{
"metadata": {
"name": "",
"signature": "sha256:b5194708e2447220722c4dfa1402fc797342ce58013c4fb6e50908b3fd6172f1"
},
"nbformat": 3,
"nbformat_minor": 0,
"worksheets": [
{
"cells": [
{
"cell_type": "heading",
"level": 1,
"metadata": {},
"source": [
"Chapter2-Passive Components "
]
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex1-pg23"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.1\n",
"import math\n",
"marked=220.;##in ohms\n",
"measured=207.;##in ohms\n",
"err=marked-measured;\n",
"tol=(err/marked)*100.;\n",
"print'%s %.2f %s'%(\"Tolerance = \",tol,\"\");\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Tolerance = 5.91 \n"
]
}
],
"prompt_number": 1
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex2-pg23"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.2\n",
"import math\n",
"r=39.;##in ohms\n",
"v=9.;##in volts\n",
"i=(v/r);##in Amps\n",
"print'%s %.2f %s'%(\"Current = \",i*1000,\" mA\");\n",
"tol=0.1;##i.e, 10%\n",
"r_min=r-(tol*r);\n",
"i_max=v/r_min;\n",
"r_max=r+(tol*r);\n",
"i_min=v/r_max;\n",
"print'%s %.2f %s %.2f %s '%(\"\\n Max.Current = \",i_max*1000,\" mA \" and \"\",i_min*1000,\" Min Current\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Current = 230.77 mA\n",
"\n",
" Max.Current = 256.41 209.79 Min Current \n"
]
}
],
"prompt_number": 3
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex3-pg23"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.3\n",
"import math\n",
"v=28.;##in volts\n",
"i=0.1;##in A\n",
"r=v/i;\n",
"p=v*i;\n",
"print'%s %.2f %s %.2f %s '%(\"Resistance Value = \",r,\" ohms & Power dissipated\"\" = \",p,\" W\");\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Resistance Value = 280.00 ohms & Power dissipated = 2.80 W \n"
]
}
],
"prompt_number": 4
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex4-pg24"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.4\n",
"import math\n",
"r=10*(10**2);\n",
"print'%s %.2f %s'%(\"Resistor value = \",r,\" ohm\");\n",
"print(\"\\nTolerance = 10 \");\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Resistor value = 1000.00 ohm\n",
"\n",
"Tolerance = 10 \n"
]
}
],
"prompt_number": 5
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex5-pg24"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.5\n",
"import math\n",
"r=27.*(10**3);\n",
"print'%s %.2f %s'%(\"Resistor value = \",r,\" ohm\");\n",
"print(\"\\nTolerance = 5 \");\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Resistor value = 27000.00 ohm\n",
"\n",
"Tolerance = 5 \n"
]
}
],
"prompt_number": 6
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex6-pg24"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.6\n",
"import math\n",
"r=56*(10);\n",
"print'%s %.2f %s'%(\"Resistor value = \",r,\" ohm\");\n",
"print(\"\\nTolerance = 5 \");\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Resistor value = 560.00 ohm\n",
"\n",
"Tolerance = 5 \n"
]
}
],
"prompt_number": 7
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex7-pg24"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.7\n",
"import math\n",
"r=25.*(10**0);\n",
"print'%s %.2f %s'%(\"Resistor value = \",r,\" ohm\");\n",
"print(\"\\nTolerance = 20 \");\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Resistor value = 25.00 ohm\n",
"\n",
"Tolerance = 20 \n"
]
}
],
"prompt_number": 8
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex8-pg25"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.8\n",
"import math\n",
"r=22.*(10**3);\n",
"print(\"Bands are Red, Red, Red, Red\");\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Bands are Red, Red, Red, Red\n"
]
}
],
"prompt_number": 9
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex9-pg25"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.9\n",
"import math\n",
"print(\"Resistance = 4.7 ohm with 10%% tolerance\");\n",
"\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Resistance = 4.7 ohm with 10%% tolerance\n"
]
}
],
"prompt_number": 10
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex10-pg25"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.10\n",
"import math\n",
"print(\"Resistance = 330 ohms with 2%% tolerance\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Resistance = 330 ohms with 2%% tolerance\n"
]
}
],
"prompt_number": 11
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex11-pg26"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.11\n",
"import math\n",
