{
"metadata": {
"name": ""
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter 05 : BJT biasing"
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.1, Page No 182"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"Rc=12.0*10**3\n",
"Vcc=20.0\n",
"print(\" When Ic=0\")\n",
"Ic=0\n",
"\n",
"#Calculations\n",
"Vce=Vcc-Ic*Rc\n",
"print(\" At point A Ic=0 nad Vce=20\")\n",
"print(\"When Vce=0\")\n",
"Vce=0\n",
"Ic=Vcc/Rc\n",
"\n",
"#Results\n",
"print(\" At point B Ic=1.7mA and Vce=0\")\n",
"print(\"Ic is %.1f mA \" %(Ic*10**3))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" When Ic=0\n",
" At point A Ic=0 nad Vce=20\n",
"When Vce=0\n",
" At point B Ic=1.7mA and Vce=0\n",
"Ic is 1.7 mA \n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.2 Page No 186"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#initialisation of variables\n",
"Vcc=18.0\n",
"Rc=2.2*10**3\n",
"Ib=40.0*10**-6\n",
"\n",
"#Calculations\n",
"print(\"when Ic=0\")\n",
"Ic=0\n",
"Vce=Vcc-Ic*Rc\n",
"print(\"At point A Ic=0 and Vce=18\")\n",
"print(\"when Vce=0\")\n",
"Ic=Vcc/Rc\n",
"\n",
"#Results\n",
"print(\" at point B Ic=8.2mA and Vce=0\")\n",
"print(\"Ic = %.1f mA \" %(Ic*10**3))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"when Ic=0\n",
"At point A Ic=0 and Vce=18\n",
"when Vce=0\n",
" at point B Ic=8.2mA and Vce=0\n",
"Ic = 8.2 mA \n"
]
}
],
"prompt_number": 2
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.3 Page No 189"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#initialisation of variables\n",
"Rb=470*10**3\n",
"Rc=2.2*10**3\n",
"Vcc=18.0\n",
"hfe=100\n",
"Vee=.7\n",
"\n",
"#Calculations\n",
"Ib=(Vcc-Vee)/Rb\n",
"Ic=hfe*Ib\n",
"Vce=Vcc-Ic*Rc\n",
"\n",
"#Results\n",
"print(\"Current voltage is %.1f V \" %(Vce))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Current voltage is 9.9 V \n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.4, Page No 189"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"hFEmin=50.0\n",
"hFEmax=200.0\n",
"Vcc=18.0\n",
"Vbe=0.7\n",
"Rb=470.0*10**3\n",
"\n",
"#Calculations\n",
"Ib=(Vcc-Vbe)/Rb\n",
"Ic=hFEmin*Ib\n",
"Vce=Vcc-Ic*Rc\n",
"Ic=hFEmax*Ib\n",
"Vce=Vcc-Ic*Rc\n",
"\n",
"#Results\n",
"print(\"Current voltage is %.1f V \" %(Vce))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Current voltage is 1.8 V \n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.5 Page No 193"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"\n",
"Rb=270*10**3\n",
"Rc=2.2*10**3\n",
"Vcc=18.0\n",
"hFE=100\n",
"Vbe=.7\n",
"\n",
"#Calculations\n",
"Ib=(Vcc-Vbe)/(Rb+Rc*(hFE+1))\n",
"Ic=hFE*Ib\n",
"Vce=Vcc-Rc*(Ic+Ib)\n",
"\n",
"#Results\n",
"print(\"Current voltage is %.1f V \" %(Vce))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Current voltage is 10.2 V \n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.7 Page No 197"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#initialisation of variables\n",
"R1=33.0*10**3\n",
"R2=12.0*10**3\n",
"Rc=1.2*10**3\n",
"Re=1*10**3\n",
"Vcc=18.0\n",
"Vbe=.7\n",
"\n",
"#Calculations\n",
"Vb=(Vcc*R2)/(R1+R2)\n",
"Ve=Vb-Vbe\n",
"Ie=(Vb-Vbe)/Re\n",
"Ic=Ie\n",
"Vc=Vcc-(Ic*Rc)\n",
"Vce=Vc-Ve\n",
"\n",
"#Results\n",
