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  "signature": "sha256:064d55405a5d05f007b28f32cf39a9f99d10f303fc4084e2d14d99aaeb87858c"
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 "worksheets": [
  {
   "cells": [
    {
     "cell_type": "heading",
     "level": 1,
     "metadata": {},
     "source": [
      "Physics of Nano Materials"
     ]
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example number 8.1, Page number 320"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      " \n",
      "#import modules\n",
      "import math\n",
      "from __future__ import division\n",
      "\n",
      "#Variable decleration\n",
      "r=5;    #radius in m\n",
      "pi=3.14;\n",
      "\n",
      "#Calculation \n",
      "SA=4*pi*r**2;    #surface area of sphere in m^2\n",
      "V=(4/3)*pi*r**3;   #volume of sphere in m^3\n",
      "R=SA/V;    #ratio\n",
      "#surface area to volume ratio can also be given by 3/radius\n",
      "\n",
      "#Result\n",
      "print(\"surface area to volume ratio of sphere in m-1 is\",R);"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "('surface area to volume ratio of sphere in m-1 is', 0.6)\n"
       ]
      }
     ],
     "prompt_number": 5
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example number 8.2, Page number 321"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      " \n",
      "#import modules\n",
      "import math\n",
      "from __future__ import division\n",
      "\n",
      "#Variable decleration\n",
      "d=26;   #distance in m\n",
      "r=d/2;  #radius in m\n",
      "pi=3.14;\n",
      "\n",
      "#Calculation\n",
      "SA=4*pi*r**2;      #surface area of sphere in m^2\n",
      "V=(4/3)*pi*r**3;   #volume of sphere in m^3\n",
      "R=SA/V;    #ratio\n",
      "R=math.ceil(R*10**3)/10**3;   #rounding off to 3 decimals\n",
      "#surface area to volume ratio can also be given by 3/radius\n",
      "\n",
      "#Result\n",
      "print(\"surface area to volume ratio of sphere in m-1 is\",R);"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "('surface area to volume ratio of sphere in m-1 is', 0.231)\n"
       ]
      }
     ],
     "prompt_number": 7
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example number 8.3, Page number 321"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      " \n",
      "#import modules\n",
      "import math\n",
      "from __future__ import division\n",
      "\n",
      "#Variable decleration\n",
      "r=1;   #radius in m\n",
      "h=1;   #height in m\n",
      "pi=3.14\n",
      "\n",
      "#Calculation\n",
      "V=(1/3)*pi*(r**2)*h;\n",
      "V=math.ceil(V*10**2)/10**2;   #rounding off to 2 decimals\n",
      "\n",
      "#Result\n",
      "print(\"volume of cone in m^3 is\",V); "
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "('volume of cone in m^3 is', 1.05)\n"
       ]
      }
     ],
     "prompt_number": 11
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example number 8.4, Page number 321"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      " \n",
      "#import modules\n",
      "import math\n",
      "from __future__ import division\n",
      "\n",
      "#Variable decleration\n",
      "r=3;   # radius in m\n",
      "h=4;   # height in m\n",
      "pi=3.14\n",
      "\n",
      "#Calculation\n",
      "SA=pi*r*math.sqrt((r**2)+(h**2));\n",
      "TSA=SA+(pi*r**2);\n",
      "\n",
      "#Result\n",
      "print(\"total surface area of cone in m^2 is\",TSA);\n"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "('total surface area of cone in m^2 is', 75.36)\n"
       ]
      }
     ],
     "prompt_number": 16
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example number 8.5, Page number 322"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      " \n",
      "#import modules\n",
      "import math\n",
      "from __future__ import division\n",
      "\n",
      "#Variable decleration\n",
      "V=100;   #volume of cone in cubic inches\n",
      "r=5;   #radius of cone in inches\n",
      "pi=3.14;\n",
      "\n",
      "#Calculation\n",
      "r_m=r*0.0254;    #radius of cone in m\n",
      "#volume V=(1/3)*pi*(r**2)*h\n",
      "#therefore h = (3*V)/(pi*r**2)\n",
      "h=(3*V)/(pi*r**2);   #height in inches\n",
      "R=3/r_m;\n",
      "h=math.ceil(h*10**3)/10**3;   #rounding off to 3 decimals\n",
      "\n",
      "#Result\n",
      "print(\"height of the cone in inches is\",h);\n",
      "print(\"surface area to volume ratio in m-1 is\",R);\n",
      "\n",
      "#answer for the surface area to volume ratio given in the book is wrong"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "('height of the cone in inches is', 3.822)\n",
        "('surface area to volume ratio in m-1 is', 23.62204724409449)\n"
       ]
      }
     ],
     "prompt_number": 18
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [],
     "language": "python",
     "metadata": {},
     "outputs": []
    }
   ],
   "metadata": {}
  }
 ]
}