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 "worksheets": [
  {
   "cells": [
    {
     "cell_type": "heading",
     "level": 1,
     "metadata": {},
     "source": [
      "Ch:6 Levers"
     ]
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "exa 6-1 - Page 171"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "from math import sqrt, pi\n",
      "Del=10#\n",
      "k=500#\n",
      "W=k*Del#\n",
      "#Let load arm be l1\n",
      "l1=200#\n",
      "#Let effort arm be l2\n",
      "l2=500#\n",
      "P=W*l1/l2#\n",
      "Ro=sqrt(W**2+P**2)#\n",
      "Ta=40#\n",
      "d=sqrt(Ro*4/(2*pi*Ta))#\n",
      "d=10#\n",
      "pb=10#\n",
      "d1=sqrt(Ro/(pb*1.5))#\n",
      "d1=20#\n",
      "l=1.5*d#\n",
      "t=10#\n",
      "T=Ro*4/(2*pi*d1**2)#\n",
      "M=(Ro/2*(l/2+t/3))-(Ro/2*l/4)#\n",
      "sigb=32*M/(pi*d1**3)#\n",
      "sigmax=(sigb/2)+sqrt((sigb/2)**2+T**2)#\n",
      "P=Ro/(l*d1)#\n",
      "D=2*d1#\n",
      "print \" d1 is %0.1f mm     \"%(d1)#\n",
      "print \"\\n D is %0.1f mm     \"%(D)#"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " d1 is 20.0 mm     \n",
        "\n",
        " D is 40.0 mm     \n"
       ]
      }
     ],
     "prompt_number": 14
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "exa 6-2 - Page 172"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "d1=80#\n",
      "p=0.981#\n",
      "Ta=40#\n",
      "siga=80#\n",
      "pa=15#\n",
      "W=pi*(d1**2)*p/4#\n",
      "P=W/8#\n",
      "Ws=W-P#\n",
      "d=sqrt(W*4/(pi*2*Ta))#\n",
      "l=1.5*d#\n",
      "D=2*d#\n",
      "T=W/(2*pi*pa**2/4)#\n",
      "M1=P*(700-87.5-(D/2))#\n",
      "h=50#\n",
      "b=h/4#\n",
      "Z=b*h**2/6#\n",
      "sigb=M1/Z#\n",
      "pmax=80#\n",
      "T=2465.6/h**2#\n",
      "pmax=(sigb/2)+sqrt((sigb/2)**2+T**2)#\n",
      "print \" h is %0.2f mm     \"%(h)#\n",
      "print \"\\n pmax is %0.2f MPa     \"%(pmax)#\n",
      "  \n",
      "#The difference in the value of pmax is due to rounding-off the digits."
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " h is 50.00 mm     \n",
        "\n",
        " pmax is 74.43 MPa     \n"
       ]
      }
     ],
     "prompt_number": 9
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "exa 6-3 - Page 173"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "P=((4*360)+(2*360))/900#\n",
      "Fv=4-2#\n",
      "Fh=P#\n",
      "Fr=sqrt(Fv**2+Fh**2)#\n",
      "P1=4*0.36/0.9#\n",
      "Rf=sqrt(4**2+1.6**2)#\n",
      "d=sqrt(Rf*10**3/(15*1.25))#\n",
      "d=16#\n",
      "l=1.25*d#\n",
      "T=Rf*10**3*4/(2*pi*d**2)#\n",
      "D=2*d#\n",
      "M1=Rf*10**3*(360-(D/2))#\n",
      "pa=15#\n",
      "h=80#\n",
      "b=h/4#\n",
      "Z=b*h**2/6#\n",
      "sigb=M1/Z#\n",
      "T=4310/(b*h)#\n",
      "pmax=(sigb/2)+sqrt((sigb/2)**2+T**2)#\n",
      "print \"P is %0.1f KN     \"%(P)#\n",
      "print \"\\npmax is %0.2f MPa     \"%(pmax)#"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "P is 2.0 KN     \n",
        "\n",
        "pmax is 69.53 MPa     \n"
       ]
      }
     ],
     "prompt_number": 10
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "exa 6-4 - Page 174"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "l=360#\n",
      "P=400#\n",
      "Mh=2*P*l/3#\n",
      "sigb=50#\n",
      "l1=60#\n",
      "d=(Mh*32/(pi*l1))**(1/3)#\n",
      "d=30#\n",
      "L=420#\n",
      "siga=60#\n",
      "H=20#\n",
      "B=H/3#\n",
      "Mx=P*(L-H/2)#\n",
      "Tx=2*P*l/3#\n",
      "sigb1=Mx*18/H**3#\n",
      "Td=P/(B*H)#\n",
      "Tr=17.17*Tx/H**4#\n",
      "T=Tr+Td#\n",