"print(\"Resistance = 0.22 ohm with 20%% tolerance\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Resistance = 0.22 ohm with 20%% tolerance\n"
]
}
],
"prompt_number": 12
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex12-pg26"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.12\n",
"import math\n",
"r1=22.;##in ohms\n",
"r2=47.;##in ohms\n",
"r3=33.;##in ohms\n",
"r_ser=r1+r2+r3;\n",
"print'%s %.2f %s'%(\"Effective resistance in series = \",r_ser,\" ohms\");\n",
"r_parel=((1./r1)+(1./r2)+(1./r3))**-1;\n",
"print'%s %.2f %s'%(\"\\n Effective resistance in parallel = \",r_parel,\" ohms\");\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Effective resistance in series = 102.00 ohms\n",
"\n",
" Effective resistance in parallel = 10.31 ohms\n"
]
}
],
"prompt_number": 13
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex13-pg27"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.13\n",
"import math\n",
"r1=4.7;##in ohms\n",
"r2=47.;##in ohms\n",
"r3=12.;##in ohms\n",
"r4=27.;##in ohms\n",
"r5=r3+r4;\n",
"r_parel=((1./r5)+(1./r2))**-1;\n",
"r_eff=r_parel+r1;\n",
"print'%s %.2f %s'%(\"Effective resistance = \",r_eff,\" ohms\");\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Effective resistance = 26.01 ohms\n"
]
}
],
"prompt_number": 14
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex14-pg27"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.14\n",
"import math\n",
"print(\"Two 100 ohm resistor of 1 W\");\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Two 100 ohm resistor of 1 W\n"
]
}
],
"prompt_number": 15
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex15-pg28"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.15\n",
"import math\n",
"temp_coeff=0.001;##in per degree centigrade\n",
"r_o=1500.;##in ohm\n",
"t=80.;##temperature diff.\n",
"r_t=r_o*(1.+(temp_coeff)*t)\n",
"print'%s %.2f %s'%(\"Resistance at \",r_t,\" degree = ohms\");\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Resistance at 1620.00 degree = ohms\n"
]
}
],
"prompt_number": 16
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex16-pg28"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.16\n",
"import math\n",
"temp_coeff=0.0005;##in per degree centigrade\n",
"r_t1=680.;##in ohm\n",
"t1=20.;##temperature diff.\n",
"t2=90.;\n",
"r_o=r_t1/(1.+(temp_coeff)*t1);\n",
"r_t2=r_o*(1.+(temp_coeff)*t2);\n",
"print'%s %.2f %s %.2f %s '%(\"Resistance at \",t2,\" degree = \",r_t2,\" ohms\");\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Resistance at 90.00 degree = 703.56 ohms \n"
]
}
],
"prompt_number": 17
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex17-pg29"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.17\n",
"import math\n",
"r_o=40.;##resis at 0 degree\n",
"r_t=44.;##at 100 degree\n",
"t=100.;##temperature diff.\n",
"temp_coeff=(1./t)*((r_t/r_o)-1.);\n",
"print'%s %.2e %s'%(\"Temperature Coefficient = \",temp_coeff,\" per degree centigrade\");\n"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Temperature Coefficient = 1.00e-03 per degree centigrade\n"
]
}
],
"prompt_number": 18
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex18-pg33"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.18\n",
"import math\n",
"V_1=50.;\n",
"V_2=10.;\n",
"dV=V_1-V_2;##in volts\n",
"dt=0.1;##in seconds\n",
"C=22.*10**-6;\n",
"i=C*(dV/dt)*1000.;##in mA\n",
"print'%s %.2f %s'%(\"Current flow = \",i,\" milliAmps\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Current flow = 8.80 milliAmps\n"
]
}
],
"prompt_number": 19
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex19-pg33"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.19\n",
"import math\n",
"C=10.*10**-6;\n",
"V=250.;##in volts\n",
"Q=V*C*1000.;##in millicoulomb\n",
"print'%s %.2f %s'%(\"Charged stored =\",Q,\" mC\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Charged stored = 2.50 mC\n"
]
}
],
"prompt_number": 20
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex20-pg33"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.20\n",
"import math\n",
"C=47.*10**-6;##in farads\n",
"W=4.;##energy in joules\n",
"V=math.sqrt(W/(0.5*C));\n",
"print'%s %.2f %s'%(\"Voltage tht be applied = \",V,\" volts\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Voltage tht be applied = 412.57 volts\n"
]
}
],
"prompt_number": 21
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex21-pg34"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.21\n",
"import math\n",
"E_o=8.85*10**-12;\n",
"E_r=5.4;\n",
"C=1*10**-9;\n",
"d=0.1*10**-3;\n",
