{
 "metadata": {
  "name": ""
 },
 "nbformat": 3,
 "nbformat_minor": 0,
 "worksheets": [
  {
   "cells": [
    {
     "cell_type": "heading",
     "level": 1,
     "metadata": {},
     "source": [
      "Chapter 22 - Combustion Processes :  First law analysis"
     ]
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 5 - Pg 419"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#Calculate the heat transferred from the system\n",
      "#initialization of varaibles\n",
      "mO=1.33\n",
      "CO=0.155\n",
      "mC=3.67\n",
      "CC=0.165\n",
      "t2=1000. #F\n",
      "tb=68. #F\n",
      "t1=300. #F\n",
      "mC2=1.\n",
      "CC2=0.17\n",
      "mO2=4.\n",
      "CO2=0.155\n",
      "H=-14087 #B/lb\n",
      "#calculations\n",
      "dE2=mO*CO*(t2-tb) + mC*CC*(t2-tb)\n",
      "dE1=mO2*CO2*(tb-t1) + mC2*CC2*(tb-t1)\n",
      "Q=dE2+dE1+H\n",
      "#results\n",
      "print '%s %d %s' %(\"Heat transfer from the system =\",Q,\"Btu\")\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Heat transfer from the system = -13513 Btu\n"
       ]
      }
     ],
     "prompt_number": 1
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 6 - Pg 422"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#calculate the cp value of methane\n",
      "#initialization of varaibles\n",
      "H1=17889 #Cal/g\n",
      "H2=-94052 #Cal/g\n",
      "H3=2* -68317 #Cal/g\n",
      "#calculations\n",
      "x=H1+H2+H3\n",
      "#results\n",
      "print '%s %d %s' %(\"Constant pressure heating value of methane =\",x,\" cal/gm formula wt.\")\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Constant pressure heating value of methane = -212797  cal/gm formula wt.\n"
       ]
      }
     ],
     "prompt_number": 2
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 7 - Pg 423"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#calculate the cv value of methane\n",
      "#initialization of varaibles\n",
      "HV=4344 #B/lb\n",
      "xC=56 #lb\n",
      "R=1.986\n",
      "T=530 #R\n",
      "MC=56 #g/mol\n",
      "#calculations\n",
      "HR=xC*HV\n",
      "Eb=-HR -R*T*(2-3)\n",
      "HV=-Eb/MC\n",
      "#results\n",
      "print '%s %d %s' %(\"COnstant volume heating value =\",HV,\"B/lb \")\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "COnstant volume heating value = 4325 B/lb \n"
       ]
      }
     ],
     "prompt_number": 3
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 8 - Pg 426"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#Calculate the products temperature\n",
      "#initialization of varaibles\n",
      "dH2=14087 #B/lb\n",
      "xc=3.67 #lb\n",
      "xN=8.78 #lb\n",
      "tb=100 #F\n",
      "#calculations\n",
      "dt2=dH2/(xc*0.196 + xN*0.248)\n",
      "t2=dt2+tb\n",
      "#results\n",
      "print '%s %d %s' %(\"products temperature =\",t2,\"F\")\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "products temperature = 4963 F\n"
       ]
      }
     ],
     "prompt_number": 4
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 9 - Pg 430"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#Calculate the efficiency\n",
      "#initialization of varaibles\n",
      "Heat=14087 #Btu/lb\n",
      "x1=0.9 #lb\n",
      "x2=0.05 #lb\n",
      "x3=0.05 #lb\n",
      "Heat2=3952 #Btu/lb\n",
      "#calculations\n",
      "h1=x1*Heat\n",
      "h2=x2*Heat2\n",
      "e=(h1+h2)/Heat\n",
      "#results\n",
      "print '%s %.2f' %(\"Efficiency = \",e)\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "Efficiency =  0.91\n"
       ]
      }
     ],
     "prompt_number": 5
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 10 - Pg 431"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#calculate the efficiency of the process\n",
      "#initialization of varaibles\n",
      "print '%s' %(\"From data and steam tables,\")\n",
      "Q=10240000. #B/hr\n",
      "w=700. #lb/hr\n",
      "h=19500. #B/lb\n",
      "#calculations\n",
      "HV=w*h\n",
      "e=Q/HV\n",
      "#results\n",
      "print '%s %.2f' %(\"Efficiency = \",e)\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "From data and steam tables,\n",
        "Efficiency =  0.75\n"
       ]
      }
     ],
     "prompt_number": 6
    }
   ],
   "metadata": {}
  }
 ]
}