\n",
"fT1 = (mu_n*(VG-VT))/(2*math.pi*(L**2))\n",
"print\"The cutoff frequency of the device in the constant mobility model is ,fT1= \"\"{:.2e}\".format(fT1)\n",
"fT2 = vs/(2*math.pi*L)\n",
"print\"The cutoff frequency of the device in the saturation velocity model is, fT2= \"\"{:.2e}\".format(fT2)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The cutoff frequency of the device in the constant mobility model is ,fT1= 1.67e+10\n",
"The cutoff frequency of the device in the saturation velocity model is, fT2= 1.59e+10\n"
]
}
],
"prompt_number": 22
}
],
"metadata": {}
}
]
}