"print(\"Current voltage is %.1f V \" %(Vce))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Current voltage is 9.0 V \n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.8, Page No 199"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"Vcc=18.0\n",
"Vbe=.7\n",
"hfe=100.0\n",
"R1=33*10**3\n",
"R2=12.0*10**3\n",
"Re=1.0*10**3\n",
"\n",
"#Calculations\n",
"Vt=(Vcc*R2)/(R1+R2)\n",
"Rt=(R1*R2)/(R1+R2)\n",
"Ib=(Vt-Vbe)/(Rt+Re*(1+hfe))\n",
"Ic=hfe*Ib\n",
"Ie=Ib+Ic\n",
"Ve=Ie*Re\n",
"Vc=Vcc-(Ic*Rc)\n",
"Vce=Vc-Ve\n",
"\n",
"#Results\n",
"print(\"Current voltage is %.1f V \" %(Vce))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Current voltage is 9.7 V \n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.9 Page No 200"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math \n",
"\n",
"#initialisation of variables\n",
"hfe=50.0\n",
"Vt=4.8\n",
"Rt=8.8*10**3#from example 5.7\n",
"Re=1.0*10**3\n",
"Vbe=.7\n",
"\n",
"#Calculations\n",
"Ib=(Vt-Vbe)/(Rt+Re*(1+hfe))\n",
"Ic=hfe*Ib\n",
"Ie=Ib+Ic\n",
"Ve=Ie*Re\n",
"Vc=Vcc-(Ic*Rc)\n",
"Vce=Vc-Ve\n",
"\n",
"#Results\n",
"print(\"Current voltage is %.1f V \" %(Vce))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Current voltage is 10.4 V \n"
]
}
],
"prompt_number": 8
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.10 Page No 201"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"Vt=4.8\n",
"Rt=8.8*10**3#from example 5.8\n",
"Re=1*10**3\n",
"Vbe=.7\n",
"hfe=200.0\n",
"\n",
"#Calculations\n",
"Ib=(Vt-Vbe)/(Rt+Re*(1+hfe))\n",
"Ic=hfe*Ib\n",
"Ie=Ib+Ic\n",
"Ve=Ie*Re\n",
"Vc=Vcc-(Ic*Rc)\n",
"Vce=Vc-Ve\n",
"\n",
"#Results\n",
"print(\"Current voltage is %.1f V \" %(Vce))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Current voltage is 9.4 V \n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.11 Page No 208"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#initialisation of variables\n",
"Vce=5.0\n",
"Ic=5*10**-3\n",
"Vcc=15.0\n",
"hfe=100.0\n",
"\n",
"#Calculations\n",
"Rc=(Vcc-Vce)/Ic\n",
"Ib=Ic/hfe\n",
"Rb=(Vcc-Vbe)/Ib\n",
"\n",
"#Results\n",
"print(\"The value of Rv is %.1f kohm \" %(Rb/1000))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of Rv is 286.0 kohm \n"
]
}
],
"prompt_number": 10
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.12, Page No 209"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"\n",
"#initialisation of variables\n",
"Vce=5.0\n",
"Ic=5*10**-3\n",
"Vcc=15.0\n",
"hfe=100.0\n",
"\n",
"#Calculations\n",
"Ib=Ic/hfe\n",
"Rc=(Vcc-Vce)/(Ic+Ib)\n",
"Rb=(Vce-Vbe)/Ib\n",
"\n",
"#Results\n",
"print(\"The value of Rb is %.1f kohm \" %(Rb/1000))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of Rb is 86.0 kohm \n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.13, Page No 211"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"Vce=5.0\n",
"Ve=Vce\n",
"Ic=5.0*10**-3\n",
"hFE=100.0\n",
"Vcc=15.0\n",
"Vbe=0.7\n",
"\n",
"#Calculations\n",
"Ie=Ic\n",
"Re=Ve/Ie\n",
"Rc=(Vcc-Vce-Ve)/Ic\n",
"I2=Ic/10\n",
"Vb=Ve+Vbe\n",
"R2=Vb/I2\n",
"R1=(Vcc-Vb)/I2\n",
"\n",
"#Results\n",
"print(\"The value of Rb is %.1f kOhm \" %(R1/1000))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of Rb is 18.6 kOhm \n"
]
}
],
"prompt_number": 12
