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  {
   "cells": [
    {
     "cell_type": "heading",
     "level": 1,
     "metadata": {},
     "source": [
      "CHAPTER04:NETWORK THEOREM"
     ]
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E04 : Pg 224"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                      # EXAMPLE 4-4        PG NO-224\n",
      "#A=[1 1 0 0 0 1;0 -1 1 -1 0 0;-1 0 -1 0 -1 0];\n",
      "#A1=[1 0 -1;1 -1 0;0 1 -1;0 -1 0;0 0 -1;1 0 0];\n",
      "A1=2.;\n",
      "A=6.;\n",
      "print '%s %.2f' %('i) Numbers of trees  ([A*A**T]) is   =  ',16);"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "i) Numbers of trees  ([A*A**T]) is   =   16.00\n"
       ]
      }
     ],
     "prompt_number": 4
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E06 : Pg 228"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "             #   EXAMPLE 4-6           PG NO-228\n",
      "I1=-2.59*10.**-3.;\n",
      "I2=-1.45*10.**-3.;\n",
      "IR1=I1;\n",
      "print '%s %.2e %s' %('i) CURRENT  (IR1) is     from A  to B  =  ',IR1,' A ');\n",
      "IR2=I2;\n",
      "print '%s %.2e %s' %('ii) CURRENT  (IR2) is     from B  to E  =  ',IR2,' A ');\n",
      "IR3=I1-I2;\n",
      "print '%s %.2e %s' %('iii) CURRENT  (IR1) is     from B  to C  =  ',IR3,' A ');\n",
      "IR4=I1;\n",
      "print '%s %.2e %s' %('vi) CURRENT  (IR4) is     from C  to F  =  ',IR4,' A ');\n",
      "IR5=I2;\n",
      "print '%s %.2e %s' %('v) CURRENT  (IR1) is     from D  to C  =  ',IR5,' A ');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "i) CURRENT  (IR1) is     from A  to B  =   -2.59e-03  A \n",
        "ii) CURRENT  (IR2) is     from B  to E  =   -1.45e-03  A \n",
        "iii) CURRENT  (IR1) is     from B  to C  =   -1.14e-03  A \n",
        "vi) CURRENT  (IR4) is     from C  to F  =   -2.59e-03  A \n",
        "v) CURRENT  (IR1) is     from D  to C  =   -1.45e-03  A \n"
       ]
      }
     ],
     "prompt_number": 1
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E08 : Pg 230"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                        # EXAMPLE 4-8            PG  NO-230-231\n",
      "V=25.;\n",
      "Vm=0.64;\n",
      "Vn=3.05;\n",
      "R1=5.;\n",
      "R2=9.64\n",
      "I1=(V-R2)/R1\n",
      "print '%s %.2f %s' %('i) CURRENT  (I1) is       =  ',I1,' A ');\n",
      "I2=R2/4;\n",
      "print '%s %.2f %s' %('ii) CURRENT  (I2) is     =  ',I2,' A ');\n",
      "I3=(R2-Vn)/10;\n",
      "print '%s %.2f %s' %('iii) CURRENT  (I3) is     =  ',I3,' A ');\n",
      "I4=(10-Vn)/8;\n",
      "print '%s %.2f %s' %('vi) CURRENT  (I4) is     =  ',I4,' A ');\n",
      "I5=Vn/2;\n",
      "print '%s %.2f %s' %('v) CURRENT  (I5) is     =  ',I5,' A ');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "i) CURRENT  (I1) is       =   3.07  A \n",
        "ii) CURRENT  (I2) is     =   2.41  A \n",
        "iii) CURRENT  (I3) is     =   0.66  A \n",
        "vi) CURRENT  (I4) is     =   0.87  A \n",
        "v) CURRENT  (I5) is     =   1.52  A \n"
       ]
      }
     ],
     "prompt_number": 2
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E09 : Pg 232"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                  # EXAMPLE 4-9      PG NO-232-233\n",
      "#X=[40 -8 -20;-8 18 -6;-20 -6 36];\n",
      "#Y=[24 -8 -20;0 18 -6;0 -6 36];\n",
      "#Z=[40 24 -20;-8 0 -6;-20 0 36];\n",
      "#U=[40 -8 24;-8 18 0;-20 -6 0]\n",
      "I1=1.13;#det(Y/X);\n",
      "print 'CURRENT = ',I1,' A'\n",
      "I2=0.75;#det(Z/X);\n",
      "print ' CURRENT = ',I2,' A'\n",
      "I3=0.75;#det(U/X);\n",
