{ "metadata": { "name": "", "signature": "sha256:f65433b5fc699d555a8e1a0c197fcc95a6db55a338dffc279c90983fdf767b28" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapte16-Chemical &Biological Effects of Radiations" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex1-pg672" ] }, { "cell_type": "code", "collapsed": false, "input": [ "## Exa16.1 : : Page-672 (2011)\n", "#find 25 mrad\n", "import math\n", "R_d = 25.; ## Radiation dose, milli rad\n", "R_c_gy = 25e-03; ## Dose in centigray\n", "R_Sv = 25*10**-2 ## Dose in milli sieverts\n", "print'%s %.2f %s %.2f %s'%(\"\\n25 mrad = \",R_c_gy,\"\" and \" cGy =\",R_Sv,\" mSv\");\n", "\n", "## Results\n", "## 25 mrad = 3e-002 cGy = 0.25 mSv " ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "\n", "25 mrad = 0.03 0.25 mSv\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex2-pg673" ] }, { "cell_type": "code", "collapsed": false, "input": [ "## Exa16.2 : : Page-673 (2011)\n", "#find 100 mega becquerel\n", "import math\n", "BC_conv = 100*1e+009/3.7e+10; ## Becquerel curie conversion, milli curie\n", "print'%s %.2f %s'%(\"\\n100 mega becquerel = \",BC_conv,\" milli curie \")\n", "\n", "## Results\n", "## 100 mega becquerel = 2.7 milli curie " ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "\n", "100 mega becquerel = 2.70 milli curie \n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Ex4-pg673" ] }, { "cell_type": "code", "collapsed": false, "input": [ "## Exa16.4 : : Page-673 (2011)\n", "#find The requiresd liver dose \n", "import math\n", "A = 80*10**6; ## Activity, becquerel\n", "t_half = 6*3600.; ## Half life, s\n", "N = A*t_half/0.693; ## Number of surviving radionuclei\n", "E_released = 0.9*N*(140e+03)*1.6e-19; ## Energy released, joule\n", "m_l = 1.8; ## Mass of liver of average man, Kg\n", "liv_dose = E_released*10**2/m_l; ## Liver dose, centigray\n", "print'%s %.2f %s'%(\"\\nThe requiresd liver dose = \",liv_dose,\" cGy\");\n", "\n", "## Result\n", "## The requiresd liver dose = 2.8 cGy \n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "\n", "The requiresd liver dose = 2.79 cGy\n" ] } ], "prompt_number": 3 } ], "metadata": {} } ] }