{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# Ch:13 Cotter and knuckle joints" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## exa 13-1 - Page 371" ] }, { "cell_type": "code", "execution_count": 1, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ " d is 26 mm \n", "\n", " d1 is 32 mm \n", "\n", " d2 is 44 mm \n", "\n", " d3 is 64 mm \n", "\n", " d4 is 40 mm \n", "\n", " sigbc is 103.0 MPa \n" ] } ], "source": [ "from math import sqrt, pi\n", "F=25*10**3#\n", "sigat=50#\n", "Ta=40#\n", "pa=80#\n", "d=sqrt((4*F)/(pi*sigat))#\n", "d=26#\n", "t=d/4#\n", "t=7#\n", "d1=1.2*d#\n", "d1=32#\n", "pc=F/(d1*t)#\n", "t=10#\n", "c=0.75*d#\n", "c=20#\n", "d2=44#\n", "tw=(d2-d1)/2#\n", "b=F/(2*t*Ta)#\n", "b=34#\n", "a=0.5*d#\n", "d3=(F/(pa*t))+d1#\n", "d3=64#\n", "e=F/(Ta*(d3-d1))#\n", "d4=sqrt((F*4/(pi*pa))+d1**2)#\n", "d4=40#\n", "f=0.5*d#\n", "sigbc=3*F*d3/(t*b**2*4)#\n", "print \" d is %0.0f mm \"%(d)#\n", "print \"\\n d1 is %0.0f mm \"%(d1)#\n", "print \"\\n d2 is %0.0f mm \"%(d2)#\n", "print \"\\n d3 is %0.0f mm \"%(d3)#\n", "print \"\\n d4 is %0.0f mm \"%(d4)#\n", "print \"\\n sigbc is %0.1f MPa \"%(sigbc)#" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## exa 13-2 - Page 372" ] }, { "cell_type": "code", "execution_count": 2, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ " d is 21 mm \n", "\n", " d1 is 28 mm \n", "\n", " t is 10 mm \n", "\n", " b is 31 mm \n", "\n", " d2 is 40 mm \n", "\n", " L is 138 mm \n" ] } ], "source": [ "from math import sqrt, pi\n", "P=40*10**3#\n", "sigut=490#\n", "FOS=4#\n", "sigts=sigut/FOS#\n", "sigcs=1.4*sigts#\n", "sigs=0.8*sigts#\n", "d=sqrt((4*P)/(pi*sigts))#\n", "d=21#\n", "sigcc=1.4*330/4#\n", "Tc=0.8*330/4#\n", "t=d/3#\n", "b=P/(2*t*Tc)#\n", "b=31#\n", "t=10#\n", "d1=28#\n", "d2=40#\n", "c=d/2#\n", "c=15#\n", "a=P/(2*(d2-d1)*98)#\n", "a=20#\n", "L=(2*a)+(2*b)+(2*c)+(2*3)#\n", "print \" d is %0.0f mm \"%(d)#\n", "print \"\\n d1 is %0.0f mm \"%(d1)#\n", "print \"\\n t is %0.0f mm \"%(t)#\n", "print \"\\n b is %0.0f mm \"%(b)#\n", "print \"\\n d2 is %0.0f mm \"%(d2)#\n", "print \"\\n L is %0.0f mm \"%(L)#" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## exa 13-3 - Page 372" ] }, { "cell_type": "code", "execution_count": 3, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ " a is 33 mm \n", "\n", " t is 11 mm \n", "\n", " t1 is 16 mm \n", "\n", " b is 20 mm \n", "\n", " b1 is 25 mm \n", "\n", " l1 is 14 mm \n", "\n", " l2 is 14 mm \n", "\n", " l3 is 20 mm \n", "\n", " l4 is 11 mm \n", "\n", " sigcr is 110.0 MPa \n", "\n", " sigcr1 is 113.0 MPa \n" ] } ], "source": [ "from math import sqrt, pi\n", "P=40*10**3#\n", "sigt=60#\n", "sigc=125#\n", "T=45#\n", "a=sqrt(P*3/(2*sigt))#\n", "a=33#\n", "t=a/3#\n", "b=P/(4.5*t*T)#\n", "b=20#\n", "b1=1.25*b#\n", "t1=P*3/(4*a*sigt)#\n", "t1=16#\n", "l2=P/(2*2*T*t1)#\n", "l2=14#\n", "l1=P/(2*a*T)#\n", "l1=14#\n", "l3=(0.6*a)#\n", "l3=20#\n", "l4=11#\n", "sigcr=P/(t*a)#\n", "sigcr1=P/(2*t1*t)#\n", "print \" a is %0.0f mm \"%(a)#\n", "print \"\\n t is %0.0f mm \"%(t)#\n", "print \"\\n t1 is %0.0f mm \"%(t1)#\n", "print \"\\n b is %0.0f mm \"%(b)#\n", "print \"\\n b1 is %0.0f mm \"%(b1)#\n", "print \"\\n l1 is %0.0f mm \"%(l1)#\n", "print \"\\n l2 is %0.0f mm \"%(l2)#\n", "print \"\\n l3 is %0.0f mm \"%(l3)#\n", "print \"\\n l4 is %0.0f mm \"%(l4)#\n", "print \"\\n sigcr is %0.1f MPa \"%(sigcr)#\n", "print \"\\n sigcr1 is %0.1f MPa \"%(sigcr1)#" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## exa 13-4 - Page 373" ] }, { "cell_type": "code", "execution_count": 4, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ " d is 30 mm \n", "\n", " sigt is 52.1 MPa \n", "\n", " b is 36 mm \n" ] } ], "source": [ "P=50*10**3#\n", "sigp=380#\n", "FOS=4#\n", "sigca=80#\n", "Ta=50#\n", "sigta=sigp/FOS#\n", "At=P/sigta#\n", "d=30#\n", "d1=1.5*d#\n", "t=P/(sigca*d1)#\n", "t=14#\n", "A=(pi*(d1**2)/4)-(d1*t)#\n", "#let tearing stress be sigt\n", "sigt=P/A#\n", "b=P/(2*t*Ta)#\n", "b=36#\n", "print \" d is %0.0f mm \"%(d)#\n", "print \"\\n sigt is %0.1f MPa \"%(sigt)#\n", "print \"\\n b is %0.0f mm \"%(b)#\n", " \n", "#The answer to tearing stress in bolt 'sigt' is calculated incorrectly in the book." ] } ], "metadata": { "kernelspec": { "display_name": "Python 2", "language": "python", "name": "python2" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 2 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython2", "version": "2.7.9" } }, "nbformat": 4, "nbformat_minor": 0 }