{ "metadata": { "name": "", "signature": "sha256:e3ffdae85ed1c10a54629e535e9e044264a512de563ad3fb48c98b93c4a65432" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 2 - Fundamental Concepts" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 1 - Pg 18" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#calculate the potential energy\n", "#Initialization of variables\n", "z=100 #ft\n", "m=32.1739 #lbm\n", "#calculations\n", "PE=m*z\n", "#results\n", "print '%s %.2f %s' %(\"Potential energy =\",PE,\"ft-lbm\")\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Potential energy = 3217.39 ft-lbm\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 2 - Pg 21" ] }, { "cell_type": "code", "collapsed": false, "input": [ "#calculate the absolute energy of this mixture and the change in mass\n", "#Initialization of variables\n", "m0=18.016 #lbm\n", "gc=32.1739 #lbm ft/lbf sec^2\n", "c=186000*5280\n", "dU=94.4*10**6 #ft-lbf\n", "#calculations\n", "U=m0/gc *c**2\n", "dm= -dU*gc/c**2\n", "#results\n", "print '%s %.2e %s' %(\"Absolute energy of this mixture =\",U,\" ft-lbf\")\n", "print '%s' %(\"\\n In case b, there is no change in mass\")\n", "print '%s %.2e %s' %(\"\\n Change in mass =\",dm,\" lbm\")\n", "print '%s' %(\"The answers are a bit different due to rounding off error in textbook.\")\n" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Absolute energy of this mixture = 5.40e+17 ft-lbf\n", "\n", " In case b, there is no change in mass\n", "\n", " Change in mass = -3.15e-09 lbm\n", "The answers are a bit different due to rounding off error in textbook.\n" ] } ], "prompt_number": 2 } ], "metadata": {} } ] }