{ "metadata": { "name": "", "signature": "sha256:ad2a8335720a8ceacd5db30334fb790c6a4c8fa5b69e23fcad6e232d80ed69c2" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "2: Crystal Structure" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 2.1, Page number 29" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "d=6.5*10**3; #density of silver bromide(Kg/m**3)\n", "m=187.8; #molecular weight of silver bromide\n", "\n", "#Calculation\n", "M=(4*m)/(6.022*10**26); #mass of ion in unit cell(kg)\n", "#d=mass of ions in unit cell/volume of unit cell\n", "a=((M/d)**(1/3))*10**10; #lattice parameter(Angstrom)\n", "\n", "#Result\n", "print \"The lattice parameter is\",round(a,2),\"Angstrom\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The lattice parameter is 5.77 Angstrom\n" ] } ], "prompt_number": 3 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 2.2, Page number 29" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "r=2.3; #atomic radius(Angstrom)\n", "\n", "#Calculation\n", "a=(4*r)/math.sqrt(3); \n", "fv=((a)**3-(2*(4/3)*math.pi*r**3))*10**-30; #free volume(m**3)\n", "\n", "#Result\n", "print \"The free volume per unit cell is\",round(fv*10**30,1),\"*10**-30 m**3\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The free volume per unit cell is 47.9 *10**-30 m**3\n" ] } ], "prompt_number": 6 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 2.3, Page number 29" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "k=8.625*10**-5; #Boltzmann constant(eV/K)\n", "#n1000/n500=ln[n1000/n500]=Ev/1000k\n", "Ev=1.08; #average energy required to create a vacancy(eV)\n", "\n", "#Calculation\n", "N=math.exp(Ev/(1000*k)); #ratio of vacancies\n", "\n", "#Result\n", "print \"The ratio of vacancies is\",round(N/10**5,1),\"*10**5\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The ratio of vacancies is 2.7 *10**5\n" ] } ], "prompt_number": 9 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 2.4, Page number 29" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "#n500=N*exp(-Ev/500k)\n", "k=8.625*10**-5; #Boltzmann constant(eV/K)\n", "Ev=0.95; #average energy required to create a vacancy\n", "\n", "#Calculation\n", "n=math.exp(-Ev/(500*k)); #n500/N\n", "\n", "#Result\n", "print \"The ratio of number of vacancies to the number of atoms is\",round(n*10**10,1),\"*10**-10\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The ratio of number of vacancies to the number of atoms is 2.7 *10**-10\n" ] } ], "prompt_number": 12 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 2.5, Page number 30" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "h=1;\n", "k=1;\n", "l=1;\n", "#d(hkl)=a/sqrt(h^2+k^2+l^2) where \"a\" is the lattice parameter\n", "r=0.18; #atomic radius(nm)\n", "\n", "#Calculation\n", "d111=(2*math.sqrt(2)*r)/math.sqrt((h**2)+(k**2)+(l**2)); #spacing(nm)\n", "\n", "#Result\n", "print \"The spacing of (111) planes in a monoatomic structure is\",round(d111,2),\"nm\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The spacing of (111) planes in a monoatomic structure is 0.29 nm\n" ] } ], "prompt_number": 14 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 2.6, Page number 30" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "M=200; #atomic weight \n", "a=5; #lattice parameter(angstrom)\n", "Na=6.022*(10**26);\n", "\n", "#Calculation\n", "rho=(2*M)/(Na*(a*10**-10)**3); #density of the structure(kg/m**3)\n", "\n", "#Result\n", "print \"The density of the bcc structure is\",round(rho/10**3,2),\"*10**3 kg/m**3\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The density of the bcc structure is 5.31 *10**3 kg/m**3\n" ] } ], "prompt_number": 17 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 2.7, Page number 30" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "#Free volume=a^3-[(4/3)*pi*r^3];for sc,a=2r\n", "#Therefore free volume =(2r)^3-[(4/3)*pi*r^3]\n", "fv=30.48*10**-30; #free volume per unit cell(m**3)\n", "\n", "#Calculation\n", "r=(fv/(8-(4/3)*math.pi))**(1/3)*(10**10); #atomic radius(angstrom) \n", "\n", "#Result\n", "print \"The atomic radius is\",round(r),\"Angstrom\" " ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The atomic radius is 2.0 Angstrom\n" ] } ], "prompt_number": 21 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 2.8, Page number 30" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "#free volume=a^3-[2*(4/3)*pi*r^3]\n", "#for bcc a=4r/3^(1/3)\n", "fv=61.72*(10**-30); #free volume(m**3)\n", "\n", "#Calculation\n", "a=-(fv/(1-math.pi*math.sqrt(3))/8)**1/3*10**31; #lattice parameter(angstrom)\n", "\n", "#Result\n", "print \"The lattice parameter is\",round(a,2),\"Angstrom\"\n", "print \"answer in the book varies due to rounding off errors\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The lattice parameter is 5.79 Angstrom\n", "answer in the book varies due to rounding off errors\n" ] } ], "prompt_number": 24 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 2.9, Page number 30" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "rho=9000; #density(kg/m**3)\n", "w=65; #atomic weight\n", "v=1; #volume(m**3)\n", "a=1.4; #average number of free electrons per atom\n", "\n", "#Calculation\n", "n=(rho*v)/(w/(6.022*10**26)); #number of atoms\n", "rhoe=n*a; #density of free electrons per atom(electrons/m**3)\n", "\n", "#Result\n", "print \"The density of free electrons is\",round(rhoe/10**29,3),\"*10**29 electrons/m**3\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The density of free electrons is 1.167 *10**29 electrons/m**3\n" ] } ], "prompt_number": 26 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example number 2.10, Page number 31" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#importing modules\n", "import math\n", "from __future__ import division\n", "\n", "#Variable declaration\n", "h=1;\n", "k=0;\n", "l=1;\n", "d101=0.5; #spacing of (101) plane\n", "\n", "#Calculation\n", "#d101=a/sqrt((h^2)+(k^2)+(l^2))\n", "a=d101*math.sqrt(2) #lattice parameter(Angstrom)\n", "\n", "#Result\n", "print \"The lattice parameter is\",round(a,1),\"Angstrom\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The lattice parameter is 0.7 Angstrom\n" ] } ], "prompt_number": 28 } ], "metadata": {} } ] }