{
"metadata": {
"name": "",
"signature": "sha256:eb16b5620fb956842995f8d06be59d7e1e1d7123054fdad5a84f667167801f94"
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 8: Differential, Instrumentation and Bridge amplifiers"
]
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 8.1 Page No 218"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"m = 100.0 #Differential Gain\n",
"E1 = 10*10**-3\n",
"E2 = 10*10**-3 #input voltages\n",
"E3 = 0*10**-3 \n",
"E4 = -20*10**-3 #input voltages\n",
"\n",
"#Calculation\n",
"Vout1 = (m*E1)-(m*E2) \n",
"Vout2 = (m*E1)-(m*E3)\n",
"Vout3 = (m*E1)-(m*E4)\n",
"\n",
"#Result\n",
"print\" Output Voltages are \", Vout1,\"V, \",Vout2,\"V ,\",Vout3,\"V\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" Output Voltages are 0.0 V, 1.0 V , 3.0 V\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 8.2 Page no. 220"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"V=5 #V\n",
"d=2 #mV\n",
"E1=V+d*10**-3\n",
"E2=V-d*10**-3\n",
"\n",
"#Calculation\n",
"Eds=E1-E2\n",
"Ecm=(E1+E2)/2.0\n",
"\n",
"#Result\n",
"print\"Input signal voltage is\",Eds*1000,\"mV\"\n",
"print\"Common mode voltage is\",Ecm,\"V\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Input signal voltage is 4.0 mV\n",
"Common mode voltage is 5.0 V\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 8.2 Page No 225"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"a = 2/9.0 #Differential Gain\n",
"E1 = 10*10**-3\n",
"E2 = 5*10**-3 #Input Voltages \n",
"\n",
"#Calculation\n",
"Vout = (E1 - E2)*(1+(2/a))\n",
"\n",
"#Result\n",
"print\" output voltage = \", Vout*1000,\"mV\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" output voltage = 50.0 mV\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 8.3 Page No 227"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"R = 25*10**3 \n",
"aR = 50.0 \n",
"\n",
"#Calculation\n",
"a = aR / R \n",
"Gain = 1 + (2/a) \n",
"\n",
"#Result\n",
"print\"Voltage Gain = \" , Gain "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Voltage Gain = 1001.0\n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 8.4 Page No 227"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"import numpy\n",
"a=numpy.inf\n",
"\n",
"#Calculation\n",
"Gain = 1+(2/a) \n",
"\n",
"#Result\n",
"print\" Voltage Gain = \", Gain"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" Voltage Gain = 1.0\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 8.5 Page No 227"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"m = 1001.0 #Gain\n",
"E1 = 5.001\n",
"E2 = 5.002\n",
"E3 = 5.001 \n",
"E4 = 5.000 \n",
"E5 = -1.001 \n",
"E6 = -1.002 \n",
"\n",
"#Calculation\n",
"Vout1 = m*(E1-E2)\n",
"Vout2 = m*(E3-E4) \n",
"Vout3 = m*(E5-E6)\n",
"\n",
"#result\n",
"print\" Output Voltages are \", Vout1,\"V \",Vout2,\"V \",Vout3,\"V\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" Output Voltages are -1.001 V 1.001 V 1.001 V\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 8.6 Page No 231"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"Vout = 5.0 #Output Voltage\n",
"\n",
"#Calculation\n",
"Vce = Vout \n",
"\n",
"#Result\n",
"print\" Vce=\",Vce,\"V\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" Vce= 5.0 V\n"
]
}
],
"prompt_number": 10
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 8.7 Page No 231"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"Vre = 1.2 \n",
"Re = 1*10**3 \n",
"Vce = 5\n",
"Vcc = 15 #Voltages in the circuit\n",
"\n",
"#Calculation\n",
"Ie = Vre / Re \n",
"Vcol = Vce + Vre \n",
"Vrl = Vcc - Vcol \n",
"\n",
"#Result\n",
"print\" Collector Voltage = \", Vcol,\"V\"\n",
