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{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Ch:13 Cotter and knuckle joints"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"exa 13-1 - Page 371"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"from math import sqrt, pi\n",
"F=25*10**3#\n",
"sigat=50#\n",
"Ta=40#\n",
"pa=80#\n",
"d=sqrt((4*F)/(pi*sigat))#\n",
"d=26#\n",
"t=d/4#\n",
"t=7#\n",
"d1=1.2*d#\n",
"d1=32#\n",
"pc=F/(d1*t)#\n",
"t=10#\n",
"c=0.75*d#\n",
"c=20#\n",
"d2=44#\n",
"tw=(d2-d1)/2#\n",
"b=F/(2*t*Ta)#\n",
"b=34#\n",
"a=0.5*d#\n",
"d3=(F/(pa*t))+d1#\n",
"d3=64#\n",
"e=F/(Ta*(d3-d1))#\n",
"d4=sqrt((F*4/(pi*pa))+d1**2)#\n",
"d4=40#\n",
"f=0.5*d#\n",
"sigbc=3*F*d3/(t*b**2*4)#\n",
"print \" d is %0.0f mm \"%(d)#\n",
"print \"\\n d1 is %0.0f mm \"%(d1)#\n",
"print \"\\n d2 is %0.0f mm \"%(d2)#\n",
"print \"\\n d3 is %0.0f mm \"%(d3)#\n",
"print \"\\n d4 is %0.0f mm \"%(d4)#\n",
"print \"\\n sigbc is %0.1f MPa \"%(sigbc)#"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" d is 26 mm \n",
"\n",
" d1 is 32 mm \n",
"\n",
" d2 is 44 mm \n",
"\n",
" d3 is 64 mm \n",
"\n",
" d4 is 40 mm \n",
"\n",
" sigbc is 103.0 MPa \n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"exa 13-2 - Page 372"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"P=40*10**3#\n",
"sigut=490#\n",
"FOS=4#\n",
"sigts=sigut/FOS#\n",
"sigcs=1.4*sigts#\n",
"sigs=0.8*sigts#\n",
"d=sqrt((4*P)/(pi*sigts))#\n",
"d=21#\n",
"sigcc=1.4*330/4#\n",
"Tc=0.8*330/4#\n",
"t=d/3#\n",
"b=P/(2*t*Tc)#\n",
"b=31#\n",
"t=10#\n",
"d1=28#\n",
"d2=40#\n",
"c=d/2#\n",
"c=15#\n",
"a=P/(2*(d2-d1)*98)#\n",
"a=20#\n",
"L=(2*a)+(2*b)+(2*c)+(2*3)#\n",
"print \" d is %0.0f mm \"%(d)#\n",
"print \"\\n d1 is %0.0f mm \"%(d1)#\n",
"print \"\\n t is %0.0f mm \"%(t)#\n",
"print \"\\n b is %0.0f mm \"%(b)#\n",
"print \"\\n d2 is %0.0f mm \"%(d2)#\n",
"print \"\\n L is %0.0f mm \"%(L)#"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" d is 21 mm \n",
"\n",
" d1 is 28 mm \n",
"\n",
" t is 10 mm \n",
"\n",
" b is 31 mm \n",
"\n",
" d2 is 40 mm \n",
"\n",
" L is 138 mm \n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"exa 13-3 - Page 372"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"P=40*10**3#\n",
"sigt=60#\n",
"sigc=125#\n",
"T=45#\n",
"a=sqrt(P*3/(2*sigt))#\n",
"a=33#\n",
"t=a/3#\n",
"b=P/(4.5*t*T)#\n",
"b=20#\n",
"b1=1.25*b#\n",
"t1=P*3/(4*a*sigt)#\n",
"t1=16#\n",
"l2=P/(2*2*T*t1)#\n",
"l2=14#\n",
"l1=P/(2*a*T)#\n",
"l1=14#\n",
"l3=(0.6*a)#\n",
"l3=20#\n",
"l4=11#\n",
"sigcr=P/(t*a)#\n",
"sigcr1=P/(2*t1*t)#\n",
"print \" a is %0.0f mm \"%(a)#\n",
"print \"\\n t is %0.0f mm \"%(t)#\n",
"print \"\\n t1 is %0.0f mm \"%(t1)#\n",
"print \"\\n b is %0.0f mm \"%(b)#\n",
"print \"\\n b1 is %0.0f mm \"%(b1)#\n",
"print \"\\n l1 is %0.0f mm \"%(l1)#\n",
"print \"\\n l2 is %0.0f mm \"%(l2)#\n",
"print \"\\n l3 is %0.0f mm \"%(l3)#\n",
"print \"\\n l4 is %0.0f mm \"%(l4)#\n",
"print \"\\n sigcr is %0.1f MPa \"%(sigcr)#\n",
"print \"\\n sigcr1 is %0.1f MPa \"%(sigcr1)#"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" a is 33 mm \n",
"\n",
" t is 11 mm \n",
"\n",
" t1 is 16 mm \n",
"\n",
" b is 20 mm \n",
"\n",
" b1 is 25 mm \n",
"\n",
" l1 is 14 mm \n",
"\n",
" l2 is 14 mm \n",
"\n",
" l3 is 20 mm \n",
"\n",
" l4 is 11 mm \n",
"\n",
" sigcr is 110.0 MPa \n",
"\n",
" sigcr1 is 113.0 MPa \n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"exa 13-4 - Page 373"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"P=50*10**3#\n",
"sigp=380#\n",
"FOS=4#\n",
"sigca=80#\n",
"Ta=50#\n",
"sigta=sigp/FOS#\n",
"At=P/sigta#\n",
"d=30#\n",
"d1=1.5*d#\n",
"t=P/(sigca*d1)#\n",
"t=14#\n",
"A=(pi*(d1**2)/4)-(d1*t)#\n",
"#let tearing stress be sigt\n",
"sigt=P/A#\n",
"b=P/(2*t*Ta)#\n",
"b=36#\n",
"print \" d is %0.0f mm \"%(d)#\n",
"print \"\\n sigt is %0.1f MPa \"%(sigt)#\n",
"print \"\\n b is %0.0f mm \"%(b)#\n",
" \n",
" #The answer to tearing stress in bolt 'sigt' is calculated incorrectly in the book."
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" d is 30 mm \n",
"\n",
" sigt is 52.1 MPa \n",
"\n",
" b is 36 mm \n"
]
}
],
"prompt_number": 4
}
],
"metadata": {}
}
]
}