{ "metadata": { "name": "", "signature": "sha256:aac83d9b958acba775304d5e53683242c3be955e852f2ce5dbe2f25d81f3bf36" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 6 FM Circuits" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 6.1 Page no 178" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Given\n", "Vc =40*10**-12\n", "c = 20*10**-12\n", "f0 = 5.5*10**6\n", "Ct = Vc+c\n", "\n", "#Calculation\n", "L = 1/((6.28*f0)**2*Ct)\n", "\n", "#Result\n", "print\"The value of the inductance is \",round(L*10**6,0),\"microhenry\"\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The value of the inductance is 14.0 microhenry\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 6.2 Page no 186" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Given\n", "f=168.96*10**6\n", "multiplier=24.0\n", "deviation = 5*10**3\n", "fm = 2.8*10**3\n", "\n", "#Calculation\n", "f0 =f/multiplier\n", "fd= deviation/multiplier\n", "phaseshift = fd/fm\n", "phaseshift_degrees = phaseshift*57.3\n", "total_phaseshift =2*phaseshift_degrees\n", "\n", "#Result\n", "print\"(a) The crystal oscillator frequency is \",f0/10**6,\"MHz\"\n", "print\"(b) The total phase shift is \",round(total_phaseshift,3),\"degree\"\n", "\n", "\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "(a) The crystal oscillator frequency is 7.04 MHz\n", "(b) The total phase shift is 8.527 degree\n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 6.3 Page no 187" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Given\n", "R =1*10**3\n", "phaseshift =4.263\n", "phaseshift_center= 45\n", "f =7.04*10**6\n", "\n", "#Calculation\n", "phase_l = phaseshift_center - phaseshift\n", "phase_u = phaseshift_center + phaseshift\n", "phaserange_total = phase_u - phase_l\n", "Xc1 = 1161\n", "C1 = 1/(6.28*f*Xc1)\n", "Xc2 = 861\n", "C2 = 1/(6.28*f*Xc2)\n", "\n", "#Result\n", "print\"The two values of the capacitance to achieve total deviation are \",round(C1*10**12,1),\"pf to\",round(C2*10**12,1),\"pf\"\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The two values of the capacitance to achieve total deviation are 19.5 pf to 26.3 pf\n" ] } ], "prompt_number": 5 } ], "metadata": {} } ] }