{
 "metadata": {
  "name": ""
 },
 "nbformat": 3,
 "nbformat_minor": 0,
 "worksheets": [
  {
   "cells": [
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "<h1>Chapter 3: Operators and Expressions<h1>"
     ]
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "<h3>Example 3.13, Page number: 3.9 <h3>"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "\n",
      "import ctypes as ct\n",
      "\n",
      "print \"interger  : \",ct.sizeof(ct.c_int())\n",
      "print \"float     : \",ct.sizeof(ct.c_float())\n",
      "print \"double    : \",ct.sizeof(ct.c_double())\n",
      "print \"character : \",ct.sizeof(ct.c_char())\n",
      "\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "interger  :  4\n",
        "float     :  4\n",
        "double    :  8\n",
        "character :  1\n"
       ]
      }
     ],
     "prompt_number": 1
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "<h3>Example 3.30, Page number: 3.19<h3>"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "\n",
      "\n",
      "print \"for the equation ax^2+bx+c \\n\"\n",
      "\n",
      "a=2\n",
      "b=6\n",
      "c=3\n",
      "\n",
      "root=(b*b-4*a*c)**0.5\n",
      "x1=(-b + root)/(2*a)\n",
      "x2=(-b - root)/(2*a)\n",
      "\n",
      "print \"x1=\",x1\n",
      "print \"x2=\",x2\n",
      "\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "for the equation ax^2+bx+c \n",
        "\n",
        "x1= -0.633974596216\n",
        "x2= -2.36602540378\n"
       ]
      }
     ],
     "prompt_number": 3
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "<h3>Example 3.31, Page number: 3.20<h3>"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "\n",
      "\n",
      "\n",
      "lower=\"l\"\n",
      "upper=lower.upper()\n",
      "print upper\n",
      "\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "L\n"
       ]
      }
     ],
     "prompt_number": 2
    }
   ],
   "metadata": {}
  }
 ]
}