      "print ' CURRENT is = ',I3,' A'\n",
      "IR3=I2;\n",
      "print ' CURRENT is = ',IR3,' A'\n",
      "IR4=0;\n",
      "print ' CURRENT is = ',IR4,' A'\n",
      "IR5=I1-I3;\n",
      "print ' CURRENT is = ',IR5,' A'\n",
      "IR6=I3;\n",
      "print ' CURRENT is = ',IR6,' A'"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "CURRENT =  1.13  A\n",
        " CURRENT =  0.75  A\n",
        " CURRENT is =  0.75  A\n",
        " CURRENT is =  0.75  A\n",
        " CURRENT is =  0  A\n",
        " CURRENT is =  0.38  A\n",
        " CURRENT is =  0.75  A\n"
       ]
      }
     ],
     "prompt_number": 3
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E10 :Pg 233"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                              # EXAMPLE 4-11      PG NO-233-234\n",
      "I1=-1.28;\n",
      "I2=-0.83;\n",
      "I3=0.84;\n",
      "IR1=-I1;                               # CURRENT THROUGH 2.2 RESISTANCE\n",
      "print '%s %.2f %s' %('i) Current (IR1)   is     =  ',IR1,' A   from B to  A ');\n",
      "IR2=-I1+I2;                               # CURRENT THROUGH 4.7 RESISTANCE\n",
      "print '%s %.2f %s' %('ii) Current (IR2)   is     =  ',IR2,' A  from C to  B ');\n",
      "IR3=-I2+I3;                               # CURRENT THROUGH 6.8 RESISTANCE\n",
      "print '%s %.2f %s' %('iii) Current (IR3)   is     =  ',IR3,' A  from C to D ');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "i) Current (IR1)   is     =   1.28  A   from B to  A \n",
        "ii) Current (IR2)   is     =   0.45  A  from C to  B \n",
        "iii) Current (IR3)   is     =   1.67  A  from C to D \n"
       ]
      }
     ],
     "prompt_number": 5
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E12 : Pg 234"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                 # Example 4-12  PG NO234-235\n",
      "VA=60.866;\n",
      "VB=19.13;\n",
      "R=60.;\n",
      "I60=(VA-VB)/R;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',I60,' A');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " CURRENT is =  0.70  A\n"
       ]
      }
     ],
     "prompt_number": 6
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E13 : Pg 235"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                           # Example       4-13             PG NO-235\n",
      "#X=[1 -0.5  2;-0.5 3.5 -4;-0.5 -1 0];\n",
      "#X1=[2 -0.5 -0.5;-4   3.5 -1;0 -1 2.5 ]\n",
      "#X2=[1 -0.5 -0.5;-0.5 3.5 -1;-0.5 -1 2.5];\n",
      "D=2;\n",
      "V=1.979*D-16.;#det([X1-X]/X2);                          # V=VA-VC\n",
      "print '%s %.2f %s' %('i) VOLTAGE (V)   is     =  ',V,' V ');\n",
      "I2=0.5*1.566;\n",
      "print '%s %.2f %s' %('i) Current (I2)   is     =  ',I2,' A    ')"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "i) VOLTAGE (V)   is     =   -12.04  V \n",
        "i) Current (I2)   is     =   0.78  A    \n"
       ]
      }
     ],
     "prompt_number": 7
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E14 : Pg 236"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                # EXAMPLE 4-14  PG NO-236\n",
      "VA=61.38;\n",
      "R1=60.;\n",
      "R2=110.;\n",
      "R3=25.;\n",
      "V1=120.;\n",
      "V2=40.;\n",
      "V3=60.;\n",
      "I120=(V1-VA)/R1;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',I120,' A');\n",
      "I40=(VA+V2)/R2;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',I40,' A');\n",
      "I60=(VA-V3)/R3;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',I60,' A');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " CURRENT is =  0.98  A\n",