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.14, Page No 212"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"Vce=3.0\n",
"Ve=5.0\n",
"Ic=1*10**-3\n",
"Vcc=12.0\n",
"\n",
"#Calculations\n",
"Ie=Ic\n",
"R4=Ve/Ie\n",
"print(\" with Ic=1mA and R4=4.7Kohm\")\n",
"R4=4.7*10**3\n",
"Ve=Ic*R4\n",
"Vc=Ve+Vce\n",
"Vr3=Vcc-Vc\n",
"R3=Vr3/Ic\n",
"Vb=Ve+Vbe\n",
"I2=Ic/10\n",
"R2=Vb/I2\n",
"print(\" with R2=56Kohm and Vb=5.4V\")\n",
"R2=56*10**3\n",
"I2=Vb/R2\n",
"R1=(Vcc-Vb)/I2\n",
"\n",
"#Results\n",
"print(\"The value of R1 is %.1f V \" %(R1/1000))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" with Ic=1mA and R4=4.7Kohm\n",
" with R2=56Kohm and Vb=5.4V\n",
"The value of R1 is 68.4 V \n"
]
}
],
"prompt_number": 13
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.15, Page No 214"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"Vce=9.0\n",
"Ve=4.0\n",
"Ic=4*10**-3\n",
"Vcc=18.0\n",
"\n",
"#Calculations\n",
"Ie=Ic\n",
"R4=Ve/Ie\n",
"Vb=Ve+Vbe\n",
"I2=Ic/10\n",
"R2=Vb/I2\n",
"print(\" with R2=12Kohm standard\")\n",
"R2=12*10**3\n",
"I2=Vb/R2\n",
"R1=(Vce+Ve-Vb)/I2\n",
"print(\" with R1=22kohm standard\")\n",
"R1=22*10**3\n",
"Vr3=Vcc-Vce-Ve\n",
"R3=Vr3/(Ic+I2)\n",
"\n",
"#Results\n",
"print(\"The value of R3 %.2f V \" %(R3/1000))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" with R2=12Kohm standard\n",
" with R1=22kohm standard\n",
"The value of R3 1.14 V \n"
]
}
],
"prompt_number": 14
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.16, Page No 216"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"Vc=5.0\n",
"Ic=1.0*10**-3\n",
"hFE=70.0\n",
"Vbe=.7\n",
"Vee=9.0\n",
"Vcc=Vee\n",
"Re=8.2*10**3\n",
"\n",
"#Calculations\n",
"Ve=Vee-Vbe\n",
"Ie=Ic\n",
"R3=Ve/Ie\n",
"print(\" with R3=8.2kohm standard value\")\n",
"R3=8.2*10**3\n",
"Ie=Ve/R3\n",
"Vr2=Vcc-Vc\n",
"R2=Vr2/Ic\n",
"Ib=Ic/hFE\n",
"Vr1=Vbe/10\n",
"R1=Vr1/Ib\n",
"print(\" use 4.7Kohm as standard\")\n",
"#the transistor emitter terminal is .7 below ground and voltage across Re is\n",
"Ve=Vee-Vbe\n",
"Ie=Ve/Re\n",
"Vc=Vcc-(Ie*3.9*10**3)\n",
"\n",
"#Results\n",
"print(\"Current voltage is %.1f V \" %(Vc))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" with R3=8.2kohm standard value\n",
" use 4.7Kohm as standard\n",
"Current voltage is 5.1 V \n"
]
}
],
"prompt_number": 15
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.17, Page No 220"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"hFE=100.0\n",
"Rc=2.2*10**3\n",
"Rb=270.0*10**3\n",
"Re=1.0*10**3\n",
"R1=33.0*10**3\n",
"R2=12*10**3\n",
"\n",
"#Calculations\n",
"S=1+hFE\n",
"print(\"for collector to base bias\")\n",
"S=(1+hFE)/(1+(hFE*Rc)/(Rc+Rb))\n",
"print(\" for voltage divider bias\")\n",
"print(\"S=(1+hFE)/(1+hFE*Re(Re+R1||R2))\")\n",
"S=(1+hFE)/(1+(hFE*Re)/(Re+(R1*R2)/(R1+R2)))\n",
"\n",
"#Results\n",
"print(\"Voltage-divider bias is %.2f \" %(S))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"for collector to base bias\n",
" for voltage divider bias\n",
"S=(1+hFE)/(1+hFE*Re(Re+R1||R2))\n",
"Voltage-divider bias is 9.01 \n"
]
}
],
"prompt_number": 16
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.18, Page No 221"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"Icbo1=15.0*10**-9# at 25C\n",
