{ "metadata": { "name": "", "signature": "sha256:47ab953016e5f85b7389dfd03b89e4eaceb4217fd3c41781effc5a2eb8d08d3e" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "11: Natural Radioactivity" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 11.1, Page number 222" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#import modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "ttg=8378-1898; #total time gap(yrs)\n", "hf=1620; #half life(yrs)\n", "n=ttg/hf; #number of half-periods\n", "Mo=200; #amount of radium(mg)\n", "\n", "#Calculation\n", "M=Mo*(0.5)**n; #amount of radium left(mg)\n", "\n", "#Result\n", "print \"amount of radium left is\",M,\"mg\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "amount of radium left is 12.5 mg\n" ] } ], "prompt_number": 4 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 11.2, Page number 222" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#import modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "T=30; #half life(days)\n", "#M is intial conc.\n", "\n", "#Calculation\n", "lamda=0.693/T; #radioactive disintegration constant(per day)\n", "#M/4 is left\n", "t1=-math.log(1/4)/lamda; #time taken(days)\n", "#M/8 is left\n", "t2=-math.log(1/8)/lamda; #time taken(days)\n", "\n", "#Result\n", "print \"radioactive disintegration constant is\",lamda,\"per day\"\n", "print \"time taken for 3/4th of original is\",int(t1),\"days\"\n", "print \"time taken for 1/8th of original is\",int(t2),\"days\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "radioactive disintegration constant is 0.0231 per day\n", "time taken for 3/4th of original is 60 days\n", "time taken for 1/8th of original is 90 days\n" ] } ], "prompt_number": 3 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 11.3, Page number 222" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#import modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "No=4750; #count rate(per minute)\n", "N=2700; #rate(counts/minute)\n", "t=5; #time(minutes)\n", "\n", "#Calculation \n", "lamda=math.log(No/N)/t; #decay constant(per minute)\n", "T=0.693/lamda; #half life(minutes)\n", "\n", "#Result\n", "print \"radioactive disintegration constant is\",round(lamda,3),\"per minute\"\n", "print \"half life of sample is\",round(T,1),\"minutes\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "radioactive disintegration constant is 0.113 per minute\n", "half life of sample is 6.1 minutes\n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 11.4, Page number 223" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#import modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "m=4.00387; #mass of alpha particle(amu)\n", "M=10**-6; #mass of Pu-239(kg) \n", "\n", "#Calculation\n", "m=m*1.66*10**-24; #mass of alpha particle(g)\n", "Mo=2300*m; #mass of 2300 alpha particles(g)\n", "lamda=(Mo/1)/M; #radioactive disintegration constant(per second)\n", "T=0.693/lamda; #half life period(seconds)\n", "T=T/(365*24*3600); #half life period(years)\n", "\n", "#Result\n", "print \"half life is\",round(T/1e+6,3),\"*10**6 years\"\n", "print \"answer given in the book varies due to rounding off errors\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "half life is 1.438 *10**6 years\n", "answer given in the book varies due to rounding off errors\n" ] } ], "prompt_number": 5 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 11.5, Page number 223" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#import modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "T=2.48*10**5; #half life(yrs)\n", "lamda=8.88*10**-14 #decay constant (per second)\n", "Mo=4; #intial mass(mg)\n", "t=62000; #time(years)\n", "Na=6.02*10**23; #Avgraodo no.(per g-mol)\n", "\n", "#Calculation\n", "lamdat=0.693/T*t; \n", "M=Mo*(math.exp(-lamdat)); #mass remained unchanged(mg) \n", "N=M*10**-3*Na/234;\n", "A=lamda*N; #activity(disintegrations/second)\n", "\n", "#Result\n", "print \"mass remained unchanged is\",round(M,3),\"mg\"\n", "print \"Activity is\",round(A/1e+5,3),\"*10**5 disintegrations/second\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "mass remained unchanged is 3.364 mg\n", "Activity is 7.684 *10**5 disintegrations/second\n" ] } ], "prompt_number": 6 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 11.6, Page number 223" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#import modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "T=1620; #half life(years)\n", "Mo=1/100; #mass(g)\n", "\n", "#Calculation\n", "lamda=0.693/T; #radioactive constant(per years) \n", "M=(1-Mo); #amount of radium left behind(g) \n", "t=math.log(1/M)/lamda; #time required to lose 1 centigram(years)\n", "t1=math.log(1/Mo)/lamda; #time required to be reduced to 1 centigram(years)\n", "\n", "#Result\n", "print \"time required to lose 1 centigram is\",round(t,1),\"years\"\n", "print \"time required to be reduced to 1 centigram is\",int(t1),\"years\"\n", "print \"answer given in the book varies due to rounding off errors\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "time required to lose 1 centigram is 23.5 years\n", "time required to be reduced to 1 centigram is 10765 years\n", "answer given in the book varies due to rounding off errors\n" ] } ], "prompt_number": 7 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 11.7, Page number 232" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#import modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "T=2*10**-4; #dead time(seconds)\n", "n=500; #number of pulses(per second)\n", "\n", "#Calculation\n", "n0=n/(1-(n*T)); #number of incoming particles(per second)\n", "r=n*T*100; #relative error of counting(%)\n", "\n", "#Result\n", "print \"intensity of the incoming beam is\",int(n0),\"particles/second\"\n", "print \"relative error of counting is\",int(r),\"%\"\n", "print \"answer for intensity given in the book is wrong\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "intensity of the incoming beam is 555 particles/second\n", "relative error of counting is 10 %\n", "answer for intensity given in the book is wrong\n" ] } ], "prompt_number": 8 } ], "metadata": {} } ] }