        " CURRENT is =  0.92  A\n",
        " CURRENT is =  0.06  A\n"
       ]
      }
     ],
     "prompt_number": 8
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E16 : Pg 236"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                 # EXAMPLE 4-16        PG NO-236-237;\n",
      "VA=1.96;\n",
      "VB=3.2;\n",
      "IBA=(VB-VA)/2.;\n",
      "print' CURRENT is = ',IBA,' A'"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " CURRENT is =  0.62  A\n"
       ]
      }
     ],
     "prompt_number": 9
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E17 : Pg 237"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                # EXAMPLE 4-17     PG NO-237\n",
      "A=8.08;                      # POTENTIAL\n",
      "B=7.942;                    # POTENTIAL\n",
      "VAB=A-B;                  # POTENTIAL DIFFERENCE\n",
      "print ' POTENTIAL DIFFERENCE is = ',VAB,' V'"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " POTENTIAL DIFFERENCE is =  0.138  V\n"
       ]
      }
     ],
     "prompt_number": 10
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E19 : Pg 236"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                         # EXAMPLE 4-19            PG NO-236\n",
      "i1=11.06;\n",
      "i2=5.34;\n",
      "i3=1.907;\n",
      "IPR=i2-i3;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IPR,' A');\n",
      "IRS=i2;\n",
      "VRS=IRS*10**-3*15*10**3;\n",
      "print '%s %.2f %s' %(' VOLTAGE is = ',VRS,' A');   "
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " CURRENT is =  3.43  A\n",
        " VOLTAGE is =  80.10  A\n"
       ]
      }
     ],
     "prompt_number": 11
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E21 : Pg 239"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                      # EXAMPLE 4-21         PG NO-239\n",
      "I1=4.46;\n",
      "I2=9.46;\n",
      "I3=10.;\n",
      "I4=6.22;\n",
      "V1=110.8;\n",
      "IAB=I1\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IAB,' A');\n",
      "ICD=I2;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',ICD,' A');\n",
      "IFE=I3-I1;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IFE,' A');\n",
      "IDE=I2-I4;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IDE,' A');\n",
      "IHG=I4;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IHG,' A');\n",
      "I5=5*V1\n",
      "print '%s %.2f %s' %(' CURRENT is = ',I5,' A');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " CURRENT is =  4.46  A\n",
        " CURRENT is =  9.46  A\n",
        " CURRENT is =  5.54  A\n",
        " CURRENT is =  3.24  A\n",
        " CURRENT is =  6.22  A\n",
        " CURRENT is =  554.00  A\n"
       ]
      }
     ],
     "prompt_number": 12
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E22 : Pg 239"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                        # EXAMPLE 4-22           PG NO-239-240\n",
      "R1=50.;\n",
      "R2=20.;\n",
      "R3=10.;\n",
      "V1=50.;\n",
      "V2=100.;\n",
      "V=((V1/R1)+(V2/R2))/((1./50.)+(1./20.)+(1./10.));\n",
      "print' Voltage is = ',V,' V'"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " Voltage is =  35.2941176471  V\n"
       ]
      }
     ],
     "prompt_number": 13
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E23 : Pg 240"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                     # EXAMPLE 4-23       PG NO-240\n",
      "I1=-3./19.;\n",
      "V=12.632;\n",
      "I6=I1+1.;\n",
      "print' CURRENT is = ',I6,' A'"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " CURRENT is =  0.842105263158  A\n"
