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   "cells": [
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "<h1>Chapter 8: Electromagnetism</h1>"
     ]
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "<h3>Example 2, page no. 93</h3>"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#calculate the force acting on the conductor.\n",
      "#Determine also the value of the force\n",
      "from __future__ import division\n",
      "import math\n",
      "#initializing  the  variables:\n",
      "B  =  0.9;#  in  tesla\n",
      "I  =  20;#  in  Amperes\n",
      "l  =  0.30;#  in  m\n",
      "alpha  =  30;#  in  degree\n",
      "u0  =  4*math.pi*1E-7;\n",
      "\n",
      "#calculation:\n",
      "F1  =  B*I*l\n",
      "F2  =  B*I*l*math.sin(alpha*math.pi/180)\n",
      "\n",
      "#Results\n",
      "print  \"\\n\\nResult\\n\\n\"\n",
      "print  \"\\n  (a)Force  when  the  conductor  is  at  right  angles  to  the  field  =  \",F1,\"  N\\n\"\n",
      "print  \"\\n  (b)Force  when  the  conductor  is  at  30\u00b0  angle  to  the  field  =  \",F2,\"  N\\n\""
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "\n",
        "\n",
        "Result\n",
        "\n",
        "\n",
        "\n",
        "  (a)Force  when  the  conductor  is  at  right  angles  to  the  field  =   5.4   N\n",
        "\n",
        "\n",
        "  (b)Force  when  the  conductor  is  at  30\u00c2\u00b0  angle  to  the  field  =   2.7   N"
       ]
      }
     ],
     "prompt_number": 1
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "<h3>Example 3, page no. 94</h3>"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#Determine the current required?\n",
      "#what is the direction of the force?\n",
      "from __future__ import division\n",
      "import math\n",
      "#initializing  the  variables:\n",
      "F  =  1.92;#  in  newton\n",
      "B  =  1.2;#  in  tesla\n",
      "l  =  0.40;#  in  m\n",
      "u0  =  4*math.pi*1E-7;\n",
      "\n",
      "#calculation:\n",
      "I  =  F/(B*l)\n",
      "\n",
      "#Results\n",
      "print  \"\\n\\nResult\\n\\n\"\n",
      "print  \"\\n  (a)Current  I  =  \",I,\"  Amperes(A)\\n\""
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "\n",
        "\n",
        "Result\n",
        "\n",
        "\n",
        "\n",
        "  (a)Current  I  =   4.0   Amperes(A)"
       ]
      }
     ],
     "prompt_number": 2
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "<h3>Example 4, page no. 95</h3>"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#calculate the magnitude of the force exerted on the conductor.\n",
      "from __future__ import division\n",
      "import math\n",
      "#initializing  the  variables:\n",
      "r  =  0.06;#  in  m\n",
      "I  =  10;#  in  Amperes\n",
      "l  =  0.35;#  in  m\n",
      "Phi  =  0.5E-3;#  in  Wb\n",
      "u0  =  4*math.pi*1E-7;\n",
      "\n",
      "#calculation:\n",
      "A  =  math.pi*r*r\n",
      "B  =  Phi/A\n",
      "F  =  B*I*l\n",
      "\n",
      "#Results\n",
      "print  \"\\n\\nResult\\n\\n\"\n",
      "print  \"\\n  (a)Force  F  =  \",round(F,2),\"  N\\n\""
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "\n",
        "\n",
        "Result\n",
        "\n",
        "\n",
        "\n",
        "  (a)Force  F  =   0.15   N"
       ]
      }
     ],
     "prompt_number": 3
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "<h3>Example 6, page no. 95</h3>"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#determine the force on each coil side (a) for a single-turn coil,\n",
      "#(b) for a coil wound with 300 turns.\n",
      "from __future__ import division\n",
      "import math\n",
      "#initializing  the  variables:\n",
      "N1  =  1;#  for  a  single-turn  coil\n",
      "N2  =  300;#  no.  of  turns\n",
      "b  =  0.024;#  in  m\n",
      "B  =  0.8;#  in  Tesla\n",
      "I  =  0.05;#  in  Amperes\n",
      "l  =  0.030;#  in  m\n",
      "u0  =  4*math.pi*1E-7;\n",
      "\n",
      "#calculation:\n",
      "#For  a  single-turn  coil,\n",
      "F1  =  N1*B*I*l\n",
      "#for  a  coil  wound  with  300  turns.\n",
      "F2  =  N2*B*I*l\n",
      "\n",
      "#Results\n",
      "print  \"\\n\\nResult\\n\\n\"\n",
      "print  \"\\n  (a)For  a  single-turn  coil,  force  on  each  coil  side  =  \",F1,\"  N\\n\"\n",
      "print  \"\\n  (b)For  a  300-turn  coil,  force  on  each  coil  side  =  \",F2,\"  N\\n\""
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "\n",
        "\n",
        "Result\n",
        "\n",
        "\n",
        "\n",
        "  (a)For  a  single-turn  coil,  force  on  each  coil  side  =   0.0012   N\n",
        "\n",
        "\n",
        "  (b)For  a  300-turn  coil,  force  on  each  coil  side  =   0.36   N"
       ]
      }
     ],
     "prompt_number": 4
    },
    {
     "cell_type": "markdown",
     "metadata": {},
     "source": [
      "<h3>Example 7, page no. 98</h3>"
     ]
    },
    {
     "cell_type": "code",
     "collapsed": false,
     "input": [
      "#Determine the force exerted on the electron in the field.\n",
      "from __future__ import division\n",
      "import math\n",
      "#initializing  the  variables:\n",
      "Q  =  1.6E-19;#  in  Coulomb\n",
      "v  =  3E7;#  in  m/s\n",
      "B  =  18.5E-6;#  in  Tesla\n",
      "u0  =  4*math.pi*1E-7;\n",
      "\n",
      "#calculation:\n",
      "F  =  Q*v*B\n",
      "\n",
      "#Results\n",
      "print  \"\\n\\nResult\\n\\n\"\n",
      "print  \"\\n  Force  exerted  on  the  electron  in  the  field.  =  \",(F/1E-17),\"E-17  N\\n\""
     ],
     "language": "python",
     "metadata": {},
     "outputs": [
      {
       "output_type": "stream",
       "stream": "stdout",
       "text": [
        "\n",
        "\n",
        "Result\n",
        "\n",
        "\n",
        "\n",
        "  Force  exerted  on  the  electron  in  the  field.  =   8.88 E-17  N"
       ]
      }
     ],
     "prompt_number": 5
    }
   ],
   "metadata": {}
  }
 ]
}