{ "metadata": { "name": "", "signature": "sha256:5b530b225e354d5204b6b04a92931fcee5b92fa42094bc3f03e4022169e39d78" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Interest Formulas and their Application" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 3.1 Page 29" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#initialisation of variable\n", "P=20000.0;#in rupees\n", "n=10.0;#in years\n", "i=18.0;#% per annum\n", "\n", "#calculation\n", "F=P*(1+i/100)**n;\n", "\n", "#result\n", "print \"Maturity value after 18 years is \", round(F,3),\" Rupees.\";\n", "print \" Ans in the book is not correct\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Maturity value after 18 years is : 104676.711 Rupees.\n", " Ans in the book is not correct\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 3.2 Page 30" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#initialisation of variable\n", "F=100000.0;#in rupees\n", "n=10.0;#in years\n", "i=15.0;#% per annum\n", "\n", "#calculation\n", "P=F/((1.0+i/100.0)**n);\n", "\n", "#result\n", "print \"The person has to invest \", round(P,3),\" Rupees.\";\n", "print \" Ans in the book is not correct\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The person has to invest 24718.471 Rupees.\n", " Ans in the book is not correct\n" ] } ], "prompt_number": 5 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 3.3 Page 31" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#initialisation of variable\n", "A=10000.0;#in rupees\n", "n=25.0;#in years\n", "i=20.0;#% per annum\n", "\n", "#calculation\n", "F=A*(((1+i/100)**n-1)/(i/100));\n", "\n", "#result\n", "print \"The future sum of the annual equal payment after 25 years is \",round(F,3),\" Rupees.\";" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The future sum of the annual equal payment after 25 years is 4719810.832 Rupees.\n" ] } ], "prompt_number": 8 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 3.4 Page 32" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#initialisation of variable\n", "F=500000.0;#in rupees\n", "n=15.0;#in years\n", "i=18.0;#% per annum\n", "\n", "#calculation\n", "A=F*((i/100)/((1+i/100)**n-1));\n", "\n", "#result\n", "print \"The annual equal ammount which must be deposited for 15 years is \",round(A,3),\" Rupees.\";" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The annual equal ammount which must be deposited for 15 years is 8201.391 Rupees.\n" ] } ], "prompt_number": 12 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 3.5 Page 33" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#initiasation of variable\n", "A=1000000.0;#in rupees\n", "n=20.0;#in years\n", "i=15.0;#% per annum\n", "\n", "#calculation\n", "P=A*(((1+i/100)**n-1)/((i/100)*(1+i/100)**n));\n", "\n", "#result\n", "print \"The amount of reserve which must be setup now is : \",round(P,3),\" Rupees\";\n", "print \" Ans in the book is not correct\"" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The amount of reserve which must be setup now is : 6259331.474 Rupees\n", " Ans in the book is not correct\n" ] } ], "prompt_number": 13 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 3.6 Page 34" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#initialisation of variable\n", "P=1000000.0;#in rupees\n", "n=15.0;#in years\n", "i=18.0;#% per annum\n", "\n", "#calculation\n", "A=P*(((i/100)*(1+i/100)**n)/((1+i/100)**n-1));\n", "\n", "#result\n", "print \"The annual equivalent installment to be paid by the company to the bank is \",round(A),\" Rupees.\";" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "The annual equivalent installment to be paid by the company to the bank is : 196403.0 Rupees.\n" ] } ], "prompt_number": 14 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 3.7 Page 35" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#initiation of variable\n", "A1=4000.0;#in rupees\n", "G=500.0;#in rupees\n", "n=10.0;#in years\n", "i=15.0;#% per annum\n", "\n", "#calculation\n", "A=A1+G*(((1+i/100)**n-(i/100)*n-1)/((i/100)*(1+i/100)**n-(i/100)));\n", "F=A*(((1+i/100)**n-1)/(i/100));\n", "\n", "#result\n", "print \"At the end of 10th year, the compound amountr of all his payments will be : \",round(F,3),\" Rupees.\";" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "At the end of 10th year, the compound amountr of all his payments will be : 115560.6 Rupees.\n" ] } ], "prompt_number": 15 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 3.8 Page 36" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#initiation of variable\n", "A1=8500.0;#in rupees\n", "G=-500.0;#in rupees\n", "n=10.0;#in years\n", "i=15.0;#% per annum\n", "\n", "#calculation\n", "A=A1+G*(((1+i/100)**n-(i/100)*n-1)/((i/100)*(1+i/100)**n-(i/100)));\n", "F=A*(((1+i/100)**n-1)/(i/100));\n", "\n", "#result\n", "print \"At the end of 10th year, the compound amountr of all his payments will be : \",round(F,3),\" Rupees.\";" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "At the end of 10th year, the compound amountr of all his payments will be : 138235.878 Rupees.\n" ] } ], "prompt_number": 17 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 3.9 Page 38" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#initiation of variable\n", "P=5000.0;#in rupees\n", "n=10.0;#in years\n", "i=12.0;#% per annum\n", "m=4.0;#no. of interest periods per year for quarterly\n", "\n", "#calculation\n", "N=n*m;\n", "r=i/m;\n", "F=P*(1+r/100)**N;\n", "\n", "#result\n", "print\"Maturity value after 10 years is \",round(F,3),\" Rupees.\";" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Maturity value after 10 years is : 16310.189 Rupees.\n" ] } ], "prompt_number": 18 } ], "metadata": {} } ] }