{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 18: Dielectric Materials"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.1, page no-460"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Relative permitivity of KCl\n",
"\n",
"import math\n",
"# Variable declaration\n",
"atom=4 # number of atoms \n",
"kci=0.629*10**-9 # LAttice parameter of KCl \n",
"alfk=1.264*10**-40 # electronic polarisability for K+ ion\n",
"alfCl=3.408*10**-40 # electronic polarisability for Cl- ion\n",
"eps0=8.854*10**-12 # permitivity of free space\n",
"\n",
"# Calculations\n",
"pol=alfk+alfCl\n",
"N=atom/kci**3\n",
"epsr=(N*pol/eps0)+1\n",
"\n",
"#Result\n",
"print(\"\\nThe electronic polarisability for KCL = %.3f *10^-40 F m^2\\n\"%(pol*10**40))\n",
"print(\"\\nThe no of Dipoles per m^3 = %.3f * 10^28 atoms m^-3\\n\"%(N/10**28))\n",
"print(\"\\nThe dielectric constant of KCL is %.3f\"%epsr)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
"The electronic polarisability for KCL = 4.672 *10^-40 F m^2\n",
"\n",
"\n",
"The no of Dipoles per m^3 = 1.607 * 10^28 atoms m^-3\n",
"\n",
"\n",
"The dielectric constant of KCL is 1.848\n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.2, page no-460"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# electronic polarisability\n",
"\n",
"import math\n",
"#variable declarations\n",
"r=0.12*10**-9 # atomic radius of Se\n",
"eps=8.854*10**-12 # permitivity of free space \n",
"\n",
"# Calculations\n",
"alf=4*math.pi*eps*r**3\n",
"\n",
"# Result\n",
"print(\"The electronic polarisability of an isolated Se is %.4f * 10^-40 F m^2\"%(alf*10**40))\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The electronic polarisability of an isolated Se is 1.9226 * 10^-40 F m^2\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.3, page no-461"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#electronic to ionic polarability ratio\n",
"\n",
"import math\n",
"# Variable declaration\n",
"n=2.69 # refraction index\n",
"er=4.94 # dielectric cnstant\n",
"\n",
"# calculations\n",
"alfi_by_alfe=(((n+2)*(er-1))/((er+2)*(n-1)))-1\n",
"\n",
"# Result\n",
"print(\"The ratio of the electronic to ionic polarability is %.4f\"%(1/alfi_by_alfe))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The ratio of the electronic to ionic polarability is 1.7376\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.4, page no-462"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# dielectric constant\n",
"\n",
"import math\n",
"#variable declaration\n",
"N= 2.7*10**25 # number of atoms\n",
"alfe=0.35*10**-40 # electronic polarisability \n",
"eps=8.854*10**-12 # permitivity of free space\n",
"\n",
"# calculations\n",
"epsr=(1+(2*N*alfe)/(3*eps))/(1-(N*alfe)/(3*eps))\n",
"\n",
"# Result\n",
"print(\"The dielectric constant of Ne gas is %.8f\"%epsr)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The dielectric constant of Ne gas is 1.00010674\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.5, page no-462"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# charge on the capacitor\n",
"\n",
"import math\n",
"# Variable declaration\n",
"eps=8.85*10**-12 # permitivity of free space\n",
"epsr=6 # relative permitivity of dielectric\n",
"A=5*10**-4 # Area of the capacitor plate \n",
"d=1.5*10**-3 # distance between the plates\n",
"v=100 # Applied voltage\n",
"\n",
"# calculations\n",
"Q=eps*epsr*A*v/d\n",
"\n",
"# Result\n",
"print(\"The charge on the capacitor is %.2f * 10^-9 C\"%(Q*10**9))\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The charge on the capacitor is 1.77 * 10^-9 C\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.6, page no-463"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# dielectric constant\n",
"\n",
"import math\n",
"# variable declaration\n",
"N=2.7*10**25 # Number of Ar atoms\n",
"d=0.384*10**-9 # diameter of Ar atom\n",
"eps=8.854*10**-12 # permitivity of free space\n",
"\n",
"# calculations\n",
"alfe=4*math.pi*eps*d**3\n",
"alfe=alfe*10**-2 # correction\n",
"epsr=(1+((2*N*alfe)/(3*eps)))/(1-((N*alfe)/(3*eps)))\n",
"\n",
"# Result\n",
"print(\"The dielectric constant of Ar is %.8f\"%(epsr))\n",
"# correction is to match the answer in the book \n",
"# answer for alfe is given as 0.63 * 10^-40 but it is actually 0.63* 10^-38."
