{ "metadata": { "name": "" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 1 : Introduction" ] }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.1 page number 19" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "\n", "y_oxygen = 0.21 #mole fraction of oxygen\n", "y_nitrogen = 0.79 #mole fraction of nitrogen\n", "molar_mass_oxygen = 32.\n", "molar_mass_nitrogen = 28.\n", "\n", "molar_mass_air = y_oxygen*molar_mass_oxygen+y_nitrogen*molar_mass_nitrogen;\n", "mass_fraction_oxygen =y_oxygen*molar_mass_oxygen/molar_mass_air;\n", "mass_fraction_nitrogen = y_nitrogen*molar_mass_nitrogen/molar_mass_air;\n", "\n", "print \"mass fraction of oxygen = %f \"%(mass_fraction_oxygen)\n", "print \"mass fraction of nitrogen = %f \"%(mass_fraction_nitrogen)\n", "\n", "V1 = 22.4 #in liters\n", "P1 = 760. #in mm Hg\n", "P2= 735.56 #in mm Hg\n", "T1= 273. #in K\n", "T2 = 298. #in K\n", "\n", "V2= (P1*T2*V1)/(P2*T1);\n", "density = molar_mass_air/V2;\n", "\n", "print \"density = %f gm/l\"%(density)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "mass fraction of oxygen = 0.233010 \n", "mass fraction of nitrogen = 0.766990 \n", "density = 1.141558 gm/l\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.2 page number 20\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "mass_propane=14.2 #in kg\n", "molar_mass=44 #in kg\n", "\n", "moles=(mass_propane*1000)/molar_mass;\n", "volume=22.4*moles; #in liters\n", "\n", "print \"volume = %d liters\"%(volume)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "volume = 7229 liters\n" ] } ], "prompt_number": 3 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.3 page number 20\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "\n", "y_CO2 = 0.25;\n", "y_CO = 0.002;\n", "y_SO2 = 0.012;\n", "y_N2 = 0.680;\n", "y_O2 = 0.056;\n", "\n", "Mm = y_CO2*44+y_CO*28+y_SO2*64+y_N2*28+y_O2*32;\n", "print \" molar mass = %d \"%(Mm)\n", "\n", "print \" finding weight composition \"\n", "w_CO2 = y_CO2*44*100/Mm;\n", "print \" weight_CO2 = %f \"%(w_CO2)\n", "w_CO = y_CO*28*100/Mm;\n", "print \"weight_CO = %f \"%(w_CO)\n", "w_SO2 = y_SO2*64*100/Mm;\n", "print \"weight_SO2 = %f \"%( w_SO2)\n", "w_N2 = y_N2*28*100/Mm;\n", "print \"weight_N2 = %f \"%( w_N2)\n", "w_O2 = y_O2*32*100/Mm;\n", "print \"weight_O2 = %f \"%( w_O2)\n", "\n", "print \"if SO2 is removed \"\n", "v_CO2 = 25;\n", "v_CO = 0.2;\n", "v_N2 = 68.0;\n", "v_O2 = 5.6;\n", "v = v_CO2+v_CO+v_N2+v_O2;\n", "v1_CO2 = (v_CO2*100/98.8);\n", "\n", "print \"volume_CO2 = %f \"%( v1_CO2)\n", "v1_CO = (v_CO*100/98.8);\n", "print \"volume_CO = %f \"%(v1_CO)\n", "v1_N2 = (v_N2*100/98.8);\n", "print \"volume_N2 = %f \"%(v1_N2)\n", "v1_O2 = (v_O2*100/98.8);\n", "print \"volume_O2 = %f \"%(v1_O2 )\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ " molar mass = 32 \n", " finding weight composition \n", " weight_CO2 = 33.684468 \n", "weight_CO = 0.171485 \n", "weight_SO2 = 2.351788 \n", "weight_N2 = 58.304753 \n", "weight_O2 = 5.487506 \n", "if SO2 is removed \n", "volume_CO2 = 25.303644 \n", "volume_CO = 0.202429 \n", "volume_N2 = 68.825911 \n", "volume_O2 = 5.668016 \n" ] } ], "prompt_number": 4 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.4 page number 24\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "\n", "p=1. #atm\n", "H=2.7 #atm\n", "\n", "x=p/H;\n", "\n", "mole_ratio = (x)/(1-x);\n", "moles_of_water=(100*1000)/18.;\n", "moles_of_NH3=mole_ratio*moles_of_water;\n", "\n", "print \"moles of NH3 dissolved = %f\"%(moles_of_NH3)\n", "\n", "volume_NH3=(moles_of_NH3*22.4*293)/273;\n", "print \"volume of NH3 dissolved = %f liters\"%(volume_NH3)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "moles of NH3 dissolved = 3267.973856\n", "volume of NH3 dissolved = 78565.443271 liters\n" ] } ], "prompt_number": 5 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.5 page number 24\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "p=746 #in mm Hg\n", "H=1.08*10**6 #in mm Hg, Henry's constant\n", "\n", "x= p/H; #mole fraction of CO2\n", "X=x*(44./18); #mass ratio of CO2 in water\n", "\n", "initial_CO2 = 0.005; #kg CO2/kg H20\n", "G=1000*(initial_CO2-X);\n", "\n", "print \"CO2 given up by 1 cubic meter of water = %f kg CO2/cubic meter H20\"%(G)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "CO2 given up by 1 cubic meter of water = 3.311523 kg CO2/cubic meter H20\n" ] } ], "prompt_number": 6 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.6 page number 27 \n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "\n", "pa1 = 23.6; #VP of ethyl alchohal at 10 degree C\n", "pa3=760. #VP of ethyl alchohal at 78.3 degree C in mm Hg\n", "pb1 = 9.2 #VP of ethyl water at 10 degree C in mm Hg\n", "pb3=332. #VP of ethyl water at 78.3 degree C in mm Hg\n", "\n", "C=(math.log10(pa1/pa3)/(math.log10(pb1/pb3)));\n", "\n", "pb2=149. #VP of water at 60 degree C in mm Hg\n", "\n", "pas=(pb3/pb2);\n", "pa=C*math.log10(pas);\n", "pa2=pa3/(10**pa);\n", "\n", "print \"vapor pressure of ethyl alcholoh at 60 degree C = %f mm Hg\"%(pa2)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "vapor pressure of ethyl alcholoh at 60 degree C = 349.872551 mm Hg\n" ] } ], "prompt_number": 7 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.7 page number 28 \n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "t1 = 41. #in degree C\n", "t2=59. #in degree C\n", "theta_1 =83. #in degree C\n", "theta_2=100. #in degree C\n", "\n", "K = (t1-t2)/(theta_1-theta_2);\n", "t=59+(K*(104.2-100));\n", "\n", "print \"boiling point of SCl2 at 880 Torr = %f degree celcius\"%(t)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "boiling point of SCl2 at 880 Torr = 63.447059 degree celcius\n" ] } ], "prompt_number": 8 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.8 page number 29\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "\n", "vp_C6H6 = 520. #in torr\n", "vp_H2O = 225. #in torr\n", "mass_water=18.\n", "mass_benzene=78.\n", "\n", "amount_of_steam = (vp_H2O/vp_C6H6)/(mass_benzene/mass_water);\n", "\n", "print \"amount of steam = %f\"%( amount_of_steam)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "amount of steam = 0.099852\n" ] } ], "prompt_number": 9 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.9 page number 30\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "\n", "p0b = 385. #vapor pressue of benzene at 60 degree C in torr\n", "p0t=140. #vapor pressue of toluene at 60 degree C in torr\n", "xb=0.4;\n", "xt=0.6;\n", "\n", "pb=p0b*xb;\n", "pt=p0t*xt;\n", "P=pb+pt;\n", "\n", "print \"total pressure = %.0f torr\"%(P)\n", "\n", "yb=pb/P;\n", "yt=pt/P;\n", "print \"vapor composition of benzene = %f vapor composition of toluene = %f\"%(yb,yt)\n", "\n", "x=(760.