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   "source": [
    "# Chapter 3: Tem"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Exa 3.1"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 1,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "T (F) =  26.60\n",
      " \n",
      " T (C) =  87.96\n",
      " \n",
      " T (K) =  361.11\n",
      "press enter key to exit\n"
     ]
    },
    {
     "data": {
      "text/plain": [
       "''"
      ]
     },
     "execution_count": 1,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "#Make the following conversions : (a) -3 C to F (b) 650 R to C (c) 650 R to K\n",
    "#initialisation of variables\n",
    "T1= -3 \t\t\t\t\t#degrees\n",
    "T2= 650. \t\t\t\t#Rankine\n",
    "T3= 650. \t\t\t\t#Rankine\n",
    "#CALCULATIONS\n",
    "t1= (9./5.)*T1+32 \t\t#In F\n",
    "t2= T2-459.67 \t\t\t#In F\n",
    "t21= (5./9.)*(t2-32) \t#In C\n",
    "t3= t21+273.15 \t\t\t#In K\n",
    "#RESULTS\n",
    "print '%s %.2f' % ('T (F) = ',t1)\n",
    "print '%s %.2f' % (' \\n T (C) = ',t21)\n",
    "print '%s %.2f' % (' \\n T (K) = ',t3)\n",
    "raw_input('press enter key to exit')"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Exa 3.2"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "T (F) =  18.00\n",
      " \n",
      " T (R) =  18.00\n",
      "press enter key to exit\n"
     ]
    },
    {
     "data": {
      "text/plain": [
       "''"
      ]
     },
     "execution_count": 2,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "#The temperatuer of an object drops from 40 to 30C. Determine the temperature\n",
    "#drop in (a) F and (b) R.\n",
    "#initialisation of variables\n",
    "T1= 40. \t\t\t\t#degrees\n",
    "T2= 30. \t\t\t\t#degrees\n",
    "#CALCULATIONS\n",
    "d1= (T1-T2)*(9./5.) \t#drop in F\n",
    "d2= d1 \t\t\t\t\t#drop in R\n",
    "#RESULTS\n",
    "print '%s %.2f' % ('T (F) = ',d1)\n",
    "print '%s %.2f' % (' \\n T (R) = ',d2)\n",
    "raw_input('press enter key to exit')"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Exa 3.3"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 3,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "L (mm) =  400.54\n",
      "press enter key to exit\n"
     ]
    },
    {
     "data": {
      "text/plain": [
       "''"
      ]
     },
     "execution_count": 3,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "#A brass wire has a length of 400mm at 20C. What is the length of the wire at 90C?\t\n",
    "#initialisation of variables\n",
    "l= 400 \t\t\t\t\t#mm\n",
    "t1= 20 \t\t\t\t\t#degrees\n",
    "t2= 90 \t\t\t\t\t#degrees\n",
    "alpha= 19.3/1000000. \t#degrees^-1\n",
    "#CALCULATIONS\n",
    "L= alpha*(t2-t1)*l \t\t#Change in Length\n",
    "L1= L+l \t\t\t\t#Final Length\n",
    "#RESULTS\n",
    "print '%s %.2f' % ('L (mm) = ',L1)\n",
    "raw_input('press enter key to exit')"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Exa 3.4"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 4,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "diameter at -15 (in) =  2.98\n",
      "press enter key to exit\n"
     ]
    },
    {
     "data": {
      "text/plain": [
       "''"
      ]
     },
     "execution_count": 4,
     "metadata": {},
     "output_type": "execute_result"
    }
   ],
   "source": [
    "#An Al 2024-T3 plate has a 2.980-in diameter hole at 69F. What is the \n",
    "#diameter if the temperature is lowered to -15F?\n",
    "import math\n",
    "#initialisation of variables\n",
    "d= 2.98 \t\t\t\t\t#in\n",
    "T1= 69 \t\t\t\t\t\t#F\n",
    "T2= -15 \t\t\t\t\t#F\n",
    "alpha= 22.7/1000000. \t\t#C^-1\n",
    "#CALCULATIONS\n",
    "A0= math.pi*d*d/4. \t\t\t#Initial Area\n",
    "alpha1= alpha/1.8 \n",
    "A= 2*alpha1*A0*(T1-T2)  \t#Change in Area\n",
    "A1= A0-A \n",
    "d1= math.sqrt(4*A1/math.pi) #diameter at -15F\n",
    "#RESULTS\n",
    "print '%s %.2f' % ('diameter at -15 (in) = ',d1)\n",
    "raw_input('press enter key to exit')"
   ]
  }
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