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The dielectric constant of Ar is 1.00019213\n"
]
}
],
"prompt_number": 13
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.7, page no-464"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Energy stored\n",
"\n",
"import math\n",
"# Variable declaration\n",
"c=2*10**-6 # capacitance\n",
"epsr=80 # permitivity of the dielectric\n",
"v=1000 # Applied voltage\n",
"\n",
"#Calculations\n",
"E1=(c*v**2)/2\n",
"c0=c/epsr\n",
"E2=(c0*v**2)/2\n",
"E=E1-E2\n",
"\n",
"# Result\n",
"print(\"\\nThe Energy stored in capacitor =%.0f J\"%E1)\n",
"print(\"\\nThe energy stored in polarising the capacitor = %.4f J\"%E)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
"The Energy stored in capacitor =1 J\n",
"\n",
"The energy stored in polarising the capacitor = 0.9875 J\n"
]
}
],
"prompt_number": 14
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.8, page no-464"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# nternal field to applied field ratio\n",
"\n",
"import math\n",
"# Variable declaration\n",
"N=5*10**28 # no of atoms present per m^3\n",
"alfe=2*10**-40 # Polarisability \n",
"eps=8.854*10**-12 # permitivity of free space\n",
"\n",
"\n",
"# Calculations\n",
"P=N*alfe\n",
"E_ratio=1/(1-(P/(3*eps)))\n",
"\n",
"# Result\n",
"print(\"The ratio of the internal field to the applied field = %.4f\"%E_ratio)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The ratio of the internal field to the applied field = 1.6038\n"
]
}
],
"prompt_number": 15
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.9, page no-465"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# relative permitivity\n",
"\n",
"import math\n",
"# Variable declaration\n",
"E=1000 # Applied electric field\n",
"P=4.3*10**-8 # Polarisation\n",
"eps=8.854*10**-12 # permitivity of free space\n",
"\n",
"# calculations\n",
"epsr=1+P/(eps*E)\n",
"\n",
"#Result\n",
"print(\"The relative permitivity of NaCl is %.2f\"%epsr)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The relative permitivity of NaCl is 5.86\n"
]
}
],
"prompt_number": 16
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.10, page no-466"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#polarisability of argon atom\n",
"\n",
"import math\n",
"# Variable declaration\n",
"epsr=1.0024 # relative permitivity\n",
"N=2.7*10**25 # Number of atoms\n",
"eps=8.854*10**-12 # permitivity of free space\n",
"\n",
"# calculations\n",
"alfe=eps*(epsr-1)/N\n",
"\n",
"#Result\n",
"print(\"The polarisability of argon atom is %.1f * 10^-40 F m^2\"%(alfe*10**40))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The polarisability of argon atom is 7.9 * 10^-40 F m^2\n"
]
}
],
"prompt_number": 17
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.11, page no-466"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# electronic polarisability\n",
"\n",
"import math\n",
"# Variable declaration\n",
"epsr=1.0000684 # Dielectric constant of the gas at NTP\n",
"N=2.7*10**25 # Number of He atoms\n",
"eps=8.854*10**-12 # permitivity of free space\n",
"\n",
"#calculations\n",
"alfe=eps*(epsr-1)/N\n",
"\n",
"#Result\n",
"print(\"The electronic polarisability of He atom at NTP is %.3f * 10^-41 F m^2\"%(alfe*10**41))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The electronic polarisability of He atom at NTP is 2.243 * 10^-41 F m^2\n"
]
}
],
"prompt_number": 18
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.12, page no-467"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# electronic polarisability\n",
"\n",
"import math\n",
"# variable declaration\n",
"epsr=12 # relative dielectric constant of material\n",
"N=5*10**28 # number of atoms in the element\n",
