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   "source": [
    "# Chapter 9 : Data Transmission"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Example 2 : pg 349"
   ]
  },
  {
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   "execution_count": 1,
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     "text": [
      "The efficiency is 70.0 %\n"
     ]
    }
   ],
   "source": [
    " \n",
    "# page no 349\n",
    "# prob no 9.2\n",
    "#calculate the efficiency\n",
    "#given\n",
    "Nd=7; N_start=1; N_stop=1.; N_parity=1;\n",
    "#calculations\n",
    "Nt= Nd + N_start+ N_stop + N_parity;\n",
    "efficiency=Nd/Nt *100;\n",
    "#results\n",
    "print 'The efficiency is',efficiency,'%'"
   ]
  },
  {
   "cell_type": "markdown",
   "metadata": {},
   "source": [
    "## Example 6 : pg 358"
   ]
  },
  {
   "cell_type": "code",
   "execution_count": 2,
   "metadata": {
    "collapsed": false
   },
   "outputs": [
    {
     "name": "stdout",
     "output_type": "stream",
     "text": [
      "5 hammming bits are required\n"
     ]
    }
   ],
   "source": [
    " \n",
    "# page no 358\n",
    "# prob no 9.6\n",
    "#calculate the no. of hamming bits\n",
    "#given\n",
    "m=21.;\n",
    "#calculations and results\n",
    "# The correct number of check bits is the smallest number that satisfy the equation 2**n  >= m+n+1;\n",
    "for n in range (1,10): # we choose range of 1 to 10\n",
    "    a=m+n+1;\n",
    "    b=2**n;\n",
    "    if(b>=a):\n",
    "        print n,'hammming bits are required'\n",
    "        break;\n",
    "    "
   ]
  }
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