{
"metadata": {
"name": "",
"signature": "sha256:c6d905c981cd31d9d5ba9137cf0938aeaccbb0b1cd83275a36f68b061bf96083"
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 10: Gases and the Kinetic Theory"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex10.1:pg-288"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" #Example 10_1\n",
" \n",
" #To find out the pressure in Lungs\n",
"h=6 #units in cm Hg\n",
"Pa=76 #Units in cm Hg\n",
"Pl=(h+Pa) #units in cm Hg\n",
"\n",
"Pl=Pl*10**-2 #units in Meters Hg\n",
"g=9.8 #Units in Meters/cm**2\n",
"H=13600 #Constant \n",
"Pl=Pl*H*g #Units in Pa\n",
"print \"The pressure in the lungs is Pl=\",round(Pl,1),\" Pa\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The pressure in the lungs is Pl= 109289.6 Pa\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex10.2:pg-288"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" #Example 10_2\n",
" \n",
" \n",
" #To find the mass of copper atom\n",
"maa=63.5 #Units in Kgs\n",
"n=6.022*10**26 #Units in number of atoms\n",
"Mass=maa/n #units in Kg/atom\n",
"print \"The Mass per atom is=\",round(Mass,28),\"Kg/Atom\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The Mass per atom is= 1.054e-25 Kg/Atom\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex10.3:pg-289"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" #Example 10_3\n",
" \n",
" \n",
" #To find te volume associted with mercury atom in liquid mercury\n",
"M=201.0 #Units in Kg/Kmol\n",
"n=6.02*10**26 #units in K mol**-2\n",
"mo=M/n #units in Kg\n",
"n1=13600.0 #units in Kg/Meter**3\n",
"noatoms=n1/mo #units in atoms/Meter**3\n",
"volume_atom=1/noatoms #units in Meter**3/Atom\n",
"print \"The volume associated is \",round(volume_atom,31),\"Meter**3/Atom\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The volume associated is 2.46e-29 Meter**3/Atom\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex10.4:pg-289"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" #Example 10_4\n",
" \n",
" \n",
" #To find the volume that one kilomole of an ideal gas occupies\n",
"p=1.013*10**5 #units in Pa\n",
"t=273.15 #units in K\n",
"n=1 #units in K mol\n",
"R=8314 #units in J/Kmol K\n",
"v=(n*R*t)/p #units in Meter**3/Kmol\n",
"print \"Volume occupied is V=\",round(v,1),\" Meter**3/Kmol\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Volume occupied is V= 22.4 Meter**3/Kmol\n"
]
}
],
"prompt_number": 10
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex10.5:pg-290"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" #Example 10_5\n",
" \n",
" \n",
" #To find the gas pressure in the container\n",
"v=5*10**-3 #units in meter**3\n",
"t=300.0 #units in K\n",
"m1=14*10**-6 #Units in Kg\n",
"M=28 #Units in Kg/Kmol \n",
"n=m1/M #units in K mol\n",
"R=8314 #units in J/Kmol K\n",
"p=(n*R*t)/v #units in Meter**3/Kmol\n",
"print \"The pressure in the container is P=\",round(p),\" Pa\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The pressure in the container is P= 249.0 Pa\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex10.6:pg-291"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" #Example 10_6\n",
" \n",
" \n",
" #To determine the mass of the air in flask\n",
"p=1.013*10**5 #Units in Pa\n",
"v=50*10**-6 #Units in meter**3\n",
"M=28.0 #Units in Kg/Mol\n",
"R=8314.0 #units in J/Kmol K\n",
"T=293 #units in K\n",
"m=(p*v*M)/(R*T) #Units in Kg\n",
"print \"The mass of air in flask is=\",round(m,7),\"Kg\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The mass of air in flask is= 5.82e-05 Kg\n"
]
}
],
"prompt_number": 16
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex10.7:pg-292"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" #Example 10_7\n",
" \n",
" \n",
" #To find out the final pressure in the drum\n",
"p1=1 #Units in atm\n",
"t2=333.0 #units in K\n",
"t1=293.0 #units in K\n",
"p2=p1*(t2/t1) #units in atm\n",
"print \"The final pressure in the drum is P2=\",round(p2,2),\" atm\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The final pressure in the drum is P2= 1.14 atm\n"
]
}
],
"prompt_number": 17
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex10.8:pg-292"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" #Example 10_8\n",
" \n",
" \n",
" #To find the final volume of gas\n",
"\n",
"t1=27.0 #Units in Centigrade\n",
"t1=t1+273 #Units in Kelvin\n",
"t2=547.0 #Units in Centigrade\n",
"t2=t2+273 #Units in Kelvin\n",
"t1=27.0 #Units in Centigrade\n",
"t1=t1+273 #Units in Kelvin\n",
"t1=27.0 #Units in Centigrade\n",
"t1=t1+273 #Units in Kelvin\n",
"p2=3700.0 #units in cm Hg\n",
"p1=74.0 #units in cm Hg\n",
"v1_v2=1/((t1/t2)*(p2/p1)) #In terms of V1\n",
"print \"The final volume of gas in terms of original volume is V2=\",round(v1_v2,5),\"*V1\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The final volume of gas in terms of original volume is V2= 0.05467 *V1\n"
]
}
],
"prompt_number": 19
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex10.9:pg-293"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" #Example 10_9\n",
" \n",
" \n",
" #To find the pressure after the car has been driven at high speed\n",
"t2=308 #Units in K\n",
"t1=273.0 #Units in K\n",
"p2_p1=(t2)/t1 #In terms of P1\n",
"P1=190.0 #Units in K Pa \n",
"P2=101 #Units in K Pa \n",
"P2=p2_p1*(P1+P2) #Units in K Pa \n",
"print \"The Final pressure is P2=\",round(P2),\" K Pa\" \n",
" #In text book the answer is printed wrong as P2=329 K Pa but the correct answer is 328 K Pa \n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The Final pressure is P2= 328.0 K Pa\n"
]
}
],
"prompt_number": 20
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex10.10:pg-294"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
" #Example 10_10\n",
"\n",
"import math\n",
" \n",
" #To findout how fast the nitrogen molecule moving in air\n",
"M=28.0 #Units in Kg/Mol\n",
"Na=6.02*10**26 #Units in K mol**-1\n",
"mo=M/Na #Units in Kg\n",
"k=1.38*10**-23 #units in J/K\n",
"T=27+273.0 #Units in K\n",
"v2=(3*k*T)/mo #unit in Meter**2/Sec**2\n",
"v=math.sqrt(v2) #Units in meter/sec\n",
"print \"The nitrogen molecule goes at a speed of V=\",round(v),\" meter/sec\"\n",
" #In text book the answer is printed wrong as v=517 m/sec the correct answer is v=516 meter/ sec\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The nitrogen molecule goes at a speed of V= 517.0 meter/sec\n"
]
}
],
"prompt_number": 21
}
],
"metadata": {}
}
]
}