{
"metadata": {
"name": "",
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"worksheets": [
{
"cells": [
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<h1>Chapter 6: Level<h1>"
]
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<h3>Example 6.1,Page Number:370<h3>"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#(a)\n",
"\n",
"# variable declaration\n",
"p=1.5 # pressure applied\n",
"a=4.0 # mA corresponds to 0 kg/cm^2\n",
"b=20.0 # mA corresponds to 2 kg/cm^2\n",
"\n",
"#calculation\n",
"wh=(((b-a)/2)*p)+a\n",
"\n",
"#result\n",
"print('(a)just at the bottom level of the tank')\n",
"print('Water head applied to the transmitter =%d mA'%wh)\n",
"\n",
"#(b)\n",
"\n",
"#calculation\n",
"wh2=(((b-a)/2)*p)+2*a\n",
"\n",
"#result\n",
"print('\\n\\n(b)5m below the bottom of the tank')\n",
"print('Water head applied to the transmitter =%d mA' %wh2)\n",
"\n",
"#(c)\n",
"\n",
"#calculation\n",
"wh3=(((b-a)/2)*p)\n",
"\n",
"#result\n",
"print('\\n\\n(c)5m above the bottom of the tank')\n",
"print('Water head applied to the transmitter =%d mA'%wh3)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a)just at the bottom level of the tank\n",
"Water head applied to the transmitter =16 mA\n",
"\n",
"\n",
"(b)5m below the bottom of the tank\n",
"Water head applied to the transmitter =20 mA\n",
"\n",
"\n",
"(c)5m above the bottom of the tank\n",
"Water head applied to the transmitter =12 mA"
]
}
],
"prompt_number": 1
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<h3>Example 6.2, Page Number:371<h3>"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#(a)\n",
"\n",
"#variable declaration\n",
"b=20.0 # Maximum output\n",
"a=4.0 # minimum output \n",
"op=16.0 # output in mA\n",
"\n",
"#calculation\n",
"p=(op-a)*2/(b-a)\n",
"p_h=p*10.0\n",
"h=p_h-2-5\n",
"\n",
"#result\n",
"print('(a)\\nh = %dm'%h)\n",
"\n",
"#(b)\n",
"\n",
"#variable declaration\n",
"p1=1 # pressure applied\n",
"\n",
"#calculation\n",
"t_op=((b-a)/2)*p1+4\n",
"\n",
"#result\n",
"print('\\n(b)\\nTransmitter output =%d mA'%t_op)\n",
"\n",
"#(c)\n",
"\n",
"#variable declaration\n",
"p2=0.5 # applied pressure\n",
"\n",
"#calculation\n",
"t_op1=((b-a)/2)*p2+4\n",
"\n",
"#result\n",
"print('\\n(c)\\nTransmitter output =%d mA'%t_op1)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a)\n",
"h = 8m\n",
"\n",
"(b)\n",
"Transmitter output =12 mA\n",
"\n",
"(c)\n",
"Transmitter output =8 mA"
]
}
],
"prompt_number": 2
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<h3>Example 6.3, Page Number: 372<h3>"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#(a)\n",
"\n",
"#variable declaration\n",
"b=20.0 # Maximum output\n",
"a=4.0 # minimum output\n",
"op=16.0 # actual output \n",
"wt_l1=25.0 # water level (i)\n",
"\n",
"#calculation\n",
"t_op=((b-a)/100)*(100-75)+4\n",
"\n",
"#result\n",
"print('(a)\\nWater level=+25cm\\nTransmitter output = %d mA' %t_op)\n",
"\n",
"#(b)\n",
"\n",
"#calculation\n",
"wt_l2=-25.0 # water level (ii)\n",
"t_op2=((b-a)/100)*(100-25)+4\n",
"\n",
"#result\n",
"print('\\n(b)\\nWater level=-25cm\\nTransmitter output = %d mA' %t_op2)\n",
"\n",
"#(c)\n",
"\n",
"#Variable declaration\n",
"t_op3=12.0 # Transmitter output \n",
"\n",
"#calculation\n",
"H=(100.0/(b-a))*(12-4) \n",
"\n",
"#result\n",
"print('\\n(c)\\nHead Applied = %d cm\\nLevel corresponding to 50 cm head =0 cm' %H)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a)\n",
"Water level=+25cm\n",
"Transmitter output = 8 mA\n",
"\n",
"(b)\n",
"Water level=-25cm\n",
"Transmitter output = 16 mA\n",
"\n",
"(c)\n",
"Head Applied = 50 cm\n",
"Level corresponding to 50 cm head =0 cm"
]
}
],
"prompt_number": 3
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<h3>Example 6.4, Page Number: 373<h3>"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#(a)\n",
"\n",
"#variable declaration\n",
"a=5.0*10**-4 #area\n",
"l=8.0 #length\n",
"dens=6.0*1000.0 #density\n",
"\n",
"#calculation\n",
"w=a*l*dens\n",
"\n",
"#result\n",
"print('(a)\\nWeight of the displacer if weighed in air = %d kg'%w)\n",
"\n",
"\n",
"#(i)\n",
"\n",
"#variable declaration\n",
"sbr1=23.0 # spring balance reading\n",