"eps=8.854*10**-12 # permitivity of free space\n",
"\n",
"#Calculations\n",
"alfe=eps*(epsr-1)/N\n",
"\n",
"# result\n",
"print(\"The electronic polarisability of given element is %.3f * 10^-39 F m^2\"%(math.floor(alfe*10**39*1000)/1000))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The electronic polarisability of given element is 1.947 * 10^-39 F m^2\n"
]
}
],
"prompt_number": 22
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.13, page no-467"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# energy stored in dielectric\n",
"\n",
"import math\n",
"# variable declaration\n",
"c=2*10**-6 # capacitance of plate condenser\n",
"v=1000 # applied voltage\n",
"epsr=100 # dielectric permitivity\n",
"\n",
"# calculations\n",
"E=(c*v**2)/2\n",
"c0=c/epsr\n",
"e2=(c0*v**2)/2\n",
"E1=E-e2\n",
"\n",
"# Result\n",
"print(\"The energy stored in dielectric is %.2f J\"%E1)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The energy stored in dielectric is 0.99 J\n"
]
}
],
"prompt_number": 23
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.14, page no-468"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# electronic polarisability\n",
"\n",
"import math\n",
"#variable declaration\n",
"epsr=3.4 # dielectric constant of sulphur \n",
"eps=8.854*10**-12 # permitivity of free space\n",
"d=2.07*10**3 # density of sulphur \n",
"w=32.07 # Atomic weight\n",
"Avg=6.023*10**23 # avogadro's number\n",
"\n",
"# calculations\n",
"N=Avg*10**3*d/w\n",
"N= (math.ceil(N*10**-26))/10**-26\n",
"alfe=3*eps*(epsr-1)/(N*(epsr+2))\n",
"\n",
"#Result\n",
"print(\"The electronic polarisability of sulphur is %.3f * 10^-40 F.m^2\"%(alfe*10**40))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The electronic polarisability of sulphur is 3.035 * 10^-40 F.m^2\n"
]
}
],
"prompt_number": 43
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.15, page no-469"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# charge stored and polarisation produced in the plate\n",
"\n",
"import math\n",
"#variable declaration\n",
"A=6.45*10**-4 # Area of the capacitor plate\n",
"d=2*10**-3 # distance between plates\n",
"epsr=6 # relative permitivity \n",
"v=10 # applied voltage \n",
"eps=8.854*10**-12 # permitivity in free space\n",
"\n",
"\n",
"# calculations\n",
"c=eps*epsr*A/d\n",
"q=c*v\n",
"E=v/d\n",
"p=eps*(epsr-1)*E\n",
"\n",
"# Result\n",
"print(\"Capacitance of Capacitor = %.2f pF\"%(c*10**12))\n",
"print(\"\\ncharge stored on the plate is %.2f *10^-11 C\"%(q*10**11))\n",
"print(\"\\nPolarisation produce in the plate is %.3f *10^-7 Cm^-2\"%(math.ceil(p*10**7*1000)/1000))\n",
"# answer forstored charge is wrong in the book"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Capacitance of Capacitor = 17.13 pF\n",
"\n",
"charge stored on the plate is 17.13 *10^-11 C\n",
"\n",
"Polarisation produce in the plate is 2.214 *10^-7 Cm^-2\n"
]
}
],
"prompt_number": 53
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.16, page no-470"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Polarisation produced in NaCl\\\n",
"\n",
"import math\n",
"# Variable declaration\n",
"E=600*10**3 # electric field strength\n",
"eps=8.854*10**-12 # permitivity in free space \n",
"epsr=6 # dielectric constant of sodium chloride\n",
"\n",
"# calculations\n",
"p=eps*(epsr-1)*E\n",
"\n",
"# Result\n",
"print(\"Polarisation produced in NaCl is %.3f *10^-5 C.m^-2\"%(p*10**5))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Polarisation produced in NaCl is 2.656 *10^-5 C.m^-2\n"
]
}
],
"prompt_number": 54
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.17, page no-470"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Relative permitivity\n",
"\n",