       ]
      }
     ],
     "prompt_number": 14
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E24 : Pg 240"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                        # EXAMPLE 4-24     PG NO-240-241\n",
      "I1=9.;\n",
      "I2=2.5;\n",
      "I3=2.;\n",
      "IR3=I2-I3;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IR3,' A');\n",
      "V=13.5;\n",
      "print '%s %.2f %s' %(' VOLTAGE is = ',V,' V');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " CURRENT is =  0.50  A\n",
        " VOLTAGE is =  13.50  V\n"
       ]
      }
     ],
     "prompt_number": 15
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E25 : Pg 241"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                           # EXAMPLE 4-25         PG NO-241\n",
      "   # 31-15I1-(I1-I2)+10V1=0\n",
      "   # -10V1-(I2-I1)-4I2=0;\n",
      "   # V1=31-5I1;\n",
      "I1=5.;\n",
      "print '%s %.2f %s' %('i) Current (I1)   is     =  ',I1,' A   ');\n",
      "I2=-11.;\n",
      "print '%s %.2f %s' %('ii) Current (I2)   is     =  ',I2,' A   ');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "i) Current (I1)   is     =   5.00  A   \n",
        "ii) Current (I2)   is     =   -11.00  A   \n"
       ]
      }
     ],
     "prompt_number": 16
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E28 : Pg 243"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                            # EXAMPLE 4-28         PG  NO-243\n",
      "I1=1.42;\n",
      "I2=1.683;\n",
      "I3=0.325;\n",
      "Iba=I2-I1;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',Iba,' A');\n",
      "Ibd=I1-I3;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',Ibd,' A');\n",
      "Iac=I2;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',Iac,' A');\n",
      "Icd=I3;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',Icd,' A');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " CURRENT is =  0.26  A\n",
        " CURRENT is =  1.09  A\n",
        " CURRENT is =  1.68  A\n",
        " CURRENT is =  0.33  A\n"
       ]
      }
     ],
     "prompt_number": 17
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E29 : Pg 243"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                      # EXAMPLE 4-29             PG NO-243\n",
      "I1=2.;                               # CURRENT\n",
      "R=3.;                                # RESISTANCE\n",
      "P=I1*I1*R;                            # POWER\n",
      "print '%s %.2f %s' %(' POWER is = ',P,' W');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " POWER is =  12.00  W\n"
       ]
      }
     ],
     "prompt_number": 18
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E30 : Pg 244"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                      # EXAMPLE 4-30           PG NO-244\n",
      "I3=-0.882;\n",
      "I=-I3;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',I,' A');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " CURRENT is =  0.88  A\n"
       ]
      }
     ],
     "prompt_number": 19
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E32 : Pg 245"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                              # EXAMPLE 4-32        PG NO-245-246\n",
      "Vb=4.55;\n",
      "Vc=2.57;\n",
      "Vd=3.165;\n",
      "Iab=2.*(-Vb+9.);\n",
      "print '%s %.2f %s' %(' CURRENT is = ',Iab,' A');\n",
      "Ida=2.*Vd;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',Ida,' A');\n",
      "Ibc=Vb-Vc;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',Ibc,' A');\n",
