{ "metadata": { "name": "" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 09 : Insulated Cables" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 9.1, Page No 196" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "V=85.0 # working voltage (kV)\n", "gmax=65.0 # dielectric strength of insulating material (kV/cm)\n", "\n", "#Calculations\n", "r=V/gmax\n", "d=2*r\n", "D=2.6*math.e\n", "\n", "#Results\n", "print(\"Diameter of the sheath =%.2f cm\\n\" %D)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Diameter of the sheath =7.07 cm\n", "\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 9.2, Page No 200" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "e1=4.0\n", "e2=4.0\n", "e3=2.5\n", "g1max=50.0\n", "g2max=40.0\n", "g3max=30.0\n", "r=0.5\t\t# radius (cm)\n", "\n", "#Calculations\n", "r1=r*e1*g1max/(e2*g2max)\n", "r2=r1*e2*g2max/(e3*g3max)\n", "V=66.0\n", "lnc=(V-((r*g1max*math.log(r1/r))+(r1*g2max*math.log(r2/r1))))\n", "m=lnc/(r2*g3max)\n", "R=r2*(math.e**m)\n", "D=2*R\n", "\n", "#Results\n", "print(\"minimum internal diameter of the lead sheath,D=%.2f cms \" %D)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "minimum internal diameter of the lead sheath,D=7.52 cms \n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 9.3, Page No 202" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "r=0.5 \t#radius of conductor(cm)\n", "g1max=34.0\n", "er=5.0\n", "r1=1.0\n", "R=7.0/2 #external dia(cm)\n", "\n", "#Calculations\n", "g2max=(r*g1max)/(er*r1)\n", "V=((r*g1max*math.log(r1/r))+(r1*g2max*math.log(R/r1)))\n", "V=V/(math.sqrt(2.0))\n", "\n", "#Results\n", "print(\"Maximum safe working volltage ,V =%.2f kV r.m.s\\n\" %V)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Maximum safe working volltage ,V =11.34 kV r.m.s\n", "\n" ] } ], "prompt_number": 3 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 9.4 Page No 202" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "r=0.9\n", "r1=1.25\n", "\n", "#Calculations\n", "r2=r1+.35\n", "r3=r2+.35 # radius of outermost layer\n", "Vd=20.0 # voltage difference (kV)\n", "g1max=Vd/(r*math.log(r1/r))\n", "g2max=Vd/(r1*math.log(r2/r1))\n", "g3max=(66-40)/(r2*math.log(r3/r2))\n", "\n", "#Results\n", "print(\"g1max =%.1f kV/cm\" %g1max)\n", "print(\"g2max =%.2f kV/cm\" %g2max)\n", "print(\"g3max =%.0f kV/cm\" %g3max)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "g1max =67.6 kV/cm\n", "g2max =64.81 kV/cm\n", "g3max =82 kV/cm\n" ] } ], "prompt_number": 4 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 9.5, Page No 206" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "V=20.0 #voltage (kV)\n", "w=314.0\n", "\n", "#Calculations\n", "C=2*3.04*10**-6\t\t\t#capacitance per phase(micro-farad)\n", "KVA=V*V*w*C*1000.0\n", "\n", "#Results\n", "print(\"3-phase kVA required =%.0f kVA\" %KVA) \t#Answer don't match due to difference in rounding off of digits" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "3-phase kVA required =764 kVA\n" ] } ], "prompt_number": 5 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 9.6, Page No 206" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "C1=0.208\n", "C2=0.096\n", "Cx=3.0*C1\n", "w=314.0\n", "V=10.0\n", "\n", "#Calculations\n", "Cy=(C1+ 2*C2)\n", "Co=((1.5*Cy)-(Cx/6))\n", "C=Co/2.0\n", "\n", "#Results\n", "print(\"(i)Capacitance between any two conductors=%.3f micro-Farad/km\" %C)\n", "c=((2*C2 + ((2/3)*C1)))\n", "print(\"(ii)Capacitance between any two bunched conductors and the third conductor=%.2f micro-Farad/km\" %c)\n", "I=V*w*Co*1000*(10**-6)/math.sqrt(3)\n", "print(\"(iii)the charging current per phase per km =%.3f A\" %I)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "(i)Capacitance between any two conductors=0.248 micro-Farad/km\n", "(ii)Capacitance between any two bunched conductors and the third conductor=0.19 micro-Farad/km\n", "(iii)the charging current per phase per km =0.899 A\n" ] } ], "prompt_number": 6 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 9.7 Page No 213" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "rm=(2.28/2)-(.152/2)# mean radius of sheath (cm)\n", "d=5.08\n", "a=d/rm\n", "w=314.0\n", "\n", "#Calculations\n", "Xm=2*(10**-7)*math.log(a) # mutual inductance (H/m)\n", "Xm2=2000*Xm\n", "V=w*Xm2*400\n", "\n", "#Results\n", "print(\"Voltage induced =%.2f volts \\n\" %V)#Answer don't match exactly due to difference in rounding off of digits i between calculations" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Voltage induced =78.54 volts \n", "\n" ] } ], "prompt_number": 7 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 9.8, Page No 214" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "R=2*0.1625\n", "Rs=2*2.14\n", "M=314.0\n", "\n", "#Calculations\n", "w=6.268*10**-4\n", "r=Rs*M*M*w*w/(R*((Rs**2)+(M*M*w*w)))\n", "\n", "#Results\n", "print(\"ratio=%.4f \" %r)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "ratio=0.0278 \n" ] } ], "prompt_number": 8 } ], "metadata": {} } ] }