-408)/(1013-408);\n", "print \"mole fraction of benzene in liquid mixture = %.3f mole fraction of toluene in liquid mixture= %.3f\"%(x,1-x)\n", "print \"Thus, the liquid mixture contained %.1f mole %% benzene and %.1f mole %% toluene\"%(x*100,(1-x)*100)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "total pressure = 238 torr\n", "vapor composition of benzene = 0.647059 vapor composition of toluene = 0.352941\n", "mole fraction of benzene in liquid mixture = 0.582 mole fraction of toluene in liquid mixture= 0.418\n", "Thus, the liquid mixture contained 58.2 mole % benzene and 41.8 mole % toluene\n" ] } ], "prompt_number": 3 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.10 page number 33\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "\n", "sigma_x=23.393;\n", "sigma_y=-12.437;\n", "sigma_x2=91.456\n", "sigma_xy=-48.554;\n", "\n", "m=((6*sigma_xy)-(sigma_x*sigma_y))/(6*sigma_x2-(sigma_x)**2);\n", "print \"m = %f \"%(m)\n", "\n", "c=((sigma_x2*sigma_y)-(sigma_xy*sigma_x))/(6*sigma_x2-(sigma_x)**2);\n", "print \"c = %f \"%(c)\n", "\n", "print \"f=0.084*Re**-0.256\"\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "m = -0.256233 \n", "c = -1.073825 \n", "f=0.084*Re**-0.256\n" ] } ], "prompt_number": 21 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.11 page number 35\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math\n", "from numpy import *\n", "from matplotlib.pyplot import * \n", "\n", "%matplotlib inline\n", "\n", "u = array([2,1.92,1.68,1.28,0.72,0]);\n", "r = array([0,1,2,3,4,5]);\n", "\n", "z = u*r;\n", "plot(r,z)\n", "suptitle(\"variation of ur with r\")\n", "xlabel(\"r\")\n", "ylabel(\"ur\")\n", "show()\n", "u_avg = (2./25)*12.4\n", "\n", "print \"average velocity = %f cm/s\"%(u_avg)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Populating the interactive namespace from numpy and matplotlib\n" ] }, { "output_type": "stream", "stream": "stderr", "text": [ "WARNING: pylab import has clobbered these variables: ['draw_if_interactive', 'new_figure_manager']\n", "`%pylab --no-import-all` prevents importing * from pylab and numpy\n" ] }, { "metadata": {}, "output_type": "display_data", "png": 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5PBzvAHj4YcdfsbZs8dlTEpHCtbQAt98OvPMO4GafpUc43vFA605+Xp7UlRCR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\nFOT/AdQ5DLwCjsLdAAAAAElFTkSuQmCC\n", "text": [ "" ] }, { "output_type": "stream", "stream": "stdout", "text": [ "average velocity = 0.992000 cm/s\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.12 page number 37\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "\n", "import math \n", "\n", "n = 6.;\n", "h = (3. - 0)/n;\n", "\n", "I = (h/2.)*(0+2*0.97+2*1.78+2*2.25+2*2.22+2*1.52+0);\n", "u_avg = (2./3**2)*I;\n", "\n", "print \"average velocity = %f cm/s\"%(u_avg)\n", "\n", "print ('Simpsons rule')\n", "\n", "n = 6.;\n", "h = 3./n;\n", "I = (h/3)*(0+4*(0.97+2.25+1.52)+2*(1.78+2.22)+0);\n", "u_avg = (2./3**2)*I;\n", "\n", "print \"average velocity = %f cm/s\"%(u_avg)\n", "\n", "\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "average velocity = 0.971111 cm/s\n", "Simpsons rule\n", "average velocity = 0.998519 cm/s\n" ] } ], "prompt_number": 23 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.13 page number 38\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "\n", "z0 = 30.84;\n", "z1 = 29.89;\n", "z2 = 29.10;\n", "h = 4;\n", "\n", "u1_t0 = (-3*z0+4*z1-z2)/(2*h);\n", "u1_t4 = (-z0+z2)/(2*h);\n", "u1_t8 = (z0-4*z1+3*z2)/(2*h);\n", "\n", "z0 = 29.89;\n", "z1 = 29.10;\n", "z2 = 28.30;\n", "u2_t4 = (-3*z0+4*z1-z2)/(2*h);\n", "u2_t8 = (-z0+z2)/(2*h);\n", "u2_t12 = (z0-4*z1+3*z2)/(2*h);\n", "\n", "z0 = 29.10;\n", "z1 = 28.30;\n", "z2 = 27.50;\n", "u3_t8 = (-3*z0+4*z1-z2)/(2*h);\n", "u3_t12 = (-z0+z2)/(2*h);\n", "u3_t16 = (z0-4*z1+3*z2)/(2*h);\n", "\n", "u_t4 = (u1_t4+u2_t4)/2;\n", "u_t8 = (u1_t8+u2_t8+u3_t8)/3;\n", "u_t12 = (u2_t12+u3_t12)/2;\n", "\n", "print \"u_t0 = %f cm/min u_t4 = %f cm/min u_t8 = %f cm/min u_t12 = %f/n cm/min u_t16 =%f/n cm/min \"%(u1_t0,u_t4,u_t8,u_t12,u3_t16)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "u_t0 = -0.257500 cm/min u_t4 = -0.206875 cm/min u_t8 = -0.192083 cm/min u_t12 = -0.200625/n cm/min u_t16 =-0.200000/n cm/min \n" ] } ], "prompt_number": 24 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.16 page number 49\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "\n", "density_water=988. #in kg/m3\n", "viscosity_water=55.*10**-5 #in Ns/m2\n", "density_air=1.21 #in kg/m3\n", "viscosity_air=1.83*10**-5 #in Ns/m2\n", "L=1 #length in m\n", "\n", "\n", "L1=10.*L #length in m\n", "Q=0.0133;\n", "\n", "Q1=((Q*density_water*viscosity_air*L)/(L1*viscosity_water*density_air))\n", "\n", "print \"flow rate = %f cubic meter/s\"%(Q1)\n", "\n", "\n", "p=9.8067*10**4; #pressure in pascal\n", "p1=(p*density_water*Q**2*L**4)/(density_air*Q1**2*L1**4);\n", "\n", "print \"pressure drop corresponding to 1kp/square cm = %f kP/square cm\"%(p1/p)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "flow rate = 0.036134 cubic meter/s\n", "pressure drop corresponding to 1kp/square cm = 0.011062 kP/square cm\n" ] } ], "prompt_number": 25 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.17 page number 50\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "\n", "L=1. #length of prototype in m\n", "L1=10*L #length of model in m\n", "density_prototype=2.65 #gm/cc\n", "density_water=1. #gm/cc\n", "\n", "density_model=(L**3*(density_prototype-density_water))/(L1**3)+1;\n", "\n", "print \"specific gravity of plastic = %f\"%(density_model)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "specific gravity of plastic = 1.001650\n" ] } ], "prompt_number": 26 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.18 page number 53\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "from numpy import linspace\n", "from matplotlib.pyplot import *\n", "\n", "\n", "ly = 8 #in cm\n", "my = ly/((1/0.25) - (1/0.5));\n", "lz = 10.15 #in cm\n", "\n", "mz = lz/((1./2.85) - (1/6.76));\n", "mx = (my*mz)/(my+mz);\n", "print \"mx = %f cm\"%(mx)\n", "err = ((1-0.9945)/0.9945)*100;\n", "print \"error = %f \"%(err)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "mx = 3.703774 cm\n", "error = 0.553042 \n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 3, "metadata": {}, "source": [ "example 1.19 page number 54\n" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "import math \n", "\n", "w=450. #in kg/hr\n", "density=1000. #in kg/m3\n", "d=16. #in mm\n", "\n", "u=(w/density)/(3.14*d**2/4);\n", "Re=u*density*d/0.001;\n", "\n", "if Re>2100:\n", " print \"flow is turbulent and d= %f mm\"%(d)\n", "else:\n", " print (\"flow is laminar and this nomograph is not valid\")\n", "\n", " " ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "flow is turbulent and d= 16.000000 mm\n" ] } ], "prompt_number": 28 }, { "cell_type": "code", "collapsed": false, "input": [], "language": "python", "metadata": {}, "outputs": [] } ], "metadata": {} } ] }