{
"metadata": {
"name": "",
"signature": "sha256:8d1a6e24325b21ce86c3b6da78ff6614496eb66a81611477ea9a7b9f8a72ae03"
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"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 5 Properties of matter"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.1 Page no 76"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"m=1 #Mass of torsional pendulum in kg\n",
"R=0.06 #Radius of torsional pendulum in m\n",
"l=1.2 #Length of the wire in m\n",
"r=0.0008 #Radius of wire in m\n",
"S=(9*10**9) #Modulus of rigidity of the material in N/m^2\n",
"\n",
"#Calculations\n",
"import math\n",
"I=(1/2.0)*m*R**2\n",
"C=(3.14*S*r**4)/(2*l)\n",
"T=2*3.14*math.sqrt(I/C)\n",
"\n",
"#Output\n",
"print\"Period of pendulum is \",round(T,1),\"s\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Period of pendulum is 3.8 s\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.2 Page no 76"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"l=0.8 #Length of the wire in m\n",
"d=(1.8*10**-3) #Diameter of the wire in m\n",
"a=1.5 #Angle of twist in degrees\n",
"S=(1.8*10**11) #Modulus of rigidity of the material in N/m^2\n",
"\n",
"#Calculations\n",
"r=(a*3.14)/180.0\n",
"W=((3.14*S*(d/2.0)**4*r**2)/(4*l))/10.0**-5\n",
"\n",
"#Output\n",
"print\"Work required to twist the wire is \",round(W,2),\"*10^-5 J\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Work required to twist the wire is 7.93 *10^-5 J\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.3 Page no 76"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"l=2 #Length of wire in m\n",
"d=(0.4*10**-3) #Diameter of the wire in m\n",
"x=(1.03*10**-3) #Extension in length in m\n",
"L=2 #Load in kg\n",
"C=(4.52*10**-6) #Couple in N/m\n",
"a=0.03 #Twist angle in radians\n",
"\n",
"#Calculations\n",
"Y=((L*9.8*l)/(x*3.14*(d/2.0)**2))/10**11\n",
"S=((C*2*l)/(3.14*(d/2.0)**4*a))/10**11\n",
"s=(Y/(2*S))-1\n",
"\n",
"#Output\n",
"print\"Youngs modulus is \",round(Y,2),\"*10**11 N/m^2\"\n",
"print\"Modulus of rigidity is \",round(S,2),\"*10**11 N/m^2\"\n",
"print\"Poissons ratio is \",round(s,2)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Youngs modulus is 3.03 *10**11 N/m^2\n",
"Modulus of rigidity is 1.2 *10**11 N/m^2\n",
"Poissons ratio is 0.26\n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.4 Page no 76"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"r=0.003 #Radius of drop of glycerine in m\n",
"T=(63.1*10**-3) #Surface tension of glycerine in N/m\n",
"\n",
"#Calculations\n",
"P=((2*T)/r)\n",
"\n",
"#Output\n",
"print\"Excess pressure inside the drop of glycerine is \",round(P,2),\"N/m^2\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Excess pressure inside the drop of glycerine is 42.07 N/m^2\n"
]
}
],
"prompt_number": 8
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.5 Page no 76"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"r1=0.001 #Initial radius in m\n",
"r2=0.004 #Final radius in m\n",
"t=2*10**-3 #Time in s\n",
"s=(7*10**-2) #Surface tension of water in N/m\n",
"\n",
"#Calculations\n",
"P=((2*s)*((1/r2)-(1/r1)))/(t*10**4)\n",
"\n",
"#Output\n",
"print\"Rate of change of pressure is \",P,\"*10**4 N/m**2 s\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Rate of change of pressure is -5.25 *10**4 N/m**2 s\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.6 Page no 77"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"d=0.02 #Diamter of soap bubble in m\n",
"s=(25*10**-3) #Surface tension in N/m\n",
"#Initial surface area of the bubble is zero and final area is 2*4*pie*r^2 where r is the radius of the bubble\n",
"\n",
"#Calculations\n",
"W=(s*2*4*3.14*(d/2.0)**2)/10.0**-5\n",
"\n",
"#Output\n",
"print\"Work done in blowing a soap bubble is \",W,\"*10**-5 J\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Work done in blowing a soap bubble is 6.28 *10**-5 J\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.7 Page no 77"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"r=0.01 #Radius of liquid drop in m\n",
"n=500 #Number of drops\n",
"s=(63*10**-3) #Surface tension in N/m\n",
"\n",
"#Calculations\n",
"r1=(((4*3.14*r**3)/3.0)/((n*4*3.14)/3.0))**(1/3.0)\n",
"As=(n*4*3.14*r1**2)\n",
"A=4*3.14*r**2\n",
"W=(s*(As-A))/10.0**-4\n",
"\n",
"#Output\n",
"print\"Energy required to break up a drop of a liquid is \",round(W,1),\"*10**-4 J\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Energy required to break up a drop of a liquid is 5.5 *10**-4 J\n"
]
}
],
"prompt_number": 8
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.8 Page no 77"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#given\n",
"d=0.04 #Inside diameter of garden hose in m\n",
"D=0.01 #Diamter of nozzle opening in m\n",
"v1=0.6 #speed of flow of water in the hose in m/s\n",
"\n",
"#calculations\n",
"a=3.14*(d/2.0)**2\n",
"A=3.14*(D/2.0)**2\n",
"v2=(v1*a)/A\n",
"\n",
"#Output\n",
"print\"Speed of flow through the nozzle is \",v2,\"m/s\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Speed of flow through the nozzle is 9.6 m/s\n"
]
}
],
"prompt_number": 10
}
],
"metadata": {}
}
]
}