"A=(C*d)/(E_o*E_r)*10**4;\n",
"print'%s %.2f %s'%(\"Required plate area = \",A,\" sq. cm\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Required plate area = 20.92 sq. cm\n"
]
}
],
"prompt_number": 22
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex22-pg34"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.22\n",
"import math\n",
"E_o=8.85*10**-12;\n",
"E_r=4.5;\n",
"n=6.;##no. of plates\n",
"d=0.2*10**-3;##in meter\n",
"A=20.*10**-4;##in sq.meter\n",
"C=((E_o*E_r*(n-1.)*A)/d)*10**11;\n",
"print'%s %.2f %s'%(\"Capacitance = \",C,\" pF\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Capacitance = 199.12 pF\n"
]
}
],
"prompt_number": 23
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex23-pg36"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.23\n",
"import math\n",
"print(\"Capacitance = 10000 pF of 10%%\"); "
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Capacitance = 10000 pF of 10%%\n"
]
}
],
"prompt_number": 24
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex24-pg36"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.24\n",
"import math\n",
"print(\"Capacitance = 150 pF of 2%% tolerance at 100 V\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Capacitance = 150 pF of 2%% tolerance at 100 V\n"
]
}
],
"prompt_number": 25
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex25-pg37"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.25\n",
"import math\n",
"C1=2.;##in nF\n",
"C2=4.;##in nF\n",
"C3=2.;\n",
"C4=4.;\n",
"C_a=C1+C2;\n",
"C_b=C_a*C3/(C_a+C3);\n",
"C_eff=C4+C_b;\n",
"print'%s %.2f %s'%(\"Capacitance = \",C_eff,\" nF\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Capacitance = 5.50 nF\n"
]
}
],
"prompt_number": 26
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex26-pg37"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.26\n",
"import math\n",
"C=100.;##in uF\n",
"C_eff=C*C/(C+C);\n",
"print'%s %.2f %s'%(\"Two capacitors of uF be in parallel used to make \",C_eff,\" uF capacitance\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Two capacitors of uF be in parallel used to make 50.00 uF capacitance\n"
]
}
],
"prompt_number": 27
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex27-pg40"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.27\n",
"import math\n",
"L=600.*10**-3;##in H\n",
"I1=6.;##in A\n",
"I2=2.;##in A\n",
"dI=I1-I2;\n",
"dt=250.*10**-3;##in sec.\n",
"E=-L*(dI/dt);\n",
"print'%s %.2f %s'%(\"Induced voltage = \",E,\" volts\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Induced voltage = -9.60 volts\n"
]
}
],
"prompt_number": 28
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex28-pg40"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.28\n",
"import math\n",
"E=2.5;##energy in joules\n",
"L=20.*10**-3;##in henry\n",
"I=math.sqrt(E/(0.5*L));\n",
"print'%s %.2f %s'%(\"Current = \",I,\" A\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Current = 15.81 A\n"
]
}
],
"prompt_number": 29
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex29-pg40"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.29\n",
"import math\n",
"u_o=12.57*10**-7;\n",
"u_r=500.;\n",
"A=15.*10**-4;##area of cross-section in sq. meters\n",
"l=20.*10**-2;##length\n",
"L=100.*10**-3;##in henry\n",
"n=math.sqrt((L*l)/(u_r*u_o*A));\n",
"print'%s %.2f %s'%(\"Inductor requires \",n,\" turns of wire\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Inductor requires 145.65 turns of wire\n"
]
}
],
"prompt_number": 30
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex30-pg42"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.30\n",
"import math\n",
"##L=(L1*L2)/(L1+L2)\n",
"L_eq=5.;##in millihenry\n",
"print'%s %.2f %s'%(\"Inductor of 10 mH wired in parallel would provide \",L_eq,\" mH\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Inductor of 10 mH wired in parallel would provide 5.00 mH\n"
]
}
],
"prompt_number": 31
},
{
"cell_type": "heading",
"level": 2,
"metadata": {},
"source": [
"Ex31-pg42"
]
},
{
"cell_type": "code",
"collapsed": false,
"input": [
"##Ex:2.31\n",
"import math\n",
"L1=60.;##in mH\n",
"L2=60.;##in mH\n",
"L_a=L1+L2;\n",
"L3=120.;##in mH\n",
"L_b=L_a*L3/(L_a+L3);\n",
"L4=50.;##in mH\n",
"L_eq=L4+L_b;\n",
"print'%s %.2f %s'%(\"Equivalent Inductance = \",L_eq,\" mH\");"
],
"language": "python",
"metadata": {},
"outputs": [
{
"output_type": "stream",
"stream": "stdout",
"text": [
"Equivalent Inductance = 110.00 mH\n"
]
}
],
"prompt_number": 32
}
],
"metadata": {}
}
]
}