{ "metadata": { "name": "", "signature": "sha256:163d017a43636b203253208922a2be0b72d9894b37f4d97c9da43a5e9b39c875" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 7 - Gases and Introductory stastical thermodynamics" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 2 - pg 192" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#calculate the Gas constant\n", "#Initialization of variables\n", "h=76. #cm\n", "d=13.5951 #g/cc\n", "g=980.655 #cm/s^2\n", "T=273.15 #K\n", "v=22414.6 #cm^3 /mol\n", "#calculations\n", "P=h*d*g\n", "R=P*v/(T)\n", "#results\n", "print '%s %.3e %s' %(\"Gas constant =\",R,\"ergs/deg. mol\")\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Gas constant = 8.315e+07 ergs/deg. mol\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 3 - pg 192" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#calculate the R value in calories\n", "#Initialization of variables\n", "cal=4.184*10**7 #ergs\n", "R=8.315*10**7 #ergs/deg/mol\n", "#calculations\n", "Rdash=R/cal\n", "#results\n", "print '%s %.3f %s' %(\"R in calories =\",Rdash,\" cal/ deg mol\")\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "R in calories = 1.987 cal/ deg mol\n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 4 - pg 192" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#calculate the root mean square velocity\n", "#Initialization of variables\n", "import math\n", "from math import sqrt\n", "R=8.315*10**7 #ergs/deg/mol\n", "T=273.2 #deg\n", "M=4 #g/mol\n", "#calculations\n", "u2=3*T*R/M\n", "u=sqrt(u2)\n", "#results\n", "print '%s %.2e %s' %(\"root mean square velocity =\",u,\" cm/sec\")\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "root mean square velocity = 1.31e+05 cm/sec\n" ] } ], "prompt_number": 3 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 5 - pg 194" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#calculate the Partial pressure of N2, O2 and CO2\n", "#Initialization of variables\n", "n1=2.\n", "n2=10.\n", "n3=3.\n", "P=720. #mm of Hg\n", "#calculations\n", "n=n1+n2+n3\n", "x1=n1/n\n", "P1=x1*P\n", "x2=n2/n\n", "P2=x2*P\n", "x3=n3/n\n", "P3=x3*P\n", "#results\n", "print '%s %d %s' %(\"\\n Partial pressure of N2 =\",P1,\"mm\")\n", "print '%s %d %s' %(\"\\n Partial pressure of O2 =\",P2,\" mm\")\n", "print '%s %d %s' %(\"\\n Partial pressure of CO2 =\",P3,\"mm\")\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "\n", " Partial pressure of N2 = 96 mm\n", "\n", " Partial pressure of O2 = 480 mm\n", "\n", " Partial pressure of CO2 = 144 mm\n" ] } ], "prompt_number": 4 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 6 - pg 197" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#calculate the Total energy\n", "#Initialization of variables\n", "T=273.2+25 #K\n", "n=1 #mol\n", "R=1.987 #cal/deg mol\n", "#calculations\n", "Etr=1.5*n*R*T\n", "Erot=1.5*n*R*T\n", "Evib=0\n", "Eel=0\n", "Etot=Etr+Erot+Evib+Eel\n", "#results\n", "print '%s %d %s' %(\"Total energy =\",Etot,\"cal\")\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Total energy = 1777 cal\n" ] } ], "prompt_number": 5 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 7 - pg 199" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#calculate the Molecular diameter of He\n", "#Initialization of variables'\n", "import math\n", "b=24.1 #cm^2/mol\n", "N=6.023*10**23 #mole^-1\n", "#calculations\n", "d=(3*b/(2*math.pi*N))**(1./3)\n", "#results\n", "print '%s %.2e %s' %(\"Molecular diameter of He =\",d,\" cm\")\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Molecular diameter of He = 2.67e-08 cm\n" ] } ], "prompt_number": 6 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 8 - pg 205" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#calculate the Volume\n", "#Initialization of variables\n", "P=100. #atm\n", "T=200. #K\n", "n=1. #mole\n", "R=0.08206 #l atm/deg mol\n", "print \"From psychrometric charts,\"\n", "Tc=126.2 #K\n", "Pc=33.5 #K\n", "#calculations\n", "Pr=P/Pc\n", "Tr=T/Tc\n", "print \"From z charts,\"\n", "z=0.83\n", "V=z*n*R*T/P\n", "#results\n", "print '%s %.3f %s' %(\"Volume =\",V,\" liter\")\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "From psychrometric charts,\n", "From z charts,\n", "Volume = 0.136 liter\n" ] } ], "prompt_number": 7 } ], "metadata": {} } ] }