{ "metadata": { "name": "" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 17 Television" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 17.1 Page no 882" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#given\n", "bw=5*10**6 #bandwidth\n", "t=53.5*10**-6 #time allocated for each visible trace\n", "\n", "#calculation\n", "T=2*bw*t #increase in horizontal resolution\n", "\n", "#result\n", "print\"Thus, the total number of vertical lines resolvable is \",T,\"lines\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Thus, the total number of vertical lines resolvable is 535.0 lines\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 17.2 Page no 822" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#given\n", "bw=5.0*10**6 #bandwidth\n", "l=428 #horizontal resolution\n", "\n", "#calculation\n", "t=l/(bw*2) #trace time\n", "x=1/30.0 #time available for a full picture\n", "y=t+10.0*10**-6 #assuming that 10us is used for horizontal blanking\n", "n=x/y #no. of horizontal traces\n", "c=600*0.7 #allowing 32 lines for vertical retrace\n", "\n", "#result\n", "print\"vertical resolution = \",c,\"lines\"\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "vertical resolution = 420.0 lines\n" ] } ], "prompt_number": 2 } ], "metadata": {} } ] }