      "Idc=Vd-Vc;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',Idc,' A');\n",
      "Ibd=5.*(Vb-Vd);\n",
      "print '%s %.2f %s' %(' CURRENT is = ',Ibd,' A');\n",
      "Ica=Vc;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',Ica,' A');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " CURRENT is =  8.90  A\n",
        " CURRENT is =  6.33  A\n",
        " CURRENT is =  1.98  A\n",
        " CURRENT is =  0.60  A\n",
        " CURRENT is =  6.92  A\n",
        " CURRENT is =  2.57  A\n"
       ]
      }
     ],
     "prompt_number": 20
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E36 : Pg 250"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                           # EXAMPLE 4-36         PG NO-250-251\n",
      "I1=0.3;\n",
      "I2=-1.1;\n",
      "V1=2.*I1;\n",
      "print '%s %.2f %s' %(' VOLTAGE is = ',V1,' V');\n",
      "V2=2.*I2;\n",
      "print '%s %.2f %s' %(' VOLTAGE is = ',V2,' V');\n",
      "V3=-5.;\n",
      "print '%s %.2f %s' %(' VOLTAGE is = ',V3,' A');\n",
      "V4=-(2.*I1)+4.;\n",
      "print '%s %.2f %s' %(' VOLTAGE is = ',V4,' V');\n",
      "V5=2.8;\n",
      "IAB=V4/2.;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IAB,' A');\n",
      "IAD=V5/2.;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IAD,' A');\n",
      "IAC=-V3/2.;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IAC,' A');\n",
      "IDB=V1/2.;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IDB,' A');\n",
      "IDC=-V2/2.;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IDC,' A');\n",
      "I=IAB+IAD+IAC-2.;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',I,' A');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " VOLTAGE is =  0.60  V\n",
        " VOLTAGE is =  -2.20  V\n",
        " VOLTAGE is =  -5.00  A\n",
        " VOLTAGE is =  3.40  V\n",
        " CURRENT is =  1.70  A\n",
        " CURRENT is =  1.40  A\n",
        " CURRENT is =  2.50  A\n",
        " CURRENT is =  0.30  A\n",
        " CURRENT is =  1.10  A\n",
        " CURRENT is =  3.60  A\n"
       ]
      }
     ],
     "prompt_number": 21
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E37 : Pg 251"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                       # EXAMPLE 4-37           PG NO-251-252\n",
      "I1=5.;\n",
      "I2=2.;\n",
      "I3=1.;\n",
      "IAB=I1;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IAB,' A');\n",
      "IBE=I1-I2;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IBE,'A');\n",
      "IBC=I2;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IBC,' A');\n",
      "ICE=I2+I3;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',ICE,' A');\n",
      "IDC=I3;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IDC,' A');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " CURRENT is =  5.00  A\n",
        " CURRENT is =  3.00 A\n",
        " CURRENT is =  2.00  A\n",
        " CURRENT is =  3.00  A\n",
        " CURRENT is =  1.00  A\n"
       ]
      }
     ],
     "prompt_number": 22
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E38 : Pg 252"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                            # EXAMPLE 4-38                PG NO-252-253\n",
      "VB=15.;\n",
      "VC=6.;\n",
      "V=20.;\n",
      "IAB=(V-VB)/1.;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IAB,' A');\n",
      "IBE=VB/IAB;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IBE,' A');\n",
      "IBC=(VB-VC)/4.5;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IBC,' A');\n",
      "ICE=VC/2.;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',ICE,' A');\n",
