{ "metadata": { "name": "", "signature": "sha256:c64912256bdcf8bcc5ce71dffc2b43e608072175b592d01f0ff0fe3771ee0132" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "6: Non Destructive Testing" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 6.1, Page number 36" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "t=50; #thickness of metal(mm)\n", "d=1; #hole diameter(mm)\n", "\n", "#Calculation\n", "sp=(d/t)*100; #sensitivity percentage(%)\n", "\n", "#Result\n", "print \"sensitivity percentage of wire is\",sp,\"%\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "sensitivity percentage of wire is 2.0 %\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 6.2, Page number 37" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "I=20*10**-3; #tube current(A)\n", "L=1; #source to film distance(m)\n", "t=60; #exposure time(s)\n", "\n", "#Calculation\n", "ef=I*t/(L**2); #exposure factor\n", "\n", "#Result\n", "print \"exposure factor is\",ef" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "exposure factor is 1.2\n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 6.3, Page number 37" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "IbyI0=20; #reduction in intensity\n", "mew=1.62; #linear absorption coefficient(per cm)\n", "\n", "#Calculation\n", "x=math.log(IbyI0)/mew; #thickness of aluminium(cm)\n", "\n", "#Result\n", "print \"thickness of aluminium is\",round(x,2),\"*10**-2 m\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "thickness of aluminium is 1.85 *10**-2 m\n" ] } ], "prompt_number": 5 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 6.4, Page number 38" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "x=2.5*10**-2; #thickness of material(m)\n", "mew=2; #linear absorption coefficient(per cm)\n", "\n", "#Calculation\n", "\n", "\n", "#Result\n", "print \" \"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ " \n" ] } ], "prompt_number": 7 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 6.5, Page number 38" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "ef=0.35; #exposure factor(curie hour)\n", "pss=5; #present source strength(curie)\n", "\n", "#Calculation\n", "et=ef/pss; #exposure time(h)\n", "\n", "#Result\n", "print \"exposure time is\",et*60,\"min\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "exposure time is 4.2 min\n" ] } ], "prompt_number": 9 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 6.6, Page number 39" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "fd=20*10**-2; #film focus distance(m)\n", "Sd=5*10**-2; #displacement of X-ray tube(m)\n", "t=5*10**-2; #thickness of steel(m)\n", "S=0.5*10**-2; #distance between images(m)\n", "\n", "#Calculation\n", "d=fd*S/(S+Sd); #distance of flow from bottom surface(m)\n", "l=t-d; #location of flow from top surface(m)\n", "\n", "#Result\n", "print \"location of flow from top surface is\",round(l*10**2,1),\"*10**-2 m\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "location of flow from top surface is 3.2 *10**-2 m\n" ] } ], "prompt_number": 12 } ], "metadata": {} } ] }