{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# Chapter 02:Static Equilibrium" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Ex2.1:pg-41" ] }, { "cell_type": "code", "execution_count": 1, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Tension in String 1 is F1= 48.0 N\n", "\n", "Tension in String 2 is F2= 64.0 N\n" ] } ], "source": [ " #Example 2_1\n", "\n", "\n", " #To find the tension in the other two Strings\n", " #As Sigma(Fx)=0\n", "F3=80 #units in Newtons\n", "Fx1=F3*math.sin(37*math.pi/180) #units in Newtons\n", "Fy1=F3*math.cos(37*math.pi/180) #units in Newtons\n", "F2=round(Fy1+0) #units in Newtons\n", "F1=round(Fx1+0) #units in Newtons\n", "print \"Tension in String 1 is F1=\",round(F1),\" N\\n\"\n", "print \"Tension in String 2 is F2=\",round(F2),\" N\"\n" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Ex2.2:pg-41" ] }, { "cell_type": "code", "execution_count": 2, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Tension in string 1 is F1= 240.0 N\n", "\n", "Tension in string 2 is F2= 319.0 N\n", "\n" ] } ], "source": [ " #Example 2_2\n", "\n", "\n", " #To find the tension in the three cords that hold the object\n", " #As Sigma(Fx)=0\n", "theta1=37 #units in degrees\n", "theta2=53 #units in degrees\n", "F1_F2=math.cos(theta2*math.pi/180)/math.cos(theta1*math.pi/180)\n", " #As Sigma(Fy)=0\n", "F3=400 #units in Newtons\n", "F2=round((F3*math.cos(theta1*math.pi/180))/(math.cos(theta1*math.pi/180)**2+math.cos(theta2*math.pi/180)**2)) #units in Newtons\n", "F1=(math.cos(theta2*math.pi/180)/math.cos(theta1*math.pi/180))*F2 #units in Newtons\n", "print \"Tension in string 1 is F1=\",round(F1),\" N\\n\"\n", "print \"Tension in string 2 is F2=\",round(F2),\" N\\n\"\n", " #In textbook the Answer for F2 is printed wrong as 320 N But the correct answer is 319 N\n" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Ex2.3:pg-42" ] }, { "cell_type": "code", "execution_count": 3, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "The Weight W= 133.0 N\n", "\n", "Tension in the chord is F= 166.0 N\n" ] } ], "source": [ " #Example 2_3\n", "\n", "\n", " #To find the weight and the Tension in the cords\n", " #As Sigma(Fx)=0\n", "theta1=53 #units in degrees\n", "theta2=37 #units in degrees\n", "F1=100 #units in Newtons\n", "F=F1/math.cos(theta1*math.pi/180) #units in Newtons\n", "W=math.cos(theta2*math.pi/180)*F #units in Newtons\n", "print \"The Weight W=\",round(W),\" N\\n\"\n", "print \"Tension in the chord is F=\",round(F),\" N\"\n", " #In text book the answers are printed wrong as F=167N and W=133N but the correct answers are W=132N and F=166N\n" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Ex2.5:pg-48" ] }, { "cell_type": "code", "execution_count": 4, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Tension in the Supporting Cable T= 2309.0 N\n" ] } ], "source": [ " #Example 2_5\n", "\n", "\n", " #To find the Tension T in the Supporting Cable\n", " #As Sigma(Fx)=0\n", "theta1=30 #units in degrees\n", "theta2=90-theta1 #units in degrees\n", "H_T=math.sin(theta1*math.pi/180)\n", "W=2000 #Units in Newtons\n", "T=W/math.sin(theta2*math.pi/180) #units in Newtons\n", "H=T*H_T #units in Newtons\n", "print \"Tension in the Supporting Cable T=\",round(T),\" N\"\n", " #In textbook The answer is printed wrong as T=2310N but the correct answer is T=2309N\n" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Ex2.6:pg-52" ] }, { "cell_type": "code", "execution_count": 5, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "The First Force