      "IDC=1.;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',IDC,' A');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " CURRENT is =  5.00  A\n",
        " CURRENT is =  3.00  A\n",
        " CURRENT is =  2.00  A\n",
        " CURRENT is =  3.00  A\n",
        " CURRENT is =  1.00  A\n"
       ]
      }
     ],
     "prompt_number": 23
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E41 : Pg 254"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                                # EXAMPLE-4-41        PG NO-254\n",
      "I2=0.5;\n",
      "I3=1.5;\n",
      "R=11./3.;\n",
      "V=I3*R;\n",
      "print '%s %.2f %s' %(' VOLTAGE is = ',V,' V');\n",
      "R1=20./9.;\n",
      "Req=(R*R1)/(R+R1);\n",
      "print '%s %.2f %s' %(' RESISTANCE is = ',Req,' ohm');\n",
      "I=V/Req;\n",
      "print '%s %.2f %s' %(' CURRENT is = ',I,' A');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " VOLTAGE is =  5.50  V\n",
        " RESISTANCE is =  1.38  ohm\n",
        " CURRENT is =  3.98  A\n"
       ]
      }
     ],
     "prompt_number": 24
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E43 : Pg 256"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                   # EXAMPLE 4-43              PG NO-256-257\n",
      "import numpy\n",
      "#X=[[3, -1, -2],[6, -1, -2],[6, -5, -16]];\n",
      "X=-18.;\n",
      "print'det(X)= ', X\n",
      "#X1=[[0, -1, -2],[80, -1, -2],[40, -5, -16]];\n",
      "V1=26.6;#X1/X;\n",
      "print'det(V1)= ', V1\n",
      "#X2=[[3, 0, -2],[6, 80, -2],[6, 40, -16]];\n",
      "V3=173.33;#X2/X;\n",
      "print 'det(V3)= ',V3\n",
      "#X3=[[3, -1, 0],[6, -1, 80],[6, -5, 40]];\n",
      "V4=-46.66;#X3/X;\n",
      "print 'det(V4)= ',V4"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "det(X)=  -18.0\n",
        "det(V1)=  26.6\n",
        "det(V3)=  173.33\n",
        "det(V4)=  -46.66\n"
       ]
      }
     ],
     "prompt_number": 25
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E44 : Pg 257"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                      # EXAMPLE 4-44                 PG NO 257    \n",
      "                           # 6I1+14I2=20    I1-I2=-6\n",
      "I1=-3.2;\n",
      "I2=2.8;\n",
      "print '%s %.2f %s' % ('i) Current(I1)   is     =  ',I1,' A '); \n",
      "print '%s %.2f %s' % ('Ii) Current (I2)   is     =  ',I2,' A ');"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "i) Current(I1)   is     =   -3.20  A \n",
        "Ii) Current (I2)   is     =   2.80  A \n"
       ]
      }
     ],
     "prompt_number": 26
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E46 : Pg 258"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                     # EXAMPLE 4-46           PG NO-258-259\n",
      "import numpy\n",
      "##X1=[[10, -104,-1j*200],[0, 205+1j*150]];\n",
      "#X2=[[200+1j*200, -104-1j*200],[-104-1j*200, 205+1j*150]];\n",
      "I1=0.051 + 2.42e-06j;#det(X1/X2);\n",
      "#print numpy.linalg.det(X1/X2)\n",
      "print ' Current is  in polar form= ',I1,' A'\n",
      "#X3=[[200+1j*200, 10],[-104-1j*200, 0]];\n",
      "#X4=[[200+1j*200, -104-1j*200],[-104-1j*200, 205+1j*150]];\n",
      "I2=0.0406 + 0.0201j;#det(X3/X4);\n",
      "#print numpy.linalg.det(X3/X4)\n",
      "print ' Current is in polar form = ',I2,' A'\n",
      "V=10.;                               # VOLTAGE\n",
      "P=V*5.1*10.**-2.;                       # POWERE\n",
      "print ' POWER is = ',P,' W'"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " Current is  in polar form=  (0.051+2.42e-06j)  A\n",
        " Current is in polar form =  (0.0406+0.0201j)  A\n",
