{ "metadata": { "name": "" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 12 : Heat Treatment" ] }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "Example 12.1 page no : 304" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "\n", "# Variables\n", "n_bcc = 1./2;\n", "n_fcc = 1./4;\n", "r_fcc = 1.26;\t\t\t#in Angstorm\n", "r_bcc = 1.24;\t\t\t#in Angstorm\n", "\n", "# Calculations\n", "a_bcc = 4.*r_bcc/math.sqrt(3);\t\t\t#in Angstorm\n", "a_fcc = 2.*math.sqrt(2)*r_fcc;\t\t\t#in Angstorm\n", "v_fcc = a_fcc**3;\n", "v_bcc = a_bcc**3;\n", "v = 100*((n_fcc*v_fcc)-(n_bcc*v_bcc))/(n_fcc*v_fcc);\n", "\n", "# Results\n", "print \"Percentage change in volume = %.3f\"%v\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Percentage change in volume = -3.764\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "Example 12.3 pageno : 317" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "# Variables\n", "e = 51.;\t\t\t#Young modulous in GPa\n", "v = 0.22;\t\t\t#poisson ratio\n", "\n", "# Calculations\n", "g = e/(2*(1-v));\t\t\t#shear modulous in GPa\n", "b = 2*10.**-10;\n", "ue = (1./2)*g*10**9*b**2*10**12;\t\t\t#in J/m**3\n", "\n", "# Results\n", "print \"Change in free energy during recrysatllization (in J/m**3) = %.1f J/m**3\"%ue\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Change in free energy during recrysatllization (in J/m**3) = 653.8 J/m**3\n" ] } ], "prompt_number": 3 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "Example 12.5 pageno : 329" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "# Variables\n", "g = 41.*10**9;\t\t\t#in N/m**2\n", "b = 0.64*10**-9;\t\t\t#in m\n", "l = 20.*10**-6;\t\t\t#in m\n", "\n", "# Calculations\n", "t = g*b/l;\t\t\t#in N/m**2\n", "T = t*10.**-6;\t\t\t#in MPa\n", "\n", "# Results\n", "print \"Contribution of these particles (in MPa) = %.3f MPa\"%T\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Contribution of these particles (in MPa) = 1.312 MPa\n" ] } ], "prompt_number": 4 } ], "metadata": {} } ] }