"\n",
"#calculation\n",
"wloss1=w-sbr1\n",
"L1=wloss1/(1000.0*a)\n",
"\n",
"#result\n",
"print('\\n(i)\\tL1=%dm'%L1)\n",
"\n",
"\n",
"#(ii)\n",
"\n",
"#variable declaration\n",
"sbr2=22.0 # spring balance reading\n",
"\n",
"#calculation\n",
"wloss2=w-sbr2\n",
"L2=wloss2/(1000.0*a)\n",
"\n",
"#result\n",
"print('\\n(ii)\\tL2=%dm'%L2)\n",
"\n",
"#(iii)\n",
"\n",
"#variable declaration\n",
"sbr3=21.0 # spring balance reading\n",
"\n",
"#calculation\n",
"wloss3=w-sbr3\n",
"L3=wloss3/(1000.0*a)\n",
"\n",
"#result\n",
"print('\\n(iii)\\tL3=%dm'%L3)\n",
"\n",
"#(b)\n",
"\n",
"#variable declaration\n",
"level=8.0 # level wen tank is full \n",
"\n",
"#calculation\n",
"wt=a*level*1000.0\n",
"spring=w-wt\n",
"\n",
"#result\n",
"print('\\n(b):when the tank is full\\nSpring Balance reading = %d kg'%spring)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"(a)\n",
"Weight of the displacer if weighed in air = 24 kg\n",
"\n",
"(i)\tL1=2m\n",
"\n",
"(ii)\tL2=4m\n",
"\n",
"(iii)\tL3=6m\n",
"\n",
"(b):when the tank is full\n",
"Spring Balance reading = 20 kg"
]
}
],
"prompt_number": 4
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<h3>Example 6.5, Page Number: 374<h3>"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#variable declaration\n",
"rho=1000.0 # density of water \n",
"v=3.0 # displaced volume of water \n",
"\n",
"#calculation\n",
"Bw=rho*v\n",
"\n",
"#Result\n",
"print('Buoyance Force(Bw) = %d kg'%Bw)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Buoyance Force(Bw) = 3000 kg"
]
}
],
"prompt_number": 5
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<h3>Example 6.6, Page Number: 374<h3>"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#variable declaration\n",
"rho=1000.0 # density of water\n",
"Bw=5000.0 # Buoyancy Force\n",
"\n",
"#calculation\n",
"v=Bw/rho\n",
"\n",
"#result\n",
"print('V = %d m^3' %v)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"V = 5 m^3"
]
}
],
"prompt_number": 6
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<h3>Example 6.7, Page Number: 374<h3>"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#variable declaration\n",
"rho=1000.0 # density of water\n",
"h=10.0 # height of liquid\n",
"\n",
"#calculation\n",
"P=rho*h\n",
"\n",
"#result\n",
"print('P = %d kg/m^2 = %d kg/cm^2 '%(P,P/10000))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"P = 10000 kg/m^2 = 1 kg/cm^2 "
]
}
],
"prompt_number": 7
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<h3>Example 6.8, Page Number: 374<h3>"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#variable declaration\n",
"rho=1000.0 # density of water\n",
"h=15.0 # height of liquid \n",
"ex_p=1.0 # External pressure on liquid\n",
"\n",
"#calculation\n",
"P=(rho*h/10000.0)+ex_p\n",
"\n",
"#result\n",
"print('P = %.1f kg/cm^2' %P)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"P = 2.5 kg/cm^2"
]
}
],
"prompt_number": 8
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<h3>Example 6.9, Page Number:374<h3>"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#variable declaration\n",
"rho=1000.0 # density of water\n",
"ex_p=0.5*10**4 # External pressure on liquid \n",
"P=1.6*10**4 #(rho*h/10000)+ex_p\n",
"\n",
"#calculation\n",
"h=(P-ex_p)/1000.0\n",
"\n",
"#result\n",
"print('h = %d m' %h)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"h = 11 m"
]
}
],
"prompt_number": 9
},
{
"cell_type": "markdown",
"metadata": {},
"source": [
"<h3>Example 6.10, Page Number:375<h3>"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"#variable declaration\n",
"c2=100.0*10**-6 # capacitance in capacitance probe\n",
"r1=10.0*10**3 # value of resistor in bride\n",
"r2=100.0*10**3 # value of resistor in bride\n",
"r3=50.0*10**3 # value of resistor in bride\n",
"\n",
"#calculation\n",
"Cx=r1*c2/r3\n",
"Cx=Cx*10**6\n",
"\n",
"#result\n",
"print('Cx = %d microFarad'%Cx)\n",
"c=5.0\n",
"\n",
"#calculation\n",
"l=Cx/c\n",
"\n",
"#result\n",
"print('\\nLevel on the probe = %dm'%l)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Cx = 20 microFarad\n",
"\n",
"Level on the probe = 4m"
]
}
],
"prompt_number": 10
}
],
"metadata": {}
}
]
}