{ "metadata": { "name": "" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 19 : Semiconductor-Device Physics" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 19.1, Page No 808" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "sg=0.971*10**3 #g/cm^3 specific gravity\n", "w=22.99*1.66*10**-27 # Weight of a sodium atom\n", "\n", "#Calculations\n", "n=sg/w\n", "Ef=3.64*10**-19*(n**(2.0/3))\n", "\n", "#Results\n", "print(\"The value of n is %.2f /m^3 x 10^28 \" %(n/10**28))\n", "print(\"The value of Ef is %.2f eV\" %(Ef))" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The value of n is 2.54 /m^3 x 10^28 \n", "The value of Ef is 3.15 eV\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 19.2, Page No 810" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "E=0.05 #eV\n", "\n", "#Calculations\n", "NE=6.82*10**27*(E**(1.0/2))\n", "\n", "#Results\n", "print(\"The value of NE is %.2f X 10^27 /m^3 \" %(NE/10**27))" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The value of NE is 1.52 X 10^27 /m^3 \n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 19.3, Page No 812" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "KE=0.26*1.6*10**-19 #j kinetic energy\n", "m=9.18*10**-31\n", "\n", "#Calculations\n", "Vav=math.sqrt((2.0*KE)/m)\n", "\n", "#Results\n", "print(\"The value of Vav is %.2f x 10^5\" %(Vav/10**5))" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The value of Vav is 3.01 x 10^5\n" ] } ], "prompt_number": 3 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 19.4, Page No 815" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "ni1=1.5*10**10 #cm^3\n", "T2=873.0 #k\n", "T1=300.0 #k\n", "Eg0=1.0\n", "\n", "\n", "\n", "#Calculations\n", "ni2=math.sqrt((ni1**2)*(T2/T1)*math.exp((1.21/8.625*10**-5)*(-(1/T2)+(1/T1))))\n", "\n", "#Results\n", "print(\"The value of ni2 is %.2f x 10^17 cm^3\" %(ni2/10**10))" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The value of ni2 is 2.56 x 10^17 cm^3\n" ] } ], "prompt_number": 4 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 19.5, Page No 817" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "kT=0.026\n", "Nc=2.89*10**19\n", "Nd=10**16\n", "\n", "#Calculations\n", "Ef=kT*(math.log((Nc/Nd),2))\n", "\n", "#Results\n", "print(\"The value of Ef is %.2f eV\" %(Ef))" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The value of Ef is 0.30 eV\n" ] } ], "prompt_number": 5 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 19.6, Page No 830" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "\n", "#initialisation of variables\n", "I1=1.0 #mA\n", "Vt=26.0 #mV\n", "tP=10**-6\n", "\n", "#Calculations\n", "g=(I1/Vt)\n", "Cd=(g*tP)/2\n", "\n", "#Results\n", "\n", "print(\"The value of Cd is %.2f nF\" %(Cd*10**9))\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The value of Cd is 19.23 nF\n" ] } ], "prompt_number": 6 } ], "metadata": {} } ] }