{ "metadata": { "name": "", "signature": "sha256:ff1027836ff09444a0f286e9b3a2446de80c3b84e271ae3db6a9354c2ea33b2b" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 4: Shear Forces and Bending Moments" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 4.3, page no. 275" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math\n", "\n", "#initialisation\n", "\n", "q = 0.2 # Uniform load intensity in K/ft\n", "P = 14 # Concentrated load in k\n", "Ra = 11 # Reaction at A from wquation of equilibrium\n", "Rb = 9 # Reaction at B from wquation of equilibrium\n", "\n", "#calculation\n", "V = 11 - 14 - (0.2*15) # shear force in k\n", "\n", "print \"Shear force at section D\", V, \"k\"\n", "M = (11*15)-(14*6)-(0.2*15*7.5) # Bending moment in K-ft\n", "print \"Bending moment at section D\", M, \"k-ft\"\n", "V1 = -9+(0.2*15) # Shear firce from alternative method in k\n", "M1 = (9*9)-(0.2*7.5*15) # Bending moment from alternative method in k-ft" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Shear force at section D -6.0 k\n", "Bending moment at section D 58.5 k-ft\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 4.7" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "\n", "#initialisation\n", "\n", "q = 1 # Uniform load intensity in k/ft\n", "M0 = 12 # Couple in k-ft\n", "Rb = 5.25 # Reaction at B in k\n", "Rc = 1.25 # Reaction at C in k\n", "b = 4 # Length of section AB in ft\n", "\n", "#calculation\n", "\n", "Mb = -(q*(b**2))/2 # Moment acting at B\n", "\n", "#Result\n", "print \"Bending moment at B\", Mb, \"k-ft\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Bending moment at B -8 k-ft\n" ] } ], "prompt_number": 2 } ], "metadata": {} } ] }