{ "metadata": { "name": "" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 14: Luminescence" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 14.1, page no-385" ] }, { "cell_type": "code", "collapsed": false, "input": [ "# Penetration depth of electron\n", "\n", "import math\n", "#Variable Declaration\n", "eb=10000.0 # Energy of incident beam in eV\n", "k=1.2*10**-4 # Constant depending on marerial \n", "b=0.151 # Constant depending on marerial\n", "e=1.6*10**-19 # charge of an electron\n", "\n", "#Calculation\n", "rc=k*(eb*e)**b\n", "\n", "#Result\n", "print('The penetration depth of the electron is %.4f \u00b5m'%(rc*10**6))" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The penetration depth of the electron is 0.6998 \u00b5m\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 14.2, page no-386" ] }, { "cell_type": "code", "collapsed": false, "input": [ "# Luminescent lifetime\n", "\n", "import math\n", "#Variable Declaration\n", "ed=0.4 # difference in energy level in eV\n", "e=1.6*10**-19 # Charge of an electron\n", "kT=0.025 # temperature equivalent \n", "q=10**8 # constant\n", "\n", "#Calculation\n", "r=q*math.e**(-(ed/kT))\n", "\n", "#Result\n", "print('The escape rate per unit time = %.1f per sec\\nTherefore, the luminescent lifetime is nearly %.0f sec'%(math.floor(r*10)/10,r))" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The escape rate per unit time = 11.2 per sec\n", "Therefore, the luminescent lifetime is nearly 11 sec\n" ] } ], "prompt_number": 5 } ], "metadata": {} } ] }