{ "metadata": { "name": "" }, "nbformat": 3, "nbformat_minor": 0, "worksheets": [ { "cells": [ { "cell_type": "heading", "level": 1, "metadata": {}, "source": [ "Chapter 05 : High Voltage DC Transmission" ] }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 5.1, Page No 107" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "Vo=3*math.sqrt(2)*110/math.pi\n", "\n", "#Calculations \n", "Vd=Vo*(math.cos(math.radians(0))+math.cos(math.radians(15)))/2.0 \n", "Vd1=Vo*(math.cos(math.radians(30)) + math.cos(math.radians(45)))/2.0 \n", "Vd2=Vo*(math.cos(math.radians(45)) + math.cos(math.radians(60)))/2.0 \n", "\n", "#Results\n", "print(\"(a)For a=0, Vd=%.2f kV\" %Vd) \n", "print(\"(b)For a=30,Vd=%.2f kV\" %Vd1) \n", "print(\"(c)For a=45,Vd=%.2f kV\" %Vd2) " ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "(a)For a=0, Vd=146.02 kV\n", "(b)For a=30,Vd=116.85 kV\n", "(c)For a=45,Vd=89.66 kV\n" ] } ], "prompt_number": 1 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 5.2, Page No 107" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "\n", "#Calculations\n", "VL=(100.0*2*math.pi)/(3*math.sqrt(2.0)*(math.cos(math.radians(30)) + math.cos(math.radians(45)))) \n", "print(\"VL=%.2f kV\" %VL) #Answers don't match due to difference in rounding off of digits\n", "Tr=VL/110.0\n", "\n", "#Results \n", "print(\"tap ratio=%.2f \" %Tr) " ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "VL=94.14 kV\n", "tap ratio=0.86 \n" ] } ], "prompt_number": 2 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 5.3, Page No 109" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variablesVd=100000\n", "Id=800.0 # current\n", "\n", "#Calculations\n", "X=((3*math.sqrt(2.0)*94.115*0.866*1000.0/math.pi)-Vd)*math.pi/(3.0*Id)\n", "\n", "#Results\n", "print(\"effective reactance per phase , X=%.2f ohm\\n\" %X)\t#Answer don't match due to difference in rounding off of digits" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "effective reactance per phase , X=143.89 ohm\n", "\n" ] } ], "prompt_number": 3 }, { "cell_type": "heading", "level": 2, "metadata": {}, "source": [ "Example 5.4 Page No 112" ] }, { "cell_type": "code", "collapsed": false, "input": [ "import math\n", "#initialisation of variables\n", "a=15.0\n", "d0=10.0\n", "y=15.0\n", "X=15.0\n", "R=10.0\n", "\n", "#Calculations\n", "Id=(3*math.sqrt(2)*120*(math.cos(math.radians(a))-math.cos(math.radians(d0+y)))*1000.0)/((R+(3.0*2*X)/math.pi)*math.pi)\n", "\n", "#Results\n", "print(\"Id=%.2f amp.\" %Id)" ], "language": "python", "metadata": {}, "outputs": [ { "output_type": "stream", "stream": "stdout", "text": [ "Id=249.99 amp.\n" ] } ], "prompt_number": 4 } ], "metadata": {} } ] }