      "sigmax=(sigb1/2)+sqrt((sigb1/2)**2+T**2)#\n",
      "Tmax=sqrt((sigb1/2)**2+T**2)#\n",
      "T=P*L#\n",
      "M=P*(l1+(2/3*l))#\n",
      "Te=sqrt(T**2+M**2)#\n",
      "Ta=40#\n",
      "D=(Te*16/(pi*Ta))**(1/3)#\n",
      "D=30# #Rounding off to nearest whole number\n",
      "print \"d is %0.1f mm     \"%(d)#\n",
      "print \"\\nD is %0.1f mm     \"%(D)#"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "d is 30.0 mm     \n",
        "\n",
        "D is 30.0 mm     \n"
       ]
      }
     ],
     "prompt_number": 11
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "exa 6-5 - Page 175"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "l2=300#\n",
      "l=450#\n",
      "P=400#\n",
      "Mx=2*P*l2/3#\n",
      "siga=80#\n",
      "dh=(Mx*32/(pi*siga))**(1/3)#\n",
      "dh=22#\n",
      "L=(2*l2/3)+l#\n",
      "T=P*L#\n",
      "Ta=40#\n",
      "d=(T*16/(pi*Ta))**(1/3)#\n",
      "d=35#\n",
      "d1=1.6*d#\n",
      "Th=T*16*d1/(pi*(d1**4-d**4))#\n",
      "l1=1.5*d#\n",
      "My=P*(L-(d1/2))#\n",
      "B=dh#\n",
      "H=sqrt(3.66*75)#\n",
      "H=30#\n",
      "Mz=P*l1/2#\n",
      "Te=sqrt(T**2+Mz**2)#\n",
      "d2=(Te*16/(pi*Ta))**(1/3)#\n",
      "d2=32#\n",
      "b=d/4#\n",
      "b=9# #Rounding off to nearest whole number\n",
      "t=d/6#\n",
      "t=6# #Rounding off to nearest whole number\n",
      "print \" d is %0.1f  mm     \"%(d)#\n",
      "print \"\\n dh is %0.1f mm     \"%(dh)#\n",
      "print \"\\n d1 is %0.1f mm     \"%(d1)#\n",
      "print \"\\n l1 is %0.1f mm     \"%(l1)#\n",
      "print \"\\n d2 is %0.1f mm     \"%(d2)#\n",
      "print \"\\n b  is %0.1f  mm     \"%(b)#\n",
      "print \"\\n t  is %0.1f  mm     \"%(t)#\n",
      "  "
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " d is 35.0  mm     \n",
        "\n",
        " dh is 22.0 mm     \n",
        "\n",
        " d1 is 56.0 mm     \n",
        "\n",
        " l1 is 52.5 mm     \n",
        "\n",
        " d2 is 32.0 mm     \n",
        "\n",
        " b  is 9.0  mm     \n",
        "\n",
        " t  is 6.0  mm     \n"
       ]
      }
     ],
     "prompt_number": 12
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "exa 6-6 - Page 175"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "L=450#\n",
      "P=700#\n",
      "T=P*L#\n",
      "Ta=50#\n",
      "d=(T*16/(pi*Ta))**(1/3)#\n",
      "d=32#\n",
      "d1=1.6*d#\n",
      "d1=52# #Rounding off to nearest whole number\n",
      "l1=1.25*d#\n",
      "My=P*(L-d1/2)#\n",
      "sigb=65#\n",
      "H=(My*18/sigb)**(1/3)#\n",
      "H=45#\n",
      "B=H/3#\n",
      "T1=P/(B*H)#\n",
      "sigmax=(sigb/2)+sqrt((sigb/2)**2+T**2)#\n",
      "Mx=P*l1/2#\n",
      "Te=sqrt((T)**2+(Mx**2))#\n",
      "d2=(Te*16/(pi*Ta))**(1/3)#\n",
      "d2=d2+6#\n",
      "d2=38# #Rounding off to nearest whole number\n",
      "print \" d is %0.1f  mm     \"%(d)#\n",
      "print \"\\n d1 is %0.1f mm     \"%(d1)#\n",
      "print \"\\n l1 is %0.1f mm     \"%(l1)#\n",
      "print \"\\n B  is %0.1f mm     \"%(B)#\n",
      "print \"\\n H  is %0.1f mm     \"%(H)#\n",
      "print \"\\n d2 is %0.1f mm     \"%(d2)#\n",
      "  "
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        " d is 32.0  mm     \n",
        "\n",
        " d1 is 52.0 mm     \n",
        "\n",
        " l1 is 40.0 mm     \n",
        "\n",
        " B  is 15.0 mm     \n",
        "\n",
        " H  is 45.0 mm     \n",
        "\n",
        " d2 is 38.0 mm     \n"
       ]
      }
     ],
     "prompt_number": 13
    }
   ],
   "metadata": {}
  }
 ]
}