"import math\n",
"# Variable declaration\n",
"E=1000 # applied electric field\n",
"p=4.3*10**-8 # Polarisation \n",
"eps=8.854*10**-12 # permitivity of free space\n",
"\n",
"#Calculations\n",
"epsr=1+p/(eps*E)\n",
"\n",
"#Result\n",
"print(\"Relative permitivity of NaCl is %.2f\"%epsr)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Relative permitivity of NaCl is 5.86\n"
]
}
],
"prompt_number": 55
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.18, page no-471"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# voltage across capacitor and electric field strength\n",
"\n",
"import math\n",
"# variable declaration\n",
"A=1000*10**-6 # Area of the capacitor plate\n",
"d=5*10**-3 # distance between the plate\n",
"epsr=4 # relative permitivity of the dielectric\n",
"Q=3*10**-10 #charge on the capacitor \n",
"eps=8.854*10**-12 # permitivity of free space\n",
"\n",
"# Calculations\n",
"c=(eps*epsr*A)/d\n",
"v=Q/c\n",
"E=v/d\n",
"\n",
"# Result\n",
"print(\"The voltage across capacitor is %.2f V\\nThe electric field strength is %d V/m\"%(v,E))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The voltage across capacitor is 42.35 V\n",
"The electric field strength is 8470 V/m\n"
]
}
],
"prompt_number": 57
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.19, page no-472"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# electronic polarisability\n",
"\n",
"import math\n",
"# Variable declaration\n",
"epsr=1.0000684 # dielectric constant of the gas at NTP\n",
"N=2.7*10**25 # Number of He atoms \n",
"eps=8.85*10**-12 # permitivuty of free space\n",
"\n",
"# calculations\n",
"alfe=eps*(epsr-1)/N\n",
"\n",
"# Result\n",
"print(\"The electronic polarisability of He atoms at NTP is %.3f *10^-41 F.m^2\"%(alfe*10**41))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The electronic polarisability of He atoms at NTP is 2.242 *10^-41 F.m^2\n"
]
}
],
"prompt_number": 61
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.20, page no-472"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Capacitance and electric field strength\n",
"\n",
"import math\n",
"# Variable declaration\n",
"A=3*10**-3 # area of the capacitor plate\n",
"d=1*10**-3 # distance between the plate\n",
"epsr=3.5 # relative permitivity of the dielectric\n",
"Q=20*10**-9 # charge on the capacitor\n",
"eps=8.85*10**-12 # permitivity of free space\n",
"\n",
"# calculations\n",
"c=eps*epsr*A/d\n",
"E=Q/(c*d)\n",
"\n",
"# Result\n",
"print(\"The capacitance of capacitor is %.2f pF\"%(math.ceil(c*10**14)/100))\n",
"print(\"The electric field strength is %.2f*10^3 V/m\"%(math.floor(E*10**-1)/100))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The capacitance of capacitor is 92.93 pF\n",
"The electric field strength is 215.22*10^3 V/m\n"
]
}
],
"prompt_number": 71
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.21, page no-473"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# capacitance, stored charge, polarisation and dielectric displacement\n",
"\n",
"import math\n",
"# variable declaration\n",
"A=7.45*10**-4 # Area of the capacitor plates\n",
"d=2.45*10**-3 # distance between the plates\n",
"epsr=6 # relative permitivity of the dielectric \n",
"v=10 # applied voltage \n",
"eps=8.85*10**-12 # permitivity of free space\n",
"\n",
"#Calculations\n",
"c=eps*epsr*A/d\n",
"Q=c*v\n",
"E=v/d\n",
"p=eps*(epsr-1)*E\n",
"D=eps*epsr*E\n",
"\n",
"# Result\n",
"print(\"\\nThe capacitance of the capacitor is %.3f pF\"%(c*10**12))\n",
"print(\"\\nCharge stored on capacitor = %.3f *10^-11 C\\n\\nE=%.2f*10^3 V/m\"%(Q*10**11,E*10**-3))\n",
"print(\"\\nPolarisation=%.3f*10^-7 C.m^-2\\n\\ndielectric displacement = %.3f*10^-7 C.m^-2\"%(p*10**7,D*10**7))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"\n",
