{ "metadata": { "name": "", "signature": "sha256:cae0ff7581c3b5c12e11b4f1b44c3beb02347fef7d7d6837104f81f1c4303c1b" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Ch-3 : Microwave Network Analysis" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Page Number: 142 Example 3.4" ] }, { "cell_type": "code", "collapsed": false, "input": [ "from __future__ import division\n", "from numpy import array, linalg, mat, set_printoptions\n", "\n", "#Given\n", "\n", "z=mat('[4 2 ;2 4]')\n", "I=mat('[1 0;0 1]') \n", "\n", "\n", "#Scattering matrix\n", "s=(z-I)*linalg.inv(z+I)\n", "set_printoptions(precision=3)\n", "print 'Scattering Matrix:\\n' ,s" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Scattering Matrix:\n", "[[ 0.524 0.19 ]\n", " [ 0.19 0.524]]\n" ] } ], "prompt_number": 12 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Page Number: 142 Example 3.5" ] }, { "cell_type": "code", "collapsed": false, "input": [ "from math import sqrt, pi \n", "from cmath import exp\n", "#Given\n", "P=12.8e-3 #W\n", "l=3 #cm\n", "lamb=4.2 #cm\n", "vswr=2.2 \n", "jfi=1J*4.49 \n", "\n", "#ap\n", "ap=sqrt(2*P) \n", "\n", "#Phase shift\n", "bl=(2*pi*l)/lamb \n", "#bp\n", "bp=(ap*(vswr-1))/(vswr+1) \n", "\n", "a=ap*exp(jfi) \n", "b=bp*exp(jfi) \n", "print 'Required Waves:\\n{:.3}'.format(a),'\\n{:.3}'.format(b)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Required Waves:\n", "(-0.0353-0.156j) \n", "(-0.0132-0.0585j)\n" ] } ], "prompt_number": 13 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Page Number: 143 Example 3.6" ] }, { "cell_type": "code", "collapsed": false, "input": [ " from math import log10\n", "#Given\n", "S11=0.10 \n", "S12=0.90 \n", "A12=-45 \n", "S21=0.90 \n", "A21=45 \n", "S22=0.3 \n", "\n", "#(i) Network is reciprocal\n", "if(A12==A21):\n", " print 'Network is reciprocal' \n", "else:\n", " \n", " print 'Network is not reciprocal' \n", "\n", "\n", "#(ii) Network is lossles\n", "x=(S11**2)+(S12**2) \n", "if(x==1):\n", " print 'Network is lossless' \n", "else:\n", " \n", " print 'Network is not lossless' \n", "\n", "\n", "#(iii)Return loss\n", "T=S11-((S12*S21)/(1+S22)) \n", "Tm=-T #mod of T\n", "L=-20*log10(Tm) \n", "print 'Return Loss: %0.3f'%L,'dB'" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Network is not reciprocal\n", "Network is not lossless\n", "Return Loss: 5.629 dB\n" ] } ], "prompt_number": 17 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Page Number: 163 Example 3.12" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#Given\n", "S11=0.6 \n", "S12=0.045 \n", "S21=2.5 \n", "S22=0.50 \n", "TS=0.5 \n", "TL=0.4 \n", "Z0=50 #ohm\n", "Vrms=10 #V\n", "\n", "#(i) Gain Parameters\n", "#(i)Reflection coefficients of input and output\n", "Tin=S11+((S12*S21*TL)/(1-(S22*TL))) \n", "Tout=S22+((S12*S21*TS)/(1-(S22*TS))) \n", "\n", "#Transducer Gain\n", "x=(1-(TS)**2)/((1-(S11*TS))**2) \n", "y=(S21*S21) \n", "z=(1-(TL)**2)/((1-(Tout*TL))**2) \n", "GT=x*y*z \n", "print 'Transducer Gain: %0.3f'%GT\n", "\n", "#Available Power Gain\n", "z1=1-(Tout)**2 \n", "GA=(x*y)/z1 \n", "print 'Available power Gain: %0.3f'%GA\n", "\n", "#Power Gain\n", "z2=1-(Tin)**2 \n", "GP=(x*y)/z2 \n", "print 'Power Gain: %0.3f'%GP\n", "\n", "#(ii) Power levels\n", "#Power available at source\n", "Pavs=(sqrt(2)*Vrms)**2/(8*Z0) \n", "print 'Power available at source: %0.3f'%Pavs,'W'\n", "\n", "Pl=9.4*Pavs \n", "#Power available at input\n", "Pin=Pl/13.5 \n", "print 'Power available at input: %0.3f'%Pin,'W'\n", "\n", "#(iii) VSWRs\n", "M1=Pin/Pavs \n", "M2=Pl/(9.6*Pavs) \n", "\n", "Tin1=sqrt(1-M1) \n", "Tout1=sqrt(1-M2) \n", "\n", "vswrin=(1+Tin1)/(1-Tin1) \n", "print 'Input VSWR: %0.3f'%vswrin\n", "vswrout=(1+Tout1)/(1-Tout1) \n", "print 'Output VSWR: %0.3f'%vswrout\n", "\n", "#Calculations for gain are done wrong in book, hence answers dont match" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Transducer Gain: 13.553\n", "Available power Gain: 14.291\n", "Power Gain: 16.803\n", "Power available at source: 0.500 W\n", "Power available at input: 0.348 W\n", "Input VSWR: 3.455\n", "Output VSWR: 1.337\n" ] } ], "prompt_number": 20 } ], "metadata": {} } ] }