{
"metadata": {
"name": "",
"signature": "sha256:04bb97393d5fbbef8189e63f66336b0ac299ced6d9fe7802df79f548f7068027"
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"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 9 : Reciprocating Pump"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 9.1 Page No : 191"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math \n",
"\n",
"# Variables\n",
"D = 0.15 # cm\n",
"S = 0.25 # cm\n",
"N = 50. # r.p.m\n",
"Hs = 5. # m\n",
"Hd = 15 # m\n",
"ns = .6 \n",
"deltaD = 0.75\n",
"w = 9810.\n",
"\n",
"# Calculations \n",
"suction = w*math.pi*D**2*Hs/(4*ns) \n",
"delivery = (w*math.pi*D**2*Hd)/(4*deltaD)\n",
"p_required = ((suction+delivery)*S*N)/(1000*60)\n",
"\n",
"\n",
"# Results \n",
"print \"Power required by the pump : %.4f kW\"%p_required\n",
"\n",
"# note : book answer is wrong."
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Power required by the pump : 1.0233 kW\n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 9.2 page no : 192"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"# Variables\n",
"D = 0.18\n",
"s = 0.36\n",
"Hs = 3.\n",
"Hd = 45.\n",
"N = 50.\n",
"n = 0.85\n",
"\n",
"# Calculations \n",
"a = math.pi*D*D/4\n",
"Q = (2*a*s*N)/60\n",
"g = 9.81\n",
"w = g*1000\n",
"P = w*Q*(Hs+Hd)/(n*1000)\n",
"\n",
"# Results \n",
"print \"power in kw required to drive the pump : %.3f\"%P\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"power in kw required to drive the pump : 8.458\n"
]
}
],
"prompt_number": 8
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 9.3 pageno : 192"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"# Variables\n",
"D = 0.15\n",
"s = 0.3\n",
"Hs = 3.\n",
"Hd = 30.\n",
"n = 0.8\n",
"a = math.pi*D*D/4\n",
"N = 60./60\n",
"w = 9810.\n",
"Q = 0.62/60\n",
"\n",
"# Calculations \n",
"Qth = (2*a*s*N)\n",
"slip = (Qth-Q)/Qth\n",
"power = (w*Qth*(Hs+Hd))/(1000*n)\n",
"\n",
"# Results \n",
"print \"power in Kw required to drive the pump : %.2f kW \\\n",
"\\npercentage slip : %.3f %%\"%(round(power,2),round((slip*100),2))\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"power in Kw required to drive the pump : 4.29 kW \n",
"percentage slip : 2.540 %\n"
]
}
],
"prompt_number": 10
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 9.4 Page No : 193"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"# Variables\n",
"D = 0.15 #mm\n",
"s = 0.3 #mm \n",
"N = 50./60 #r.p.m \n",
"H = 25. #m, height\n",
"Qact = 0.0042 #liter/s \n",
"Ld = 22. #m long \n",
"d = 0.1 #mm \n",
"\n",
"# Calculations \n",
"a = math.pi*D*D/4\n",
"Qth = a*s*N\n",
"w = 9810\n",
"power = w*Qth*H/1000\n",
"slip = (Qth-Qact)/Qth\n",
"W = 2*math.pi*N\n",
"a1 = math.pi*d*d/4\n",
"g = 9.81\n",
"Had = (Ld*a*W*W*s)/(g*a1*2)\n",
"\n",
"# Results \n",
"print \"theoritical discharge : %.8f m**3/s \\\n",
"\\ntheoritical power : %.5f kW \\\n",
"\\npercentage slip : %.2f %% \\\n",
"\\nacceleration head : %.2f m\"%(Qth,round(power,5),round((slip*100),2),round(Had,2))\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"theoritical discharge : 0.00441786 m**3/s \n",
"theoritical power : 1.08348 kW \n",
"percentage slip : 4.93 % \n",
