{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"CHAPTER 18 OPERATIONAL AMPLIFIERS"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18-1, Page 672"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Vout=13.5 #As per figure 18-7b(V)\n",
"Aov=100000 #open loop voltage gain\n",
"\n",
"V2=Vout/Aov #required input voltage(V)\n",
"\n",
"print 'Required input voltage V2 = ',V2*10**6,'uV'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Required input voltage V2 = 135.0 uV\n"
]
}
],
"prompt_number": 71
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18-2, Page 672"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"CMRR_dB=40 #As per figure 18-7a at 100KHz(dB)\n",
"\n",
"CMRR=10**(CMRR_dB/20)\n",
"\n",
"print 'Common-mode rejection ratio = ',CMRR"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Common-mode rejection ratio = 100\n"
]
}
],
"prompt_number": 76
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18-3, Page 673"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"\n",
"Av1=1000 #Voltage gain as per figure 18-7c for 1KHZ\n",
"Av10=100 #Voltage gain as per figure 18-7c for 10KHZ\n",
"Av100=10 #Voltage gain as per figure 18-7c for 100KHZ\n",
"\n",
"print 'Voltage gain for 1KHZ = ',Av1\n",
"print 'Voltage gain for 1KHZ = ',Av10\n",
"print 'Voltage gain for 1KHZ = ',Av100"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Voltage gain for 1KHZ = 1000\n",
"Voltage gain for 1KHZ = 100\n",
"Voltage gain for 1KHZ = 10\n"
]
}
],
"prompt_number": 77
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18-4, Page 673"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Vout=0.25 #output changes in 0.1us (V)\n",
"t=0.1 #time for output change(us) \n",
"\n",
"SR=Vout/t #slew rate(V/us)\n",
"\n",
"print 'Slew rate SR = ',SR,'V/us'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Slew rate SR = 2.5 V/us\n"
]
}
],
"prompt_number": 79
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18-5, Page 673"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"SR=15 #slew rate(V/us)\n",
"Vp=10 #Peak output voltage(V)\n",
"\n",
"fmax=1000*SR/(2*math.pi*Vp) #power bandwidth (KHz) \n",
"\n",
"print 'Power bandwidth = ',round(fmax),'KHz'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Power bandwidth = 239.0 KHz\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18-6, Page 673"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"import math\n",
"\n",
"SR1=0.5 #Slew rate1(V/us)\n",
"SR2=5 #Slew rate2(V/us)\n",
"SR3=50 #Slew rate3(V/us)\n",
"Vp=8 #peak voltage(V)\n",
"\n",
"fmax1=1000*SR1/(2*math.pi*Vp) #power bandwidth1 (KHz) \n",
"fmax2=1000*SR2/(2*math.pi*Vp) #power bandwidth2 (KHz) \n",
"fmax3=SR3/(2*3*math.pi*Vp) #power bandwidth3 (MHz) \n",
"\n",
"print 'Power bandwidth1 = ',math.ceil(fmax1),'KHz'\n",
"print 'Power bandwidth2 = ',math.ceil(fmax2),'KHz'\n",
"print 'Power bandwidth3 = ',math.ceil(fmax3),'MHz'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Power bandwidth1 = 10.0 KHz\n",
"Power bandwidth2 = 100.0 KHz\n",
"Power bandwidth3 = 1.0 MHz\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18-7, Page 678"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Vin=10 #input voltage(mV)\n",
"Rf=75 #feedback path resistance Rf (KOhm)\n",
"R1=1.5 #inverting input resistance R1(KOhm)\n",
"Funity=1 #Funity (MHz)\n",
"\n",
"Av_CL=-Rf/R1 #closed loop voltage gain\n",
"f2_CL1=Funity/-Av_CL #closed loop bandwidth1(KHz)\n",
"Vout1=Av_CL*Vin #output voltage1(mV)\n",
"Vout2=-Vin #output voltage2(mV)\n",
"\n",
"print 'Output voltage for 1KHz = ',Vout1,'mVpp'\n",
"print 'Output voltage for 1MHz = ',Vout2,'mVpp'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Output voltage for 1KHz = -500.0 mVpp\n",
"Output voltage for 1MHz = -10 mVpp\n"
]
}
],
"prompt_number": 90
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18-8, Page 679"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Vin=10 #input voltage(mV)\n",
"Rf=75 #feedback path resistance Rf (KOhm)\n",
"R1=1.5 #inverting input resistance R1(KOhm)\n",
"Iinb=80*10**-9 #bias current(A)\n",
"Iino =20*10**-9 #Iin(off) (A) \n",
"Vino=2.0 #Vin(off) (mV)\n",
"Av=50 #voltage gain \n",
"RB1=0 #resistance at noninverting input(KOhm) \n",
"\n",
"RB2=R1*Rf/(Rf+R1) #thevenin resistance at inverting input(KOhm) \n",
"V1err=(RB1-RB2)*Iinb*10**6 #dc error input1 (mV)\n",
"V2err=(RB1+RB2)*(Iino/2)*10**6 #dc error input2 (mV)\n",
"V3err=Vino #dc error input3 (mV)\n",
"Verror=Av*(abs(V1err)+V2err+V3err) #output error voltage(mV)\n",
"\n",
"print 'output error voltage Verror = ',round(Verror,2),'mV'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"output error voltage Verror = 106.62 mV\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18-9, Page 679"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Vin=10 #input voltage(mV)\n",
