{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# CHAPTER 4:ANALOG ELECTRONIC VOLT-OHM-MILLIAMMETER" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 4-1, Page Number 88" ] }, { "cell_type": "code", "execution_count": 1, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "When E=10 V, meter current is 1 mA\n", "\n", "Input Impedance,\n", "with transistor= 1.0 mega ohm\n", "without transistor= 9.3 kilo ohm\n" ] } ], "source": [ "import math\n", "\n", "#Variable Declaration\n", "Vcc=20 #Supply Voltage(V)\n", "Rsm=9.3*10**3 #Rsm=Rs+Rm(ohm)\n", "Im=1*10**-3 #Emitter Current(A)\n", "hfe=100 #Transistor h parameter\n", "Vb1=0.7 #Base Emitter Voltage drop(V)\n", "#Calculation\n", "#To obtain meter current when E=10V\n", "E=10 #Base input voltage(V)\n", "Ve=E-Vb1 #Emitter Voltage(V) found using KVL aclong base loop\n", "Im=Ve/Rsm #Emitter current \n", "\n", "#With the transistor\n", "Ib=Im/hfe #Base current is approximately equlat to Ie/hfe\n", "Ri=E/Ib #Input resistance with transistor\n", "\n", "#Without transistor\n", "Ri1=Rsm #Input resistance without transistor\n", "\n", "#Results\n", "\n", "print \"When E=10 V, meter current is\",int(Im*10**3),\"mA\"\n", "print \n", "print \"Input Impedance,\"\n", "print \"with transistor=\",round(Ri/10**6),\"mega ohm\"\n", "print \"without transistor=\",Ri1/10**3,\"kilo ohm\"\n", "\n" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 4-2, Page Number 89" ] }, { "cell_type": "code", "execution_count": 2, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "When E=0V, I2=I3= 2.9 mA\n", "When E=1V, meter circuit voltage(V)= 1.0 V\n", "When E=0.5, meter circuit voltage= 0.5 V\n" ] } ], "source": [ "import math\n", "\n", "#Variable Declaration\n", "\n", "R2=3.9*10**3 #in ohm\n", "R3=3.9*10**3 #in ohm\n", "Vcc=12 #in V\n", "Vee=-12 #in V \n", "Vbe=0.7 #Base Emitter voltage in V\n", "\n", "#Calculation \n", "\n", "#When E=0\n", "E=0 \n", "Vr2=E-Vbe-Vee #KVL \n", "Vr3=E-Vbe-Vee #KVL\n", "I2=Vr2/R2 #Ohm's Law\n", "I3=I2 \n", "\n", "print \"When E=0V, I2=I3=\",round(I3*10**3,1),\"mA\"\n", "\n", "#When E=1\n", "E=1 #in V\n", "Vp=0 #in V\n", "Ve1=E-Vbe #KVL\n", "Ve2=Vp-Vbe #KVL\n", "V=Ve1-Ve2 #KVL\n", "print \"When E=1V, meter circuit voltage(V)=\",V,\"V\"\n", "\n", "#When E=0.5\n", "E=0.5 #in V\n", "Vp=0 #in V\n", "Ve1=E-Vbe #KVL \n", "Ve2=Vp-Vbe #KVL\n", "V=Ve1-Ve2 #KVL \n", "print \"When E=0.5, meter circuit voltage=\",V,\"V\"\n", "\n" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 4-3, Page Number: 93" ] }, { "cell_type": "code", "execution_count": 6, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "Im is 0.75 which is 75.0 % of full scale\n", "As the meter is in 10V range, 75% of full scale is 7.5 V\n" ] } ], "source": [ "import math\n", "\n", "#Variable Declaration\n", "\n", "E=7.5 #in V\n", "Vgs=-5 #FET gate source voltage in V\n", "Vp=5 #in V\n", "Rsm=1*10**3 #Rs+Rm in ohm\n", "Im=1*10**-3 #in A\n", "Ra=800*10**3 #in ohm\n", "Rb=100*10**3 #in ohm\n", "Rc=60*10**3 #in ohm\n", "Rd=40*10**3 #in ohm\n", "\n", "Eg=E*(Rc+Rd)/(Ra+Rb+Rc+Rd) #Voltage Divider Rule \n", "Vs=Eg-Vgs #KVL \n", "\n", "Ve1=Vs-Vbe #KVL \n", "Ve2=Vp-Vbe #KVL\n", "V=Ve1-Ve2 #KVL\n", "Im=V/Rsm #Ohm's Law\n", "\n", "print \"Im is\",round(Im*10**3,2),\"which is\",round(Im*10**3,2)*100,\"% of full scale\"\n", "print \"As the meter is in 10V range, 75% of full scale is\",10*0.75,\"V\"" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 4-4, Page Number: 97" ] }, { "cell_type": "code", "execution_count": 3, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "R3= 100.0 ohm\n", "R4= 4.9 kilo ohm\n" ] } ], "source": [ "import math\n", "\n", "#Variable Declaration\n", "\n", "Im=100*10**-6 #Full scale current in A\n", "Rm=10*10**3 #Meter resistance in ohm \n", "Ib=0.2*10**-6 #Op-amp input current in A\n", "E=20*10**-3 #Maximum input in V\n", "\n", "#Calculations\n", "\n", "I4=1000*Ib #Since I4>>Ib\n", "Vout=Im*Rm #Ohm's Law \n", "\n", "R3=E/I4 #Ohm's Law \n", "R4=(Vout-E)/I4 #Ohm's Law\n", "\n", "#Results\n", "\n", "print \"R3=\",R3,\"ohm\"\n", "print \"R4=\",round(R4*10**-3,1),\"kilo ohm\"\n", "\n" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 4-5, Page Number: 98" ] }, { "cell_type": "code", "execution_count": 4, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "R3= 1.0 kilo Ohm\n", "Maximum voltage at output terminal= 1.1 V\n" ] } ], "source": [ "import math\n", "\n", "#Variable Declaration\n", "E=1.0 #in V\n", "I=1*10**-3 #in A\n", "Rm=100 #in ohm\n", "\n", "R3=E/I #Ohm's Law\n", "Vo=I*(R3+Rm) #Maximum Output voltage\n", "\n", "print \"R3=\",R3/1000,\"kilo Ohm\"\n", "print \"Maximum voltage at output terminal=\",round(Vo,1),\"V\"\n", "\n" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Example 4-7, Page Number: 107" ] }, { "cell_type": "code", "execution_count": 5, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "R3= 45.0 ohm\n", "When input is 50mV, meter deflection is 0.5 mA(half scale)\n" ] } ], "source": [ "import math\n", "\n", "#Variable Declaration\n", "\n", "Iav=1*10**-3 #in A \n", "Rm=1.2*10**3 #in ohm\n", "E=100*10**-3 #in V\n", "\n", "#With half wave rectifiers,\n", "Ip=2*Iav/0.637 #Using relation between Ip and Iav for HWR\n", "\n", "#Peak value of Er3=input peak voltage\n", "Ep=E/0.707 #Relation between peak voltage and rms \n", "R3=Ep/Ip #in ohm\n", "print \"R3=\",round(R3),\"ohm\"\n", "\n", "#When E=50mV\n", "E=50*10**-3 #in V\n", "Ep=E/0.707 #Peak Voltage in V \n", "Ip=Ep/R3 #Peak current in A \n", "\n", "Iav=0.637*Ip/2 #Average Current in A\n", "\n", "print \"When input is 50mV, meter deflection is\",round(Iav*10**3,1),\"mA(half scale)\"\n" ] }, { "cell_type": "code", "execution_count": null, "metadata": { "collapsed": true }, "outputs": [], "source": [] } ], "metadata": { "kernelspec": { "display_name": "Python 2", "language": "python", "name": "python2" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 2 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython2", "version": "2.7.9" } }, "nbformat": 4, "nbformat_minor": 0 }