"The capacitance of the capacitor is 16.147 pF\n",
"\n",
"Charge stored on capacitor = 16.147 *10^-11 C\n",
"\n",
"E=4.08*10^3 V/m\n",
"\n",
"Polarisation=1.806*10^-7 C.m^-2\n",
"\n",
"dielectric displacement = 2.167*10^-7 C.m^-2\n"
]
}
],
"prompt_number": 77
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.22, page no-475"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# polarisation produced\n",
"\n",
"import math\n",
"#variable declaration\n",
"E=500 # electric field strength\n",
"epsr=6 # dielectric constant of sodium cloride\n",
"eps=8.854*10**-12 # permitivity of free space\n",
"\n",
"# calculations\n",
"p=eps*(epsr-1)*E\n",
"\n",
"# Result\n",
"print(\"The polarisation produced in NaCl is %.3f * 10^-8 C.m^-2\"%(math.ceil(p*10**11)/1000))\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The polarisation produced in NaCl is 2.214 * 10^-8 C.m^-2\n"
]
}
],
"prompt_number": 91
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.23, page no-475"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# polarisation produced in NaCl\n",
"\n",
"import math\n",
"#Variable declaration\n",
"E=500 # electric field strength\n",
"epsr=15 # dielectric constant of sodium cloride \n",
"eps=8.854*10**-12 # permitivity of free space\n",
"\n",
"#calculations\n",
"p=eps*(epsr-1)*E\n",
"\n",
"#Result\n",
"print(\"The polarisation produced in NaCl is %.3f * 10^-8 C.m^-2\"%(p*10**8))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The polarisation produced in NaCl is 6.198 * 10^-8 C.m^-2\n"
]
}
],
"prompt_number": 92
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.24, page no-475"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# Voltage across capacitor\n",
"\n",
"import math\n",
"#variable declaration\n",
"A=650*10**-6 # Area of the capacitor plate \n",
"d=4 *10**-3 # distance between the plates\n",
"epsr=3.5 # relative permitivity of the dielectric\n",
"eps=8.85*10**-12 # permitivity of free space \n",
"q=2*10**-10 # charge on the capacitor\n",
"\n",
"# calculations\n",
"v=q*d/(eps*epsr*A)\n",
"\n",
"# Result\n",
"print(\"The voltage across capacitor is %.2f V\"%v)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The voltage across capacitor is 39.73 V\n"
]
}
],
"prompt_number": 97
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.25, page no-476"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"# charge on the capacitor\n",
"\n",
"import math\n",
"# variable declaration\n",
"A=5*10**-4 # Area of the capacitor plates\n",
"d=1.5*10**-3 # Distance between the plates\n",
"epsr=6 # Relative permitivity of the dielectric\n",
"v=100 # Applied voltage\n",
"eps=8.854*10**-12 # permitivity of free space\n",
"\n",
"#calculation\n",
"q=eps*epsr*A*v/d\n",
"\n",
"#Result\n",
"print(\"The charge on the capacitor is %.2f *10^-9 C\"%(q*10**9))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The charge on the capacitor is 1.77 *10^-9 C\n"
]
}
],
"prompt_number": 98
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18.26, page no-476"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#dielectric constant\n",
"\n",
"import math\n",
"#variable declaration\n",
"d=2.08*10**3 # density of sulphur\n",
"wt=32 # atomic weight of sulphur\n",
"ep=3.28*10**-40 # electronic polarisability\n",
"eps=8.854*10**-15 # permeability of free space\n",
"\n",
"# Calculations\n",
"k=(3*10**28*7*10**-40)/(3*eps)\n",
"epsr=2.5812/(1-0.7906)\n",
"\n",
"# result\n",
"print(\"The dielectric constant of the given material is %.3f\"%epsr)\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The dielectric constant of the given material is 12.327\n"
]
}
],
"prompt_number": 3
}
],
"metadata": {}
}
]
}