"Rf=75 #feedback path resistance Rf (KOhm)\n",
"R1=1.5 #inverting input resistance R1(KOhm)\n",
"Iinb=500*10**-9 #bias current(A)\n",
"Iino =200*10**-9 #Iin(off) (A) \n",
"Vino=6.0 #Vin(off) (mV)\n",
"Av=50 #voltage gain \n",
"RB1=0 #resistance at noninverting input(KOhm) \n",
"\n",
"RB2=R1*Rf/(Rf+R1) #thevenin resistance at inverting input(KOhm) \n",
"V1err=(RB1-RB2)*Iinb*10**6 #dc error input1 (mV)\n",
"V2err=(RB1+RB2)*(Iino/2)*10**6 #dc error input2 (mV)\n",
"V3err=Vino #dc error input3 (mV)\n",
"Verror=Av*(abs(V1err)+V2err+V3err) #output error voltage(mV)\n",
"\n",
"print 'output error voltage Verror = ',round(Verror,2),'mV'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"output error voltage Verror = 344.12 mV\n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18-10, Page 683"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"import math\n",
"\n",
"Vin=50 #input voltage(mV)\n",
"Rf=3.9*10**3 #feedback path resistance Rf (Ohm)\n",
"R1=100 #inverting input resistance R1(Ohm)\n",
"Funity=1*10**6 #Funity (Hz)\n",
"\n",
"Av_CL=1+(Rf/R1) #closed loop voltage gain\n",
"f2_CL1=Funity/Av_CL #closed loop bandwidth1(KHz)\n",
"Av_CL1=math.ceil(10**(12/20.0)) #Av for 12 dB at 250 KHz \n",
"Vout=Av_CL1*Vin #output voltage(mV)\n",
"\n",
"print 'Output voltage for 250KHz = ',Vout,'mVpp'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Output voltage for 250KHz = 200.0 mVpp\n"
]
}
],
"prompt_number": 30
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18-11, Page 684"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Vin=10 #input voltage(mV)\n",
"Rf=3.9*10**3 #feedback path resistance Rf (Ohm)\n",
"R1=100 #inverting input resistance R1(Ohm)\n",
"Iinb=500*10**-9 #bias current(A)\n",
"Iino =200*10**-9 #Iin(off) (A) \n",
"Vino=6.0*10**-3 #Vin(off) (V)\n",
"Av=40 #voltage gain \n",
"RB1=0 #resistance at noninverting input(KOhm) \n",
"\n",
"RB2=R1*Rf/(Rf+R1) #thevenin resistance at inverting input(KOhm) \n",
"V1err=(RB1-RB2)*Iinb #dc error input1 (mV)\n",
"V2err=(RB1+RB2)*(Iino/2) #dc error input2 (mV)\n",
"V3err=Vino #dc error input3 (mV)\n",
"Verror=Av*(abs(V1err)+V2err+V3err) #output error voltage(mV)\n",
"\n",
"print 'output error voltage Verror = ',Verror*1000,'mV'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"output error voltage Verror = 242.34 mV\n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18-12, Page 687"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Vin1=100*10**-3 #input voltage1(V)\n",
"Vin2=200*10**-3 #input voltage2(V)\n",
"Vin3=300*10**-3 #input voltage3(V)\n",
"Rf=100.0 #feedback path resistance Rf (KOhm)\n",
"R1=20.0 #inverting input resistance R1(KOhm)\n",
"R2=10.0 #inverting input resistance R2(KOhm)\n",
"R3=50.0 #inverting input resistance R3(KOhm)\n",
"\n",
"Av1_CL=-Rf/R1 #closed loop voltage gain\n",
"Av2_CL=-Rf/R1 #closed loop voltage gain\n",
"Av3_CL=-Rf/R1 #closed loop voltage gain\n",
"Vout=Av1_CL*Vin1+Av2_CL*Vin2+Av3_CL*Vin3 #output voltage1(mV)\n",
"RB2=(R1**-1+R2**-1+R3**-1+Rf**-1)**-1 #thevenin resistance at inverting input(KOhm) \n",
"\n",
"print 'Output voltage = ',Vout,'Vpp'\n",
"print 'thevenin resistance at inverting input RB2 = ',round(RB2,2),'KOhm'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Output voltage = -3.0 Vpp\n",
"thevenin resistance at inverting input RB2 = 5.56 KOhm\n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18-13, Page 688"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"Vin=10 #ac voltage source (mVpp)\n",
"Av=1 #voltage gain\n",
"Funity=1 #unity frequency (MHz) \n",
"\n",
"Vout=Av*Vin #output voltage(V) \n",
"f2_CL=Funity #bandwidth(MHz) \n",
"\n",
"print 'Output voltage = ',Vout,'mVpp'\n",
"print 'Bandwidth f2(CL) = ',f2_CL,'MHz'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Output voltage = 10 mVpp\n",
"Bandwidth f2(CL) = 1 MHz\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 18-14, Page 688"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"\n",
"RL=1.0 #load resistance(Ohm)\n",
"Vout=9.99 #load voltage(mV)\n",
"Vz=0.01 #voltage across Zout(CL) (mV)\n",
"\n",
"iout=Vout/RL #load current(mA)\n",
"Zout_CL=Vz/iout #output impedance(Ohm)\n",
"\n",
"print 'Load current iout = ',iout,'mA'\n",
"print 'closed loop output impedance Zout(CL) = ',round(Zout_CL,3),'Ohm'"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Load current iout = 9.99 mA\n",
"closed loop output impedance Zout(CL) = 0.001 Ohm\n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "code",
"collapsed": false,
"input": [],
"language": "python",
"metadata": {},
"outputs": []
}
],
"metadata": {}
}
]
}