F1= -1800.0 N\n", "\n", "The Second Force F2= 2700.0 N\n", "\n" ] } ], "source": [ " #Example 2_6\n", "\n", "\n", " #To find the forces exerted bythe pedestals on the board\n", "tou=900 #units in Newtons\n", "d1=3 #units in Meters\n", "d2=1.5 #Units in Meters\n", "F1=-(tou*d1)/d2 #Units in Newtons\n", "F2=tou-F1 #units in Newtons\n", "print \"The First Force F1=\",round(F1),\" N\\n\"\n", "print \"The Second Force F2=\",round(F2),\" N\\n\"\n" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Ex2.7:pg-53" ] }, { "cell_type": "code", "execution_count": 6, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Tension T= 291.0 N\n", "\n", "H= 232.0 N\n", "\n", "V= -25.13 N\n" ] } ], "source": [ " #Example 2_7\n", "\n", "\n", " #To find tension in the supporting cable and Components of the force exerted by the hinge\n", "F1=50 #units in Newtons\n", "d1=0.7 #units in meters\n", "F2=100 #units in Newtons\n", "d2=1.4 #units in meters\n", "d3=1 #units in meters\n", "theta2=53 #units in degrees\n", "T=round(((F1*d1)+(F2*d2))/(d3*math.cos(theta2*math.pi/180))) #units in Newtons\n", "theta1=37 #units in degrees\n", "H=math.cos(theta1*math.pi/180)*T #units in Newtons\n", "\n", "V=F1+F2-(math.cos(theta2*math.pi/180)*T) #units in Newtons\n", "print \"Tension T=\",round(T),\" N\\n\"\n", "print \"H=\",round(H),\" N\\n\"\n", "print \"V=\",round(V,2),\" N\"\n", " #In text book the answer is printed wrong as H=234N but the correct answer is H=232N\n" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Ex2.8:pg-55" ] }, { "cell_type": "code", "execution_count": 7, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Tension T= 410.0 N\n", "\n", "H= 140.0 N\n", "\n", "V= -301.0 N\n" ] } ], "source": [ " #Example 2_8\n", "\n", "\n", " #To find the tension in the Muscle and the Component Forces at elbow\n", "F1=65 #units in Newtons\n", "d1=0.1 #units in Meters\n", "F2=20 #Units in Newtons\n", "d2=0.35 #units in meters\n", "theta1=20 #units in degrees\n", "d3=0.035 #units in Meters\n", "Tm=((F1*d1)+(F2*d2))/(math.cos(theta1*math.pi/180)*d3) #units in Newtons\n", "V=F1+F2-(Tm*math.cos(theta1*math.pi/180))\n", "H=Tm*math.sin(theta1*math.pi/180)\n", "print \"Tension T=\",round(Tm),\" N\\n\"\n", "print \"H=\",round(H),\" N\\n\"\n", "print \"V=\",round(V),\" N\"\n" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Ex2.9:pg-55" ] }, { "cell_type": "code", "execution_count": 10, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Force P= 276.0 N\n", "\n", "Force V= 600.0 N\n", "\n", "Force H= 276.0 N\n" ] } ], "source": [ " #Example 2_9\n", "\n", "\n", "#To find the forces at the wall and the ground\n", "theta1=53 #units in degrees\n", "d1=3 #units in meters\n", "F1=200 #units in Newtons\n", "d2=4 #units in Meters\n", "F2=400 #units in Newtons\n", "theta2=37 #units in degrees\n", "d3=6 #units in meters\n", "P=((math.cos(theta1*math.pi/180)*d1*F1)+(math.cos(theta1*math.pi/180)*d2*F2))/(math.cos(theta2*math.pi/180)*d3) #units in Newtons\n", "H=P #units in Newtons\n", "V=F1+F2 #units in Newtons\n", "print \"Force P=\",round(P),\" N\\n\"\n", "print \"Force V=\",round(V),\" N\\n\"\n", "print \"Force H=\",round(H),\" N\"\n", " #In text book the answer is printed wrong as P=H=275N but the correct answer is P=H=276N\n" ] } ], "metadata": { "kernelspec": { "display_name": "Python 2", "language": "python", "name": "python2" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 2 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython2", "version": "2.7.11" } }, "nbformat": 4, "nbformat_minor": 0 }