"print\" Voltage across Rl =\", Vrl,\"V\"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" Collector Voltage = 6.2 V\n",
" Voltage across Rl = 8.8 V\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 8.8 Page No 232"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"Rs = 1*10**3\n",
"E1 = 100*10**-3 \n",
"E2 = 0 \n",
"Rl = 5*10**3 \n",
"Gain = 10 \n",
"\n",
"#Calculation\n",
"Il = 10*((E1-E2)/Rs)\n",
"Vr = Il * Rs \n",
"Vref = Il * Rl \n",
"V9 = Vref + Gain*(E1 - E2)\n",
"\n",
"#Result\n",
"print\" Current across Load Resistor = \", Il*1000 ,\"mA\"\n",
"print\" Voltage across R = \", Vr,\"V\"\n",
"print\" Reference Voltage = \", Vref,\"V\" \n",
"print\" Voltage at terminal 9 =\", V9,\"V\" "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" Current across Load Resistor = 1.0 mA\n",
" Voltage across R = 1.0 V\n",
" Reference Voltage = 5.0 V\n",
" Voltage at terminal 9 = 6.0 V\n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 8.9 Page No 234"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"GF = 2.0 #Gage factor\n",
"DR = 0.001 \n",
"R = 120.0 \n",
"\n",
"#calculation\n",
"L = DR /(R*GF) \n",
"\n",
"#result\n",
"print\" Change in length is \",round(L*10**6,1),\"microinches per inch\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" Change in length is 4.2 microinches per inch\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 8.10 Page No 236"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"E = 1.0 \n",
"DR = 0.001 \n",
"R = 120.0 #Resistance in Ohm\n",
"\n",
"#Calculation\n",
"Vout = (E*DR)/(4*R) \n",
"\n",
"#Result\n",
"print\" Output of the Bridge = \", round(Vout*10**6,1),\"micro voltage\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" Output of the Bridge = 2.1 micro voltage\n"
]
}
],
"prompt_number": 10
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 8.11 Page No 241"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"Vout = 100*10**-3 \n",
"E = 5.0\n",
"R = 120.0 \n",
"Gain = 1000.0 \n",
"E1 = 30 *10**6 \n",
"Gf = 2.0 #Gage factor\n",
"\n",
"#calculation\n",
"Vbridge = Vout / Gain \n",
"DL = 20*10**-6 \n",
"DR = (R * Vbridge)/E \n",
"Rratio = DR / R #Change in Resistance\n",
"Strain = DL / Gf #Change in Length \n",
"Stress = E1 * Strain \n",
"\n",
"#Result\n",
"print \" Change in Resistance = \", DR*1000 ,\"mohm\"\n",
"print \" Ratio of Resistance = \", Rratio,\"micro ohm/ohm\"\n",
"print \" Strain value = \", Strain ,\"micro inch/inch\"\n",
"print \" Stress value = \", Stress ,\"psi\""
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" Change in Resistance = 2.4 mohm\n",
" Ratio of Resistance = 2e-05 micro ohm/ohm\n",
" Strain value = 1e-05 micro inch/inch\n",
" Stress value = 300.0 psi\n"
]
}
],
"prompt_number": 12
},
{
"cell_type": "heading",
"level": 3,
"metadata": {},
"source": [
"Example 8.12 Page No 245\n"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Given\n",
"T1=25 #C Temprature\n",
"T2=50\n",
"Tref=25 #C Reference temprature\n",
"Rref=10000\n",
"Rtrans=3603 #ohm, at 50 C\n",
"\n",
"\n",
"#Calculation\n",
"dR=Rtrans-Rref\n",
"R1=10 #Kohm say\n",
"E=1 #V trial choice\n",
"I=E/(R1+Rref/1000.0)\n",
"Vo=-I*dR\n",
"\n",
"#result\n",
"print\"The value of dR for each temprature is\",dR,\"ohm\"\n",
"print\"The current is\",I,\"mA\"\n",
"print\"Vo for each value of R\",Vo,\"mV\"\n",
"#NOTE: In the book the value of Vo is calculated wrong"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of dR for each temprature is -6397 ohm\n",
"The current is 0.05 mA\n",
"Vo for each value of R 319.85 mV\n"
]
}
],
"prompt_number": 2
}
],
"metadata": {}
}
]
}