{ "metadata": { "name": "" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 10 : Thermodynamic relations" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 10.1 pageno: 329" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "# Variables\n", "t = 289.6;\t\t\t#temperature in K\n", "dt = 0.0244;\t\t\t#raise in temperature in deg.C\n", "v1 = 0.00095;\t\t\t#volume occupied in liquid state in litres\n", "v2 = 0.00079;\t\t\t#volume occupied in solid state in litres\n", "\n", "# Calculations\n", "l = t*(v1-v2)/dt;\t\t\t#latent heat of fusion in lit.atm\n", "\n", "# Result\n", "print 'the latent heat of fusion is %3.2f lit.atm'%(l)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "the latent heat of fusion is 1.90 lit.atm\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 10.2 pageno : 329" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "# Variables\n", "t = 295. \t\t\t#temperature of water in K\n", "dp = 10**6.\t \t\t#cahnge in pressure in dyne/sq.cm\n", "j = 4.2*10**7;\t\t\t#joules constant in ergs/cal\n", "\n", "# Calculations\n", "dc = -t*10**-5*dp/j;\t\t\t#change in specific heat\n", "\n", "# Result\n", "print 'the change in specific heat is %.e cal/degree'%(dc)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "the change in specific heat is -7e-05 cal/degree\n" ] } ], "prompt_number": 3 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 10.3 pageno: 329" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "# Variables\n", "cp = 0.0909\t \t\t#specific heat at consmath.tant pressure in cal/degree\n", "t = 273;\t\t \t#temperature in K\n", "v = 0.112;\t\t\t #specific volume in lit/deg.C\n", "a = 5.01*10**(-6);\t\t#coefficient of linear expansion\n", "k = 8*10**-7;\t\t\t#compressibility of copper in per atoms\n", "\n", "# Calculations\n", "cv = cp+(9*a**2*v*t*0.024142*10**3/k);\t\t\t#specific heat at constant volume in cal/deg.C\n", "\n", "# Result\n", "print 'specific heat at constant volume is %3.2f cal/deg.C'%(cv)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "specific heat at constant volume is 0.30 cal/deg.C\n" ] } ], "prompt_number": 4 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 10.5 pageno : 331" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "# Variables\n", "t = 289.6;\t\t\t#temperature in K\n", "dt = 0.0244;\t\t\t#raise in temperature in deg.C\n", "v1 = 0.00095;\t\t\t#volume occupied in liquid state in litres\n", "v2 = 0.00079;\t\t\t#volume occupied in solid state in litres\n", "\n", "# Calculations\n", "l = t*(v1-v2)/dt;\t\t\t#latent heat of fusion in lit.atm\n", "\n", "# Result\n", "print 'the latent heat of fusion is %3.3f lit.atm'%(l)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "the latent heat of fusion is 1.899 lit.atm\n" ] } ], "prompt_number": 5 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 10.6 pageno : 331" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "# Variables\n", "l = 539;\t\t\t#latent heat of water at 100deg.C in cal\n", "j = 4.2*10**7;\t\t\t#joules constant in ergs/cal\n", "t = 373;\t\t\t#temperature of water in K\n", "v2 = 1670;\t\t\t#volume of steam formed in cc\n", "v1 = 1;\t\t\t#intial volume in cc\n", "g = 981;\t\t\t#acceleration due to gravity in cm/sec**2\n", "d = 13.6;\t\t\t#specific gravity of hg\n", "\n", "# Calculations\n", "dp = l*j/(t*(v2-v1)*g*d);\t\t\t#rate of change of saturation pressure in cm of mercury\n", "\n", "# Result\n", "print 'the rate of change of saturation pressure is %3.1f cm of hg'%(dp)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "the rate of change of saturation pressure is 2.7 cm of hg\n" ] } ], "prompt_number": 6 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 10.7 pageno : 331" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "# Variables\n", "p1 = 77.371;\t\t\t#pressure at 100.5deg.C in cm of hg\n", "p2 = 74.650;\t\t\t#pressure at 99.5deg.C in cm of hg\n", "g = 981;\t\t\t#universal gas constant