"acceleration head : 20.75 m\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 9.5 Page No : 194"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"# Variables\n",
"s = 0.15 #m, strok length\n",
"Ls = 7. #7 pipe\n",
"ds = 0.075 #cylinder \n",
"N = 75./60 \n",
"Hs = 2.5 #m, water level\n",
"z = 16./9 \n",
"f = 0.01\n",
"W = 2*math.pi*N\n",
"g = 9.81\n",
"\n",
"# Calculations \n",
"Has = Ls*z*W*W*ds/g\n",
"H = Hs+Has\n",
"H1 = Has-Hs\n",
"Hfs = (4*f*Ls/(ds*2*g))*((z*W*ds)**2)\n",
"H2 = Hfs+Hs\n",
"\n",
"# Results \n",
"print \"pressure head:beginning of suction stroke : %.4f m \\\n",
"\\nend of the suction stroke : %.4f m \\\n",
"\\nmiddle of the suction stroke : %.4f m\"%(round(H,4),round(H1,4),round(H2,4))\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"pressure head:beginning of suction stroke : 8.3688 m \n",
"end of the suction stroke : 3.3688 m \n",
"middle of the suction stroke : 2.7087 m\n"
]
}
],
"prompt_number": 13
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 9.6 Page No : 196"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"# Variables\n",
"D = 0.08 #m diameter\n",
"s = 0.15 #m stroke \n",
"Hs = 3. # water for sump\n",
"ds = 0.03 #diameter \n",
"g = 9.81 \n",
"Ls = 4.5 \n",
"p = 78.86*(1000) #kN/m**2 \n",
"w = 9810. \n",
"W = 2*math.pi/60\n",
"\n",
"# Calculations \n",
"z = (D/ds)**2\n",
"Hsep = p/w\n",
"Habs = 10.3-Hsep\n",
"Has = Hsep-Hs\n",
"N = ((Has*g*2)/(z*W*W*s*Ls))**0.5\n",
"\n",
"# Results \n",
"print \"maximium speed in rpm at which may run without separation\",round(N,2),\"r.p.m\"\n",
"\n",
"# note : rounding off error"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"maximium speed in rpm at which may run without separation 43.34 r.p.m\n"
]
}
],
"prompt_number": 16
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 9.7 Page No : 197"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"# Variables\n",
"Hs = 5.\n",
"Ls = 10.\n",
"D = 0.15 #m diameter\n",
"d = 0.1 \n",
"N = 30./60\n",
"s = 0.15 #m delivery head\n",
"g = 9.81\n",
"W = 2*math.pi*N\n",
"w = 9810.\n",
"ha = 10.3\n",
"\n",
"# Calculations \n",
"z = (D/d)**2\n",
"H = (Ls*z*W*W*s/g)\n",
"Ph = Hs+H\n",
"Phabs = ha-Ph\n",
"f = 0.01\n",
"Hfs = (4*f*Ls/(d*2*g))*((z*W*s)**2)\n",
"H1 = Hs+Hfs\n",
"H1abs = ha-H1\n",
"H2 = Hs-H\n",
"H2abs = ha-H2\n",
"Hd = 15.\n",
"Ld = 25.\n",
"H11 = (Ld*z*W*W*s/g)\n",
"H12 = H11+Hd\n",
"H12abs = ha+H12\n",
"Hfd = (4*f*Ld/(d*2*g))*((z*W*s)**2)\n",
"H22 = Hd+Hfd\n",
"H22abs = ha+H22\n",
"H3 = Hd-H11\n",
"H3abs = ha+H3\n",
"a = 3.142*D*D/4\n",
"Q = a*s*2*N\n",
"power = (w*Q*(Hs+Hd+(0.6666*Hfs)+Hfd*0.6666))/1000\n",
"\n",
"# Results \n",
"print \"pressure head at middle and end of suction stroke\",round(H1abs,4),round(H2abs,4)\n",
"print \"pressure head at beginning,middle,end of suction stroke\",round(H12abs,4),round(H22abs,3),round(H3abs,4)\n",
"print \"power in Kw required to drive the pump\",round(power,3)\n",
"\n",
"# note : rounding off error."
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"pressure head at middle and end of suction stroke 5.0708 8.6955\n",
"pressure head at beginning,middle,end of suction stroke 33.7888 25.873 16.8112\n",
"power in Kw required to drive the pump 0.534\n"
]
}
],
"prompt_number": 17
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}