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  {
   "cells": [
    {
     "cell_type": "heading",
     "level": 1,
     "metadata": {},
     "source": [
      "Chapter : 4 - Junction (Contd.)"
     ]
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 4.12.1 - Page No : 4-46"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "from __future__ import division\n",
      "from numpy import pi\n",
      "# Given data\n",
      "q = 1.6 * 10**-19 # in C\n",
      "N_D = 10**15 # in electrons/cm**3\n",
      "N_D = N_D * 10**6 # in electrons/m**3\n",
      "epsilon_r = 12 \n",
      "epsilon_o = (36 * pi * 10**9)**-1 \n",
      "epsilon = epsilon_o * epsilon_r \n",
      "a = 3 * 10**-4 # in cm\n",
      "a = a * 10**-2 # in m\n",
      "V_P = (q * N_D * a**2)/( 2 * epsilon) # in V\n",
      "print \"The Pinch off voltage = %0.1f V \" %V_P\n",
      "# V_GS = V_P * (1-(b/a))**2\n",
      "b = (1-0.707) *a # in m\n",
      "print \"The value of b = %0.3f \u00b5m \" %(b*10**6)\n",
      "print \"Hence the channel width has been reduced to about one third of its value for V_GS = 0\"\n",
      "# Note : The unit of b in the book is wrong since the value of b is calculated in \u00b5m."
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "The Pinch off voltage = 6.8 V \n",
        "The value of b = 0.879 \u00b5m \n",
        "Hence the channel width has been reduced to about one third of its value for V_GS = 0\n"
       ]
      }
     ],
     "prompt_number": 2
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example :  4.12.2 - Page No : 4-47"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "from math import sqrt\n",
      "# Given data\n",
      "I_DSS = 8 # in mA\n",
      "V_P = -4 # in V\n",
      "I_D = 3 # in mA\n",
      "V_GS = V_P * (1 - sqrt(I_D/I_DSS)) # in V\n",
      "print \"The value of V_GS = %0.2f V \" %V_GS\n",
      "V_DS = V_GS - V_P # in V\n",
      "print \"The value of V_DS = %0.2f V \" %V_DS"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "The value of V_GS = -1.55 V \n",
        "The value of V_DS = 2.45 V \n"
       ]
      }
     ],
     "prompt_number": 4
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example :  4.12.3 - Page No : 4-47"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "# Given data\n",
      "V_P = -4 # in V\n",
      "I_DSS = 9 # in mA\n",
      "I_DSS = I_DSS * 10**-3 # in A\n",
      "V_GS = -2 # in V\n",
      "I_D = I_DSS * ((1 - (V_GS/V_P))**2) # in A\n",
      "print \"The drain current = %0.2f mA \" %(I_D*10**3)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "The drain current = 2.25 mA \n"
       ]
      }
     ],
     "prompt_number": 5
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example :  4.12.4 - Page No : 4-47"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "# Given data\n",
      "I_DSS = 12 # in mA\n",
      "I_DSS = I_DSS * 10**-3 # in A\n",
      "V_P = -(6) # in V\n",
      "V_GS = -(1) # in V\n",
      "g_mo = (-2 * I_DSS)/V_P # in A/V\n",
      "g_m = g_mo * (1 - (V_GS/V_P)) # in S\n",
      "print \"The value of transconductance = %0.2f mS \" %(g_m*10**3)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "The value of transconductance = 3.33 mS \n"
       ]
      }
     ],
     "prompt_number": 6
    },
    {
     "cell_type": "heading",
     "level": 2,
     "metadata": {},
     "source": [
      "Example 4.12.5 - Page No : 4-48"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "# Given data\n",
      "I_DSS = 10 # in mA \n",
      "I_DSS = I_DSS * 10**-3 # in A\n",
      "V_P = -(5) # in V\n",
      "V_GS = -(2.5) # in V\n",
      "g_m = ((-2 * I_DSS)/V_P) * (1 -(V_GS/V_P)) # in S\n",
      "g_m = g_m * 10**3 # in mS\n",
      "print \"The Transconductance = %0.f mS \" %g_m\n",
      "I_D = I_DSS * ((1 - (V_GS/V_P))**2) # in A\n",
      "print \"The drain current = %0.1f mA \"  %(I_D*10**3)"
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "The Transconductance = 2 mS \n",
        "The drain current = 2.5 mA \n"
       ]
      }
     ],
     "prompt_number": 8
    }
   ],
   "metadata": {}
  }
 ]
}