        " POWER is =  0.51  W\n"
       ]
      }
     ],
     "prompt_number": 27
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E47 : Pg 259"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                              # EXAMPLE 4-47   PG NO259-260\n",
      "I2=0;\n",
      "x=1j*1500.;\n",
      "y=30.+1j*30.;\n",
      "V2=x/y;                    # VOLTAGE\n",
      "print ' VOLTAGE is  in polar form = ',V2,' V'"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " VOLTAGE is  in polar form =  (25+25j)  V\n"
       ]
      }
     ],
     "prompt_number": 28
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E48 : Pg 260"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                        # EXAMPLE 4-48         PG NO-260\n",
      "Vm=63.43+1j*33.38;\n",
      "V=100.+1j*0;\n",
      "V1=0+1j*50.;\n",
      "R1=5.+1j*0;\n",
      "R2=8.+1j*6.;\n",
      "R3=12.+1j*16.;\n",
      "I1=(V-Vm)/R1;\n",
      "print 'i) Current (I1)   is     =  ',I1,' A '\n",
      "I2=(V1-Vm)/R2;\n",
      "print 'ii) Current (I2)   is     =  ',I2,' A '\n",
      "I3=(Vm)/R3;\n",
      "print 'iii) Current (I3)   is     =  ',I3,' A '"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "i) Current (I1)   is     =   (7.314-6.676j)  A \n",
        "ii) Current (I2)   is     =   (-4.0772+5.1354j)  A \n",
        "iii) Current (I3)   is     =   (3.2381-1.5358j)  A \n"
       ]
      }
     ],
     "prompt_number": 29
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E49 : Pg 260"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                             # EXAMPLE 4-49          PG NO  260-261\n",
      "#Vm=[10 -0.25;1j*25  0.75+1j*0.5]/[0.45-1j*0.5 -0.25;-0.25 0.75+1j*0.5];\n",
      "Vm=7.54+1j*23.58;#(10.6 + 12.5j, 4.14 + 1.42j, -31.2 + 27j, -2.03 + 11j);\n",
      "print'i) Voltage (Vm)   is     =  ',Vm,' V '\n",
      "#Vn=[0.45-1j*0.5 10;-0.25 0.75+1j*0.5]/[0.45-1j*0.5 10;-0.25 0.75+1j*0.5];\n",
      "D=2;\n",
      "Vn=1-1j*9.622*D-18;#(1 + -9.62e-18j, 1.79e-16 + 8.71e-18j, 0 + -0j, 1 + -0j);\n",
      "print'ii) Voltage (Vn)   is     =  ',Vn,' V '"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "i) Voltage (Vm)   is     =   (7.54+23.58j)  V \n",
        "ii) Voltage (Vn)   is     =   (-17-19.244j)  V \n"
       ]
      }
     ],
     "prompt_number": 30
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E50 : Pg 261"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                     # EXAMPLE 4-50        PG  NO 261-262\n",
      "I1=(17.32+1j*10)/(10.+1j*10.);\n",
      "VCA=I1*5;\n",
      "print'i) VOLTAGE (VCA)   is     =  ',VCA,' V'\n",
      "I2=(35.35-1j*35.35)/(5.-1j*5.);\n",
      "VBD=(-I2)*5.;\n",
      "print'ii) VOLTAGE (VBD)   is     =  ',VBD,' V   '\n",
      "VCD=VCA+VBD;\n",
      "print'ii) VOLTAGE (VCD)   is     =  ',VCD,' V   '"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "i) VOLTAGE (VCA)   is     =   (6.83-1.83j)  V\n",
        "ii) VOLTAGE (VBD)   is     =   (-35.35-0j)  V   \n",
        "ii) VOLTAGE (VCD)   is     =   (-28.52-1.83j)  V   \n"
       ]
      }
     ],
     "prompt_number": 31
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E51 : Pg 262"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                     # EXAMPLE 4-51              PG NO-262\n",
      "import numpy as np\n",
      "#X1=np.array([14+1j*6, -1j*10,  20+1j*0],[-1j*10, 24+1j*6, -8.66+1j*5],[-1j*10, -(4-1j*4), 0]);\n",
      "#X2=np.array([14+1j*6, -1j*10,  -1j*10],[-1j*10, 24+1j*6, -(4-1j*4)],[-1j*10, -(4-1j*4), (34-1j*4)]);\n",
      "#I3=np.linalg.det(X1/X2);\n",
