{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# Chapter 13: Boiling Heat Transfer" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Exa 13.1" ] }, { "cell_type": "code", "execution_count": 1, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Heat transfer coefficient for nucleate boiling (W/m^2 C) = 1.76e+05\n", "press enter key to exit\n" ] }, { "data": { "text/plain": [ "''" ] }, "execution_count": 1, "metadata": {}, "output_type": "execute_result" } ], "source": [ "#Water at 1 atm is boiled on a brass surface. Using the rohsenow correlation\n", "#determine the heat transfer coefficient for nucleate boiling if the wall \n", "#superheat is 11C?\n", "import math\n", "#initialisation of variables\n", "P= 1 \t\t\t\t#atm\n", "dt= 11 \t\t\t\t#C\n", "Csf= 0.006\n", "r= 1./3.\n", "s= 1.\n", "cl= 4.218 \t\t\t#J/gm K\n", "hfg= 2257 \t\t\t#J/gm\n", "Pr= 1.75\n", "ul= 283.1/1000. \t#gm/m s\n", "s= 57.78/1000. \t\t#N/m\n", "pl= 958*1000. \t\t#gm/m^3\n", "pv= 598. \t\t\t#gm/m^3\n", "gc= 1000. \t\t\t#gm m/N s^2\n", "g= 9.8 \t\t\t\t#m/s^2\n", "#CALCULATIONS\n", "p= pl-pv \t\t\t#change in density\n", "q= ((math.pow(((cl*dt)/(hfg*Csf*Pr)),(1/r))*(ul*hfg))/math.pow((gc*s/(g*p)),(0.5))) #Heat transfer rate\n", "h= q/dt \t\t\t#Heat transfer coefficient\n", "#RESULTS\n", "print '%s %.2e' % ('Heat transfer coefficient for nucleate boiling (W/m^2 C) = ',h)\n", "raw_input('press enter key to exit')" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Exa 13.2" ] }, { "cell_type": "code", "execution_count": 2, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Condensation heat tranfer coefficient if the tube is vertical (Btu/h ft^2 F) = 758.79\n", " \n", " Condensation heat tranfer coefficient if the tube is horizontally (Btu/h ft^2 F) = 1926.98\n", "press enter key to exit\n" ] }, { "data": { "text/plain": [ "''" ] }, "execution_count": 2, "metadata": {}, "output_type": "execute_result" } ], "source": [ "#A tube, 1/2 in OD and 5 ft long, is used to condense steam at 6 psia; the\n", "#average temperature of the tube is maintained at 130 F. Determine the \n", "#condensation heat transfer coefficient if the tube is mounted\n", "#(a) vertically and (b) horizontally\n", "import math\n", "#initialisation of variables\n", "k= 0.384 \t\t\t\t\t\t\t\t\t\t\t#Btu/hr ft F\n", "Tsat= 170.03 \t\t\t\t\t\t\t\t\t\t#F\n", "hfg= 996.2 \t\t\t\t\t\t\t\t\t\t\t#Btu/lbm\n", "T= 130 \t\t\t\t\t\t\t\t\t\t\t\t#F\n", "l= 5. \t\t\t\t\t\t\t\t\t\t\t\t#ft\n", "P= 6. \t\t\t\t\t\t\t\t\t\t\t\t#psia\n", "g= 4.17*math.pow(10,8) \t\t\t\t\t\t\t\t#ft/h^2\n", "d= 0.042 \t\t\t\t\t\t\t\t\t\t\t#ft\n", "p= 61.2 \t\t\t\t\t\t\t\t\t\t\t#lbm/ft^3\n", "u= 1.05 \t\t\t\t\t\t\t\t\t\t\t#lbm/ft h\n", "#CALCULATIONS\n", "dt= Tsat-T \t\t\t\t\t\t\t\t\t\t\t#Change in temp.\n", "Tf= (Tsat+T)/2. \t\t\t\t\t\t\t\t\t#Average temp.\n", "hc= 0.943*math.pow(((k*k*k*p*p*g*hfg)/(l*u*dt)),(1./4.))\n", "hc1= 0.725*math.pow(((k*k*k*p*p*g*hfg)/(d*u*dt)),(1./4.))\n", "#RESULTS\n", "print '%s %.2f' % ('Condensation heat tranfer coefficient if the tube is vertical (Btu/h ft^2 F) = ',hc)\n", "print '%s %.2f' % (' \\n Condensation heat tranfer coefficient if the tube is horizontally (Btu/h ft^2 F) = ',hc1)\n", "raw_input('press enter key to exit')" ] } ], "metadata": { "kernelspec": { "display_name": "Python 2", "language": "python", "name": "python2" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 2 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython2", "version": "2.7.6" } }, "nbformat": 4, "nbformat_minor": 0 }