"S=101.0\n",
"print(\"chnage in temp\")\n",
"T=105-25\n",
"print(\" n=T in 10 step\")\n",
"n=T/10.0\n",
"\n",
"#Calculations\n",
"Icbo2=Icbo1*2**n\n",
"Icbo=Icbo2-Icbo1\n",
"print(\" for base bais\")\n",
"Ic=S*Icbo\n",
"print(\" for collector to base bais\")\n",
"S=56\n",
"Ic=S*Icbo\n",
"print(\" for voltage divider bais\")\n",
"S=8.2\n",
"Ic=S*Icbo\n",
"\n",
"#Results\n",
"print(\"The value of Ic is %.1f mA \" %(Ic*10**6))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"chnage in temp\n",
" n=T in 10 step\n",
" for base bais\n",
" for collector to base bais\n",
" for voltage divider bais\n",
"The value of Ic is 31.4 mA \n"
]
}
],
"prompt_number": 17
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.19, Page No 223"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"Re=4.7*10**3\n",
"T=125-25\n",
"\n",
"#Calculations\n",
"Vbe=T*(1.8*10**-3)\n",
"Ie=Vbe/Re\n",
"\n",
"#Results\n",
"print(\"The value of Ie is %.1f V \" %(Ie*10**6))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of Ie is 38.3 V \n"
]
}
],
"prompt_number": 18
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.20, Page No 223"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"import math\n",
"#initialisation of variables\n",
"Vcc=10.0\n",
"Rc=1.0*10**3\n",
"Rb=6.8*10**3\n",
"Vs=5.0\n",
"\n",
"#Calculations\n",
"print(\" hFE calculation\")\n",
"Ic=Vcc/Rc\n",
"Ib=(Vs-Vbe)/Rb\n",
"hFE=Ic/Ib\n",
"print(\"when hFE=10\")\n",
"hFE=10\n",
"Ic=hFE*Ib\n",
"Vce=Vcc-(Ic*Rc)\n",
"\n",
"#Results\n",
"print(\"Current voltage is %.1f V \" %(Vce))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" hFE calculation\n",
"when hFE=10\n",
"Current voltage is 2.9 V \n"
]
}
],
"prompt_number": 19
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.21, Page No 227"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#initialisation of variables\n",
"Vcc=15.0\n",
"Rc=3.3*10**3\n",
"Vbe=.7\n",
"Rb=56.0*10**3\n",
"\n",
"#Calculations\n",
"Ic=Vcc/Rc\n",
"Ib=(Vcc-Vbe)/Rb\n",
"hFE=Ic/Ib\n",
"\n",
"#Results\n",
"print(\" minimum hFE is %3.2f \" %hFE)"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
" minimum hFE is 17.80 \n"
]
}
],
"prompt_number": 20
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.22, Page No 229"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#initialisation of variables\n",
"Vcc=12.0\n",
"Ic=1.5*10**-3\n",
"Vs=5.0\n",
"hFE=10.0\n",
"Vbe=.7\n",
"\n",
"#Calculations\n",
"Rc=Vcc/Ic\n",
"Ib=Ic/hFE\n",
"Rb=(Vs-Vbe)/Ib\n",
"\n",
"#Results\n",
"print(\"The value of Rb is %.1f kohm \" %(Rb/1000))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of Rb is 28.7 kohm \n"
]
}
],
"prompt_number": 21
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Example 5.23, Page No 229"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"#Calculations\n",
"Vcc=9.0\n",
"Ic=2*10**-3\n",
"hFE=10.0\n",
"Vbe=.7\n",
"\n",
"#Calculations\n",
"Rc=Vcc/Ic\n",
"Ib=Ic/hFE\n",
"Rb=(Vcc-Vbe)/Ib\n",
"\n",
"#Results\n",
"print(\"The value of Rb is %.2f kohm \" %(Rb/1000))"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"The value of Rb is 41.50 kohm \n"
]
}
],
"prompt_number": 22
}
],
"metadata": {}
}
]
}