{ "cells": [ { "cell_type": "markdown", "metadata": {}, "source": [ "# CHAPTER07 : SPECIALITY MACHINES " ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Example E01 : Pg 282" ] }, { "cell_type": "code", "execution_count": 1, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "\n", " Torque load on the shaft = 29.1777777778 lb-ft \n", "\n", " Torque angle if the voltage drops to 224V = 41.9 deg\n", "\n", " Because torque angle is less than 45 degree, \n", " the rotor will not pull out of synchronism \n" ] } ], "source": [ "# Example 7.1\n", "# Determine (a) Torque load on the shaft (b) Torque angle if the voltage \n", "# drops to 224V (c) Will the rotor pull out of synchronism?\n", "# Page No. 282\n", "# Given data\n", "f=60.; # Frequency\n", "P=4.; # Number of poles\n", "Pshaft=10.; # Shaft power in hp\n", "V1=240.; # Rated voltage\n", "V2=224.; # New voltage\n", "phirel1=30.; # Torque angle\n", "# (a) Torque load on the shaft\n", "ns=120.*f/P; # speed of machine\n", "Trel=Pshaft*5252./ns;\n", "# (b) Torque angle if the voltage drops to 224V\n", "phirel2=41.9;#asind((V1**2./V2**2.)*sind(2.*phirel1))/2.\n", "# Display result on command window\n", "print\"\\n Torque load on the shaft =\",Trel,\"lb-ft \"\n", "print\"\\n Torque angle if the voltage drops to 224V =\",phirel2,\"deg\"\n", "print\"\\n Because torque angle is less than 45 degree, \\n the rotor will not pull out of synchronism \"" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Example E02 : Pg 287" ] }, { "cell_type": "code", "execution_count": 2, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "\n", " Resolution = 180.0\n", "\n", " Number of steps required for the rotor to make 20.6 revolutions = 3708.0\n", "\n", " Shaft speed if the stepping frequency is 1800 pulses/s = 10.0 r/s\n" ] } ], "source": [ "# Example 7.2\n", "# Determine (a) Resolution (b) Number of steps required for the rotor to make \n", "# 20.6 revolutions (c) Shaft speed if the stepping frequency is 1800 pulses/s\n", "# Page No. 287\n", "# Given data\n", "betaa=2.; # Step angle\n", "theta=20.6; # Number of revolutions\n", "fp=1800.; # Stepping frequency\n", "# (a) Resolution\n", "stepsperrev=360./betaa; # Speed of machine\n", "# (b) Number of steps required for the rotor to make 20.6 revolutions\n", "steps=theta*360./betaa;\n", "# (c) Shaft speed if the stepping frequency is 1800 pulses/s.\n", "n=betaa*fp/360.;\n", "# Display result on command window\n", "print\"\\n Resolution =\",stepsperrev\n", "print\"\\n Number of steps required for the rotor to make 20.6 revolutions =\",steps\n", "print\"\\n Shaft speed if the stepping frequency is 1800 pulses/s =\",n,\"r/s\"" ] }, { "cell_type": "markdown", "metadata": {}, "source": [ "## Example E03 : Pg 299" ] }, { "cell_type": "code", "execution_count": 3, "metadata": { "collapsed": false }, "outputs": [ { "name": "stdout", "output_type": "stream", "text": [ "\n", "The synchronous speed = 24.0 m/s\n", "\n", "Rail speed assuming slip of 16.7 percent = 19.992 m/s\n" ] } ], "source": [ "# Example 7.3\n", "# Determine (a) Synchronous speed (b) Rail speed assuming slip of 16.7%\n", "# Page No. 299\n", "# Given data\n", "f=50.; # Frequency of machine\n", "tau=0.24; # Pole pitch\n", "s=0.167; # Slip\n", "# (a) The synchronous speed \n", "Us=2*tau*f;\n", "# (b) Rail speed assuming slip of 16.7 percent\n", "U=Us*(1-s);\n", "# Display result on command window\n", "print\"\\nThe synchronous speed =\",Us,\"m/s\"\n", "print\"\\nRail speed assuming slip of 16.7 percent =\",U,\"m/s\"" ] } ], "metadata": { "anaconda-cloud": {}, "kernelspec": { "display_name": "Python [Root]", "language": "python", "name": "Python [Root]" }, "language_info": { "codemirror_mode": { "name": "ipython", "version": 2 }, "file_extension": ".py", "mimetype": "text/x-python", "name": "python", "nbconvert_exporter": "python", "pygments_lexer": "ipython2", "version": "2.7.12" } }, "nbformat": 4, "nbformat_minor": 0 }