in cm/sec**2\n", "d = 13.6;\t\t\t#specific gravity\n", "l = 537;\t\t\t#latent heat of vapourisation in cal/gm\n", "t = 373;\t\t\t#temperature of water in K\n", "j = 4.2*10**7;\t\t\t#joules constant in ergs/cal\n", "v1 = 1;\t\t\t#intial volume in cc\n", "\n", "# Calculations\n", "v2 = v1+(l*j/(t*(p1-p2)*g*d));\t\t\t#volume of gram of steam at 100deg.C in cc\n", "\n", "# Result\n", "print 'volume of gram of steam at 100deg.C is %.f cc'%(v2)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "volume of gram of steam at 100deg.C is 1667 cc\n" ] } ], "prompt_number": 8 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 10.8 pageno : 332" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "# Variables\n", "t = 350;\t\t\t#boiling point temperature in K\n", "l = 46;\t\t\t#latent heat of vapourisation in cal/gm\n", "v1 = 1/1.6;\t\t\t#intial volume in cc\n", "dp = 2.3;\t\t\t#change in pressure with temperature in cm of hg/deg.C\n", "d = 13.6;\t\t\t#specific gravity of mercury\n", "g = 981;\t\t\t#acceleration due to gravity in cm/sec**2\n", "j = 4.2*10**7;\t\t\t#joukes constant in ergs/cal\n", "\n", "#CALCULTIONS\n", "v2 = v1+(l*j)/(t*dp*d*g);\t\t\t#specific volume in cc\n", "\n", "# Result\n", "print 'specific volume of vapour of carbon is %3.3f cc'%(v2)\n", "print \"Note : Answer is slightly different because of rounding error\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "specific volume of vapour of carbon is 180.513 cc\n", "Note : Answer is slightly different because of rounding error\n" ] } ], "prompt_number": 9 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 10.9 pageno : 332" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "# Variables\n", "l = 536.;\t\t\t#latent heat of vapourisation in cal/gm\n", "v1 = 1.;\t\t\t#volume of 1 gm of water in cc\n", "v2 = 1600.;\t\t\t#volume of steam in cc\n", "t = 373.;\t\t\t#boiling point of water in K\n", "p = 1.;\t\t\t#pressure in cm of hg\n", "d = 13.6;\t\t\t#specific gravity of mercury\n", "g = 981.;\t\t\t#gravitational constant in cm/sec**2s/cal\n", "j = 4.2*10**7;\t\t\t#joules constant in erg/cal\n", "\n", "# Calculations\n", "dt = (t*(v2-v1)*d*g)/(l*j);\t\t\t#change in temperature in deg.C\n", "\n", "# Result\n", "print 'change in temperature is %3.2f deg.C'%(dt)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "change in temperature is 0.35 deg.C\n" ] } ], "prompt_number": 10 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 10.10 page no : 332" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "# Variables\n", "t = 353;\t\t\t#temperature in K\n", "p = 76*13.6*981;\t\t\t#pressure in dynes/sq.cm\n", "v = 0.146;\t\t\t#specific volume in cc/kg\n", "l = 35.6;\t\t\t#latent heat of fusion in cal/gm\n", "j = 4.18*10**7;\t\t\t#joules constant in ergs/cal\n", "\n", "# Calculations\n", "dt = t*p*v/(l*j);\t\t\t#change in melting point per atmosphere\n", "\n", "# Result\n", "print 'the rate of change in melting point is %.3f per atmosphere'%(dt)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "the rate of change in melting point is 0.035 per atmosphere\n" ] } ], "prompt_number": 12 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 10.11 pageno : 333" ] }, { "cell_type": "code", "collapsed": false, "input": [ "\n", "# Variables\n", "l = 79.6*4.18*10**7;\t\t\t#latent heat of water in ergs/gm\n", "t = 273.16;\t\t\t#temperature of water in K\n", "v1 = 1.0001;\t\t\t#specific volume of water at 0deg.C in cc\n", "v2 = 1.0908;\t\t\t#specific volume of ice at 0deg.C in cc\n", "p = 1.013*10**6;\t\t\t#pressure of atmosphere in dyne/sq.cm\n", "\n", "# Calculations\n", "dt = t*(v1-v2)*p/l;\t\t\t#change in freezing point of water in deg.C\n", "\n", "# Result\n", "print 'change in freezing point of water is %3.4f deg.C'%(dt)\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "change in freezing point of water is -0.0075 deg.C\n" ] } ], "prompt_number": 1 } ], "metadata": {} } ] }