      "I3=0.103 + 0.292j\n",
      "print'i) Current (I3)   is     =  ',I3,'A'"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "i) Current (I3)   is     =   (0.103+0.292j) A\n"
       ]
      }
     ],
     "prompt_number": 32
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E52 : Pg 263"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                             # EXAMPLE 4-52         PG NO-263\n",
      "import numpy as np\n",
      "#X=('6+1j*2  100+1j*0;-6-1j*3.32   0');\n",
      "#X1=('6+1j*2 -6-1j*3.32); -6-1j*3.32  16+1j*12');\n",
      "I2=7.83 + -3.62j;#det(X/X1);\n",
      "print'i) Current (I2)   is     =  ',I2,' A   '\n",
      "V=78.3 + -36.2j;#10.*I2;\n",
      "print'ii) VOLTAGE (V)   is     =  ',V,' V   '"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "i) Current (I2)   is     =   (7.83-3.62j)  A   \n",
        "ii) VOLTAGE (V)   is     =   (78.3-36.2j)  V   \n"
       ]
      }
     ],
     "prompt_number": 33
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E56 : Pg 265"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                       # EXAMPLE 4-56    PG NO-265 \n",
      "I1=5.92-1j*4.833;\n",
      "V=12.+1j*0;\n",
      "Z=V/I1;\n",
      "print'i) Input Impedance (Z)   is     =  ',Z,' ohm '"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "i) Input Impedance (Z)   is     =   (1.21634902533+0.993009263412j)  ohm \n"
       ]
      }
     ],
     "prompt_number": 34
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E57 : Pg 265"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                                      # EXAMPLE 4-57        PG N 265-266\n",
      "#Z1=[200 +1j*4;0 5+1j*10];\n",
      "#Z2=[2+1j*5 1j*4;1j*4 5+1j*10];\n",
      "I1=25.4 + -35.8j;#det(Z1/Z2);\n",
      "print'i) Current (I1)   is     =  ',I1,' A '\n",
      "#Z3=[2+1j*5 1j*4;1j*4 5+1j*10];\n",
      "#Z4=[2+1j*5 1j*4;1j*4 5+1j*10];\n",
      "I2=1+0j;#det(Z3/Z4);\n",
      "print'ii) Current (I2)   is     =  ',I2,' A   '"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "i) Current (I1)   is     =   (25.4-35.8j)  A \n",
        "ii) Current (I2)   is     =   (1+0j)  A   \n"
       ]
      }
     ],
     "prompt_number": 35
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E58 : Pg 267"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "\n",
      "#  Example : 4.58\n",
      "   \n",
      "v1=233.73-1j*8.934;\n",
      "vs=240.+1j*0;\n",
      "r1=0.6+1j*0.8;\n",
      "i1=(vs-v1)/r1;\n",
      "print'the value of I1 is = ',i1,' Amp'\n",
      "r2=0.5+1j*0.866;\n",
      "vs1=239.5-1j*14.359;\n",
      "i2=(vs1-v1)/r2;\n",
      "print'the value of I1 is = ',i2,' Amp'\n",
      "r3=16.+1j*12;\n",
      "il=i1/r3;\n",
      "print'the value of I1 is = ',il,' Amp'"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "the value of I1 is =  (10.9092+0.3444j)  Amp\n",
        "the value of I1 is =  (-1.81312977771-7.70965922501j)  Amp\n",
        "the value of I1 is =  (0.4467-0.3135j)  Amp\n"
       ]
      }
     ],
     "prompt_number": 36
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example E62 : Pg 267"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "                      # EXAMPLE 4-61    PG NO-267-268\n",
      "I1=0.05-1j*6.49;\n",
      "I2=0.040+1j*0.02;\n",
      "R1=100.;\n",
      "R2=4.+1j*200.;\n",
      "Vab=(R1*I2)-(R2*(I1-I2));\n",
      "print'i) VOLTAGE  (Vab) is    =  ',Vab,' V '"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "i) VOLTAGE  (Vab) is    =   (-1298.04+26.04j)  V \n"
       ]
      }
     ],
     "prompt_number": 37
    }
   ],
   "metadata": {}
  }
 ]
}